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Specify the moment estimators for \(\mu\) and \(a^{2}\) for the normal distribution.

Short Answer

Expert verified
The moment estimator for \(\mu\) is the sample mean, \(\bar{X} = \frac{1}{n} \sum_{i=1}^{n} X_{i}\), and the moment estimator for \(a^{2}\) is the sample variance, \(S^{2} = \frac{1}{n-1} \sum_{i=1}^{n} (X_{i} - \bar{X})^2\).

Step by step solution

01

Moment Estimator for \(\mu\)

The first moment (or mean) of a normal distribution corresponds to \(\mu\). So, the moment estimator for \(\mu\) is the sample mean, denoted \(\bar{X}\). It is calculated by summing all the observations and dividing by the number of observations. Mathematically, it can be represented as: \(\bar{X} = \frac{1}{n} \sum_{i=1}^{n} X_{i}\). Here, \(n\) is the sample size, and \(X_i\) is a particular observation.
02

Moment Estimator for \(a^{2}\)

The second central moment (or variance) of a normal distribution corresponds to \(a^{2}\). So, the moment estimator for \(a^{2}\) is the sample variance, denoted \(S^{2}\). It's calculated by subtracting the sample mean from each observation, squaring the result, summing all these squares, and then dividing by the number of observations minus one. Mathematically, it is represented as: \(S^{2} = \frac{1}{n-1} \sum_{i=1}^{n} (X_{i} - \bar{X})^2\). Here, \(\bar{X}\) is the sample mean derived in the previous step.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Normal Distribution
The normal distribution, often referred to as the Gaussian distribution, is a probability distribution that is symmetrically centered around its mean, \( \mu \), and characterizes many natural phenomena. Imagine a bell-shaped curve; this is what the normal distribution looks like. The further away from the mean, the less likely the value. This distribution is described by its mean (\(\mu\)) and variance (\(\sigma^2\)), where the variance measures the spread of the data.

When working with a normal distribution, a key aspect to grasp is the idea that about 68% of the data falls within one standard deviation of the mean, about 95% within two standard deviations, and about 99.7% within three. This is known as the empirical rule and is crucial when making predictions or inferences about populations based on a normal distribution. Understanding the normal distribution is fundamental since moment estimators are used to estimate the parameters (\(\mu\) and \(\sigma^2\)) of such distributions from sample data.
Sample Mean as a Moment Estimator
The sample mean is a critical statistic used to estimate the population mean (\(\mu\)) in a normal distribution. It is denoted as \(\bar{X}\) and is the arithmetic average of all observed data points. To calculate the sample mean, you sum up all the individual observations \(X_i\) and divide by the total number of observations \(n\). The formula is: \[\bar{X} = \frac{1}{n} \sum_{i=1}^{n} X_{i}\].

As a measure of central tendency, the sample mean plays a pivotal role in the moment estimator method. It is considered the first moment about the origin, hence when estimating \(\mu\), the sample mean itself is used. The accuracy of the sample mean as an estimator increases with the sample size; the larger the number of observations, the closer the sample mean is to the population mean, assuming a random and representative sample. This aligns with the law of large numbers, implying the reliability of the sample mean as an estimator.
Sample Variance as a Moment Estimator
The sample variance \(S^{2}\) provides an estimation of the population variance \(\sigma^{2}\) of a normal distribution. To compute the sample variance, you take each observation, subtract the sample mean \(\bar{X}\), square this difference, sum all these squared differences, and finally divide by \(n-1\), one less than the sample size. This correction, known as Bessel's correction, accounts for the bias in the estimation of the population variance from a sample. The formula for sample variance is: \[S^{2} = \frac{1}{n-1} \sum_{i=1}^{n} \left(X_{i} - \bar{X}\right)^{2}\].

As a second moment about the mean, the sample variance is a measure of dispersion, indicating how spread out the data points are around the mean. It's square root, the sample standard deviation, is what most people use to understand variability intuitively. In the context of moment estimators, knowing the spread of data can be as informative as knowing its central location, especially when making predictions or assessing the reliability of the data.

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Most popular questions from this chapter

In a batch chemical process, two catalysts arc being compared for their effect on the output of the process reaction. A sample of \(\lfloor 2\) batches was prepared using catalyst 1 and a sample of 10 batches was obtained using catalyst \(2 .\) The 12 batches for which catalyst 1 was used gave an average yield of 85 with a sample standard deviation of \(4,\) and the second sample gave an average of 81 and a sample standard deviation of \(5 .\) Find a \(90 \%\) confidence interval for the difference between the population means, assuming that the: populations art: approximately normally distributed with equal variances.

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Two kinds of thread are being compared for strength. Fifty pieces of each type of thread are tested under similar conditions. Brand \(A\) had an average: tensile strength of 78.3 kilograms with a standard deviation of 5.6 kilograms, while brand \(B\) had an average tensile strength of 87.2 kilograms with a standard deviation of 6.3 kilograms. Construct a \(95 \%\) confidence interval for the difference of the population means.

A group of human factor researchers are concerned about reaction to a stimulus by airplane pilots with a certain cockpit arrangement. An experiment was conducted in a simulation laboratory and 15 pilots were used with average reaction time 3.2 seconds and sample standard deviation 0.6 seconds, It is of interest to characterize extremes (i.e., worst case scenario). To that end, answer the following: (a) Give a particular important one-sided \(99 \%\) confidence bound on the mean reaction time. What assumption, if any, must you make on the distribution of reaction time? (b) Give a \(99 \%\) one-sided prediction interval and give an interpretation of what it means. Must you make an assumption on the distribution of reaction time to compute this bound? (c) Compute a one-sided tolerance bound with \(99 \%\) confidence that involves \(95 \%\) of reaction times. Again, give interpretation and assumption on distribution if any. [Note: The one-sided tolerance limit values are also included in Table A.7].

(a) According to a report in the Roanoke Times \& World-News, approximately \(2 / 3\) of the 1600 adults polled by telephone said they think the space shuttle program is a good investment for the country. Find a \(95 \%\) confidence interval for the proportion of American adults who think the space shuttle program is a good investment for the country. (b) What can we assert with \(95 \%\) confidence about the possible size of our error if we estimate the proportion of American adults who think the space shuttle program is a good investment to be \(2 / 3 ?\)

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