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For the following given information, find the critical region, compute \(\mathrm{t}\) and decide whether the results are significant or not significant. Sample mean \(\underline{\mathrm{X}}=26\) Sample slandered deviation \(\mathrm{s}=6\) Sample size \(\mathrm{n}=25\) Null hypothesis \(\mu=30\) Alternate hypothesis \(\mu<30\) Significance level \(\alpha=.01\).

Short Answer

Expert verified
The t-test statistic is calculated as \(t = -3.33\), which is more extreme than the critical value \(t_{critical} = -2.50\) at the 0.01 significance level for a one-tailed test. Therefore, the results are significant, and we reject the null hypothesis in favor of the alternate hypothesis.

Step by step solution

01

Calculate the t-test statistic

We compute the t-test statistic using the provided sample mean, the null hypothesis mean, sample standard deviation, and sample size. The formula for the t-test statistic is: \[ t = \frac{(\bar{X} - \mu)}{(s/\sqrt{n})} \] Using the given values, we have: \[\bar{X} = 26, s = 6, n = 25, \mu = 30\] Plugging these values into the formula: \[ t = \frac{(26-30)}{(6/\sqrt{25})} \]
02

Calculate the t-test statistic value

Now we can compute the t value: \[ t = \frac{(-4)}{(6/\sqrt{25})} = \frac{-4}{1.2} = -3.33 \]
03

Determine the critical value from the t-distribution table

We now need to determine the critical value for the given significance level, \(\alpha=.01\). In this problem, we are using a one-tailed t-test, given that our alternate hypothesis is \(\mu < 30\). Since we have a sample size of 25, the degrees of freedom (df) are given by: \[ df = n - 1 = 25 - 1 = 24 \] Referencing a t-distribution table for the significance level \(\alpha=0.01\) and degrees of freedom \(df=24\), we find the critical value to be approximately -2.50.
04

Compare t-test statistic to critical value

We now compare our calculated t-test statistic value with the critical value: - Our calculated t-test statistic: \(t = -3.33\) - Critical value at the .01 significance level (for one-tailed test) : \(t_{critical} = -2.50\) Since our t-test statistic is more extreme (less) than the critical value (-3.33 < -2.50), we reject the null hypothesis.
05

Decide if the results are significant or not significant

Since we rejected the null hypothesis, we conclude that the results are significant at the 0.01 significance level. This indicates that the sample mean is significantly less than the null hypothesis population mean 30, supporting the alternate hypothesis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

critical region
The concept of the critical region is pivotal in hypothesis testing. It refers to the range of values that the test statistic must fall into for us to reject the null hypothesis. To find this region, one must first decide the significance level of the test, represented as \(\alpha\), and then determine the corresponding critical value using a statistical distribution table, like the t-distribution table in our case.

For our exercise, since we are conducting a one-tailed t-test with \(\alpha=.01\), we search the t-distribution table for the value where the cumulative probability in the tail is equal to 0.01. This value marks the boundary of our critical region. If the computed test statistic falls below this critical value, as it did at -3.33, we are in the critical region and thus reject the null hypothesis. This critical region approach enables a systematic and objective way to make decisions about statistical hypotheses.
hypothesis testing
At its core, hypothesis testing is a method used to determine whether there is enough evidence in a sample of data to infer that a certain condition holds for the entire population. The process begins by stating two hypotheses: the null hypothesis \(H_0\), which is a statement of no effect or no difference, and the alternative hypothesis \(H_a\), which is what we suspect might be true instead.

In the problem at hand, the null hypothesis \(\mu=30\) suggests that there is no significant difference between the sample mean and the population mean. The alternative hypothesis \(\mu<30\) indicates that the sample mean is less than the population mean. Following the calculation of the t-test statistic and comparing it against the critical value, we use this evidence to either reject or fail to reject the null hypothesis. The overall aim is to reach a conclusion that either supports the alternative hypothesis (rejecting \(H_0\)) or does not find enough evidence against the null hypothesis (failing to reject \(H_0\)).
one-tailed t-test
A one-tailed t-test is a statistical test used when the research hypothesis specifies the direction of the effect. This means we're only looking for evidence that the test statistic falls into one tail of the distribution, either high or low, but not both. This contrasts with a two-tailed t-test where the effect could be in either direction.

In our exercise, the alternative hypothesis calls for a one-tailed test because it specifically states that \(\mu<30\). We're interested in finding out if the mean is lower than the hypothesized value. Had the alternative hypothesis been that \(\mueq30\), a two-tailed test would have been appropriate. The one-tailed t-test is more powerful than a two-tailed test for detecting an effect in one direction because all of the testing power is concentrated in that one tail, making it a suitable choice for our problem.
significance level
The significance level, denoted as \(\alpha\), is a threshold chosen by the researcher to decide whether to reject the null hypothesis. It represents the probability of making a Type I error, which is rejecting a true null hypothesis. Common choices for \(\alpha\) are 0.05, 0.01, and 0.001, corresponding to confidence levels of 95%, 99%, and 99.9%, respectively.

In our example, the significance level is set at 0.01, indicating that we have a 99% confidence level in our test. We are willing to accept a 1% risk of wrongly rejecting a true null hypothesis. If the p-value of our test statistic is less than 0.01, we reject the null hypothesis. By setting a low \(\alpha\), we make our hypothesis test more stringent, requiring stronger evidence to reject \(H_0\). Thus, the selection of \(\alpha\) impacts the conclusion of the hypothesis test significantly.

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