/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 15 Plot the point with the rectangu... [FREE SOLUTION] | 91Ó°ÊÓ

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Plot the point with the rectangular coordinates. Then find the polar coordinates of the point taking \(r>0\) and \(0 \leq \theta<2 \pi\). \((5,-12)\)

Short Answer

Expert verified
The polar coordinates of the point with rectangular coordinates (5, -12) are approximately (13, 5.176).

Step by step solution

01

Plot the point with rectangular coordinates

Plot the point (5, -12) on the Cartesian plane. This point is located 5 units to the right of the y-axis and 12 units below the x-axis. Draw a segment OM from the origin O to the point M(5, -12).
02

Calculate the distance r from the origin

To find the polar coordinate r, we need to calculate the distance between the origin O and the point M(5, -12). Use the distance formula: \(r = \sqrt{(x-0)^2 + (y-0)^2}\) Plug in the given coordinates (5, -12): \(r = \sqrt{(5 - 0)^2 + (-12 - 0)^2}\) Calculate the value of r: \(r = \sqrt{5^2 + (-12)^2} \) \(r = \sqrt{25 + 144}\) \(r = \sqrt{169}\) \(r = 13\) So, the value of r is 13.
03

Calculate the angle θ

To compute the polar coordinate θ, we need to find the angle between the segment OM and the positive x-axis. For this, use the tangent function: \(tan(\theta) = \frac{y}{x}\) Plug in the given coordinates (5, -12): \(tan(\theta) = \frac{-12}{5}\) Next, we need to find the angle θ: \(\theta = arctan(\frac{-12}{5})\) However, since the point is in the 4th quadrant and the arctan function only gives values for the 1st and 4th quadrant, we don't have to add any multiples of π to the angle: \(\theta = 5.17604... \text{ radians}\) To keep θ within the specified range, it is unnecessary to make any adjustments. The angle θ is approximately 5.176 radians.
04

Combine r and θ to find the polar coordinates

Now, combine r and θ to form the polar coordinates (r, θ). We know the value of r is 13, and the angle θ is approximately 5.176 radians. Hence, the polar coordinates are: (13, 5.176)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cartesian to polar conversion
Understanding the conversion from Cartesian coordinates to polar coordinates involves interpreting the position of a point in two different systems. In a Cartesian system, a point is identified by its horizontal (x) and vertical (y) distances from a reference point, commonly the origin (0,0). Alternatively, in a polar system, the same point is described by how far away it is from the origin (r), and the angle (θ) it forms with the positive x-axis.

To convert from Cartesian to polar coordinates, we employ a two-step process. First, we calculate the radial distance 'r' using the distance formula:
\[ r = \sqrt{x^2 + y^2} \]
The angle 'θ', also known as the polar angle, is determined through inverse trigonometric functions. Specifically, we frequently use the arctangent function because it relates the angle to the ratio of the y-coordinate to the x-coordinate:
\[ \theta = \text{atan2}(y, x) \]
However, caution is required in cases where the point lies in quadrants II, III, or IV, as adjustments may have to be made to ensure that the angle θ lies within the desired range of \(0 \leq \theta < 2\pi\).
Plotting points on Cartesian plane
Plotting points on the Cartesian plane is a fundamental skill in geometry that allows us to visually represent the location of points in a two-dimensional space. Each point on the plane is determined by an ordered pair of numbers, (x, y), which correspond to the point's horizontal and vertical positions. The Cartesian plane is divided into four quadrants, with the horizontal x-axis and vertical y-axis intersecting at the origin.

To plot a point, you start by moving from the origin along the x-axis by the amount indicated by the first number in the ordered pair. Then, move parallel to the y-axis by the amount indicated by the second number. The intersection of these two movements is the location of the point. For example, to plot (5, -12), count 5 units to the right along the x-axis and then 12 units down parallel to the y-axis.
Distance formula
The distance formula is a mathematical expression used to determine the straight-line distance between two points in a Cartesian coordinate system. This fundamental formula arises from the Pythagorean theorem and is used extensively in various fields, from navigation to graphics.

The general form of the distance formula is:\[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \]
When calculating the distance from the origin to a point (x, y), the formula simplifies since the origin's coordinates are (0,0), leading to:\[ r = \sqrt{x^2 + y^2} \]
In the given exercise, we used the simplified distance formula to find the radial distance 'r' for the polar coordinate, which was key for the Cartesian to polar conversion.
Inverse trigonometric functions
Inverse trigonometric functions are used to determine angles based on the ratios of the sides of a right triangle. They are the mathematical opposites of the standard trigonometric functions: sine, cosine, and tangent. Of these inverses, the arctangent function is especially important for converting Cartesian coordinates to polar coordinates. It gives an angle whose tangent is a given number and is denoted as \( \arctan \) or \( \tan^{-1} \).

For example, to find the angle 'θ' in polar coordinates, we use the arctangent function in the relation:\[ \theta = \text{atan2}(y, x) \]
This 'atan2' function takes into account the signs of both 'x' and 'y' to determine the correct quadrant for the angle. In the exercise's step by step solution, the use of 'atan2' simplified the process of finding the correct angle without needing additional tweaks for the angle range.

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Most popular questions from this chapter

Let \(P\) be a point located a distance \(d\) from the center of a circle of radius \(r\). The curve traced out by \(P\) as the circle rolls without slipping along a straight line is called a trochoid. (The cycloid is the special case of a trochoid with \(d=r .\) ) Suppose that the circle rolls along the \(x\) -axis in the positive direction with \(\theta=0\) when the point \(P\) is at one of the lowest points on the trochoid. Show that the parametric equations of the trochoid are $$ x=r \theta-d \sin \theta \quad \text { and } \quad y=r-d \cos \theta $$ where \(\theta\) is the same parameter as that for the cycloid. Sketch the trochoid for the cases in which \(dr\).

Determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false. The curve with parametric equations \(x=f(t)\) and \(y=g(t)\) is a line if and only if \(f\) and \(g\) are both linear functions of \(t\).

Find the foci and vertices of the ellipse, and sketch its graph. $$ 4 x^{2}+9 y^{2}=36 $$

a. Plot the graphs of the cardioids \(r=a(1+\cos \theta)\) and \(r=a(1-\cos \theta)\). b. Show that the cardioids intersect at right angles except at the pole.

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