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For an F-distribution find (a) \(f_{0.05}\) with \(v_{1}=7\) and \(v_{2}=15\); (b) \(f_{0.05}\) with \(v_{1}=15\) and \(v_{2}=7\) : (c) \(f_{0.01}\) with \(v_{1}=24\) and \(v_{2}=19\); (el) \(f_{0.95}\) with \(v_{1}=19\) and \(v_{2}=24\) (e) \(f_{0.99}\) with \(v_{1}=28\) and \(v_{2}=12\).

Short Answer

Expert verified
The solutions will be found from the F-distribution table. (a) \(f_{0.05}\) with \(v_{1}=7\), \(v_{2}=15\); (b) \(f_{0.05}\) with \(v_{1}=15\), \(v_{2}=7\); (c) \(f_{0.01}\) with \(v_{1}=24\), \(v_{2}=19\); (d) \(f_{0.95}\) with \(v_{1}=19\), \(v_{2}=24\); (e) \(f_{0.99}\) with \(v_{1}=28\), \(v_{2}=12\). These values will depend on the specific F-distribution table used to perform the lookups.

Step by step solution

01

Understand the Parameters

The parameters to use to look up the critical value in the F-distribution table are given in each part of the problem. The parameters are the alpha level and the degrees of freedom for the numerator (\(v_{1}\)) and the denominator (\(v_{2}\)).
02

Use the Parameters and Locate the F-Critical Value

Use these parameters to locate the F-Critical Value in the F-distribution table. Find the intersection corresponding to the parameters on the table's respective rows and columns. Do this for each part of the problem.
03

Reference the Value

The value found at the intersection in the F-distribution table is the F-Critical Value. It's important to note that some of these values may require rounding depending on the precision required.
04

Answer the Questions

'(a)’ Corresponds to the F-critical value at \(v_{1}=7\) and \(v_{2}=15\) at 0.05 alpha level, ‘(b)' at \(v_{1}=15\) and \(v_{2}=7\) at 0.05 alpha level, ‘(c)’ at \(v_{1}=24\) and \(v_{2}=19\) at 0.01 alpha level, ‘(d)’ at \(v_{1}=19\) and \(v_{2}=24\) at 0.95 alpha level, and ‘(e)' at \(v_{1}=28\) and \(v_{2}=12\) at 0.99 alpha level.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

F-critical value
The F-critical value is a crucial part of statistical analysis, especially when performing hypothesis testing that involves the F-distribution. - It represents the cutoff point or threshold beyond which you would reject the null hypothesis in an F-test. - Obtaining the F-critical value requires you to know the degrees of freedom for both the numerator and the denominator, as well as the alpha level associated with your test. In any given scenario, you compare the test statistic derived from your sample data to the F-critical value. If the test statistic exceeds the F-critical value, you have enough evidence to reject the null hypothesis. On the other hand, if it does not, the evidence isn't strong enough to make a rejection.
Degrees of freedom
Degrees of freedom are fundamental for finding the critical values in any statistical test, including those that utilize the F-distribution. - In an F-test, you typically deal with two degrees of freedom: one corresponding to the numerator (\(v_{1}\)) and the other to the denominator (\(v_{2}\)).- These degrees of freedom are derived from sample sizes or related parameters of the datasets that you are comparing.The degrees of freedom play a key role in determining the shape of the F-distribution curve. Larger degrees of freedom generally produce a distribution closer to the normal distribution shape, which is crucial when approximating probabilities and making inferences about sampled data.
Alpha level
The alpha level, often denoted as \(\alpha\), is an important parameter in statistical hypothesis testing.- It signifies the probability of making a Type I error, which occurs when the null hypothesis is erroneously rejected.- Common alpha levels used in statistical tests are 0.05, 0.01, and 0.10.When interpreting the F-critical value, alpha helps define the critical region of the distribution. For example, an alpha level of 0.05 implies a 5% risk level that you would falsely reject the null hypothesis. Lowering your alpha level, such as using 0.01, decreases this risk but requires stronger evidence to achieve statistical significance.
F-distribution table
The F-distribution table is an essential tool for statisticians and researchers when performing an F-test. - This table organizes critical values according to different combinations of \(v_{1}\) and \(v_{2}\) degrees of freedom along with various alpha levels. - It allows you to determine the corresponding F-critical value by locating the intersection point of the values and parameters you are working with.While using the F-distribution table, make sure you interpret the values accurately, as misreading could lead to incorrect conclusions. Given advances in technology, you might also find digital tools or software that provide a more accessible way to calculate these critical values without manually looking them up in tables.

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Most popular questions from this chapter

The grade-point averages of 20 college seniors selected at random from a graduating class are as follows: $$\begin{array}{rrrrr}3.2 & 1.9 & 2.7 & 2.4 & 2.8 \\ 2.9 & 3.8 & 3.0 & 2.5 & 3.3 \\ 1.8 & 2.5 & 3.7 & 2.8 & 2.0 \\ 3.2 & 2.3 & 2.1 & 2.5 & 1.9\end{array}$$ Calculate the standard deviation.

A normal population with unknown variance has a mean of \(20 .\) Is one likely to obtain a random sample of size \(!\) ) from this population with a mean of 24 and a standard deviation of \(4.1 ?\) If not, what conclusion would you draw?

The heights of 1000 students are approximately normally distributed with a mean of 174.5 centimeters and a standard deviation of 6.9 centimeters. If 200 random samples of size 25 are drawn from this population and the means recorded to the nearest tenth of a centimeter, determine (a) the mean and standard deviation of the sampling distribution of \(\bar{X}\); (b) the number of sample means that fall between 172.5 and 175.8 centimeters inclusive; (c) the number of sample means falling below 172.0 centimeters.

A random sample of size 25 is taken from a normal population having a mean of 80 and a standard deviation of \(5 .\) A second random sample of size 36 is taken from a different normal population having a mean of 75 and a standard deviation of 3 . Find the probability that the sample mean computed from the 25 measurements will exceed the sample mean computed from the 36 measurements by at least 3.4 but less than 5.9 . Assume the difference of the means to be measured to the nearest tenth.

A manufacturing firm claims that the batteries used in their electronic games will last an average of 30 hours. To maintain this average. L6 batteries are tested each month. If the computed /-value falls between \(-t_{0.025}\) and \(t_{0.025},\) the firm is satisfied with its claim. What conclusion should the firm draw from a sample that has a mean \(x=27.5\) hours and a standard deviation \(a=5\) hours? Assume the distribution of battery lives to be approximately normal.

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