/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 632 Two independent reports on the v... [FREE SOLUTION] | 91Ó°ÊÓ

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Two independent reports on the value of a tincture for treating a disease in camels were available. The first report made on a small pilot series showed the new tincture to be probably superior to the old treatment with a Yates' \(\mathrm{X}^{2}\) of \(3.84, \mathrm{df}=1, \alpha=.05\). The second report with a larger trial gave a "not significant" result with a Yates \(\mathrm{X}^{2}=2.71, \mathrm{df}=1\), \(\alpha=.10 .\) Can the results of the 2 reports be combined to form a new conclusion?

Short Answer

Expert verified
When combining the results of the two reports, we find a combined \(X^2 = 6.55\), which is greater than the critical value of \(2.71\) at the higher significance level, α = 0.10. Thus, considering the findings from both reports, the new tincture is probably superior to the old treatment, assuming varying significance levels do not impact the conclusions.

Step by step solution

01

Analyze each report individually

In the first report, we have \(X^2 = 3.84\), \(df = 1\), and \(\alpha = 0.05\). Since the \(X^2\) is equal to the critical value for this test at the given significance level (α), the tincture is considered probably superior to the old treatment. In the second report, we have \(X^2 = 2.71\), \(df = 1\), and \(\alpha = 0.10\). This result is "not significant," meaning there's not enough evidence to conclude that the new tincture is better than the old treatment at the given α level.
02

Determine if it is appropriate to combine results

Since both reports have the same degrees of freedom, df = 1, we can consider combining the results. However, we must consider the fact that, in the second report, the level of significance is higher than in the first report, which means that the conclusions might not be directly comparable. Nonetheless, we can proceed by combining the results under the assumption that the different significance levels do not affect the conclusions.
03

Combine results and draw a new conclusion

To combine the \(X^2\) test results, we can sum the individual \(X^2\) values and compare the combined result to the critical value of the test statistic for that combined chi-square value: Combined \(X^2 = 3.84 + 2.71 = 6.55\) Next, we need to find the critical value for a combined χ^2 test statistic with our given degrees of freedom and the higher significance level, α = 0.10. We find that, for a χ^2 test, the critical value is \(χ^2 = 2.71\). Since the combined \(X^2\) value (6.55) is greater than the critical value (2.71), we can conclude that the new tincture is probably superior to the old treatment when considering the results from both reports (assuming different significance levels do not affect the conclusions).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Yates' correction
Understanding Yates' correction is crucial when analyzing categorical data using the chi-square test, especially when dealing with small sample sizes. Yates' correction, also known as the continuity correction, is applied to the chi-square test to adjust for the approximation that is made by using a continuous distribution to estimate a discrete distribution. This adjustment is typically used when the sample size is small, and the degrees of freedom are 1, as it helps to prevent overestimation of the statistical significance.

In our exercise involving two reports on camel treatment efficacy, Yates' correction was used to adjust the chi-square test results. The correction can affect the outcome by slightly increasing the p-value, making it less likely to reject the null hypothesis. It's a subtlety that must be applied carefully, often recommended when the expected frequency in any cell of a contingency table is below 5. Correct application of Yates' correction can alter our conclusions and ensures a more accurate analysis of the data at hand.
Degrees of Freedom
The concept of degrees of freedom in statistics is a measure of the number of values in a calculation that are free to vary. When conducting a chi-square test, the degrees of freedom (df) are calculated based on the number of categories or levels within the variables being tested. It is often expressed as the number of categories minus one. For a 2x2 contingency table, there is typically 1 degree of freedom.

In our example, both reports used a chi-square test with 1 degree of freedom, indicating they analyzed two categories within the variable. Degrees of freedom play a significant role in determining the critical value against which the test statistic is compared. It is essential to match the chi-square value with the correct degrees of freedom when consulting the chi-square distribution table to determine statistical significance.
Significance Level
The significance level, denoted by the symbol \( \alpha \), is the probability of rejecting the null hypothesis when it is actually true, committing a Type I error. Common values for \( \alpha \) include 0.05 or 0.01. Choosing a significance level is subjective and depends on the consequences of making a Type I error. For example, in our camel treatment exercise, the first report used \( \alpha = 0.05 \) while the second report set \( \alpha = 0.10 \), implying a greater willingness to accept a false positive in the latter.

The selection of significance is level critical because it affects the critical value used to judge whether a chi-square value is sufficiently extreme to reject the null hypothesis. Understanding and appropriately setting the \( \alpha \) value is paramount, as it reflects the researcher's tolerance for risk and directly impacts the conclusions drawn from statistical tests.
Combining Chi-Square Results
Combining chi-square results from multiple studies or reports can be a powerful tool for strengthening conclusions, particularly when dealing with related data sets. When pooling chi-square values, one must ensure that the degrees of freedom are the same or appropriately adjusted for the combined test. The overall chi-square value for the combined data sets is simply the sum of all individual chi-square values.

As seen in our camel treatment reports example, the combined chi-square value was calculated as 6.55 by adding the individual \( X^2 \) values from both reports. It is then compared against a pre-determined critical value, which, if exceeded, suggests that the combined evidence is significant. It's a way to amplify statistical power and uncover trends that may not be apparent when examining results separately. However, when combining results, one must also consider differences in the significance levels used in each report and ensure consistency in the analytical approach to draw valid conclusions.

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Most popular questions from this chapter

For a shipment of cable, suppose that the specifications call for a mean breaking strength of 2,000 pounds. A sampling of the breaking strength of a number of segments of the cable has a mean breaking strength of 1955 pounds with an associated standard error of the mean of 25 pounds. Using the 5 percent level, test the significance of the difference found.

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