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A random sample of 10 chocolate energy bars of a certain brand has, on average, 230 calories with a standard deviation of 15 calories. Construct a \(99 \%\) confidence interval for the true mean calorie content of this brand of energy bar. Assume that the distribution of the calories is approximately normal.

Short Answer

Expert verified
The 99% confidence interval for the true mean calorie content of this brand of energy bar is from 217.83 to 242.17 calories.

Step by step solution

01

Calculate Standard Error

The first step is to calculate the standard error (SE). The SE is given by the formula: SE = s/√n, where s is the standard deviation and n is the sample size. Substituting the given values, SE becomes \(15/√10 = 4.74 (rounded to two decimal places)\)
02

Determine the Critical Value

The next step is to find the critical value (z*) from the z-table. Since we are constructing a 99% confidence interval, this implies that 0.5% of the data lies to the right and 0.5% to the left in a two-tailed test. Therefore, the critical z-value corresponding to 0.995 (0.5% + 99%) in the z-table is approximately 2.57.
03

Calculate Margin of Error

The Margin of Error (E) is calculated as the product of the critical value and the standard error. Therefore, E = z* x SE = 2.57 x 4.74 = 12.17
04

Formulate the Confidence Interval

The final step is to add and subtract the margin of error from the sample mean to formulate the confidence interval: \((230 - 12.17, 230 + 12.17) = (217.83, 242.17)\). Thus, we are 99% confident that the true mean calorie content of this brand of energy bar lies between 217.83 and 242.17 calories.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standard Error
The concept of Standard Error (SE) is fundamental in statistical analysis, especially when we are dealing with sample data and want to make inferences about a population parameter. In simple terms, the standard error is a measure of the amount of variability or spread in a sample statistic. It is used to determine how much a sample mean deviates from the true population mean.

The standard error can be calculated using the formula:
SE = \( \frac{s}{\sqrt{n}} \), where \( s \) represents the sample standard deviation, and \( n \) is the sample size. The smaller the SE, the more precise the estimate of our sample statistic is likely to be. In the example provided, the standard deviation is given as 15 calories, and the sample size is 10 chocolate energy bars. Using the formula, the standard error is approximately 4.74 calories.

Understanding the standard error is crucial because it is part of the foundation of how we create confidence intervals and conduct hypothesis testing. A critical point to remember is that the standard error decreases when the sample size increases, suggesting the sample mean is likely a better estimate of the population mean.
Critical Value
In statistical analysis, the Critical Value is a key concept used in hypothesis testing and constructing confidence intervals. It represents a point in the distribution of a test statistic beyond which there is a certain probability that the test statistic would not typically lie. In other words, it defines the cut-off point or threshold.

For constructing a confidence interval, this critical value helps to determine the range within which the true population parameter lies with a certain level of confidence. To find it, one typically refers to a table (such as the z-table for normal distributions) that corresponds to the chosen level of confidence. In our example, for a 99% confidence interval, we are looking for the z-value that leaves 0.5% of the data on each end in a two-tailed test.

The z-table tells us that the z-value associated with 99.5% (since we add the 0.5% tail to our 99% confidence level) is approximately 2.57. This critical value multiplies by the standard error to give us the margin of error needed to construct our confidence interval. A more significant critical value suggests a wider range of possible values for the population parameter, which means our interval will be broader when we need higher confidence.
Margin of Error
The Margin of Error is an expression of the extent to which a sample statistic could differ from the true population parameter. It is closely tied to confidence intervals as it provides the range above and below the sample statistic to create the interval. Mathematically, the margin of error is the product of the critical value and the standard error: Margin of Error (E) = Critical Value (z*) × Standard Error (SE).

In the example of the chocolate energy bars, the margin of error is calculated by multiplying the critical value of 2.57 (for a 99% confidence level) by the standard error of 4.74, yielding a margin of error of about 12.17 calories. This value is then used to construct the confidence interval by adding and subtracting from the sample mean.

The resultant interval (217.83, 242.17) indicates that we are 99% confident the true mean calorie content of the energy bars is within this range. A larger margin of error provides a wider interval, implying less precision, but more confidence that the interval contains the true mean, while a smaller margin of error yields a narrower interval, suggesting greater precision but potentially less confidence.

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Most popular questions from this chapter

An automotive company is considering two types of batteries for its automobile. Sample information on the life of the battery is being used. Twenty batteries of type \(A\) and twenty batteries of type \(B\) are being used. The summary statistics are \(X A=32.91\), \(x_{B}=30.47, s_{A}=1.57,\) and \(s_{B}-1.74 .\) Assume the data on each battery are normally distributed and assume \(\sigma_{A}=\sigma_{B}\) (a) Find a \(95 \%\) confidence interval on \(\mu_{A}-\mu_{B}\). (b) Draw some conclusion from (a) that provides some insight into whether \(A\) or \(B\) should be adopted.

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A certain supplier manufactures a type of rubber mat that is sold to automotive companies. In the application, the pieces of material must have certain hardness characteristics. Defective mats are occasionally discovered and rejected. The supplier claims that the proportion defective is \(0.05 .\) A challenge was made by one of the clients who purchased the product. Thus an experiment was conducted in which 400 mats are tested and 17 were found defective. (a) Compute a \(95 \%\) two-sided confidence interval on the proportion defective. (b) Compute an appropriate \(95 \%\) one-sided confidence interval on the proportion defective. (c) Interpret both of these in (a) and (b) and comment on the claim made by the supplier.

In a study conducted by the Department of Zoology at. Virginia Tech. fifteen "samples" of water were collected from a certain station in the James River in order to gain some insight regarding the amount of orthophosphorous in the river. The concentration of the chemical is measured in milligrams per liter. Let us suppose that the mean at the station is not as important as the upper extremes of the distribution of the chemical at the station. Concern centers around whether the concentrations at these extremes are too large. Readings for the fifteen water samples gave a sample mean of 3.84 milligrams per liter and sample standard deviation of 3.07 milligrams per liter. Assume that the readings are a random sample from a normal distribution. Calculate a prediction interval (upper \(95 \%\) prediction limit) and a tolerance limit \((95 \%\) upper tolerance limit that exceeds \(95 \%\) of the population of value). Interpret both; that is, tell what each communicates to us about the upper extremes of the distribution of orthophosphorous at the sampling station.

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