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The loaves of rye bread distributed to local stores by a certain bakery have an average length of 30 centimeters and a standard deviation of 2 centimeters As suming that the lengths are normally distributed, what percentage of the loaves are (a) longer than 31.7 centimeters? (b) between 29.3 and 33.5 centimeters in length? (c) shorter than 25.5 centimeters?

Short Answer

Expert verified
Based on the computed Z-scores and the standard normal distribution table, we find the percentage of loaves longer than 31.7cm, percentage between 29.3cm and 33.5cm, and percentage shorter than 25.5cm respectively.

Step by step solution

01

Identify given parameters and question

We are given that the average (mean, μ) length of the loaves is 30cm, and the standard deviation (σ) is 2cm. The lengths are normally distributed. We are then tasked to find (a) what percentage of the loaves are longer than 31.7cm, (b) what percentage of loaves are between 29.3 cm and 33.5 cm in length and (c) what percentage of loaves are shorter than 25.5cm, using the concept of Normal Distribution and Z-Score.
02

Apply the Z-Score formula

In a normally distributed dataset, the Z-score for a value \(x\) can be calculated with the formula \(Z = \frac{{x - μ}}{σ}\). Hence, we calculate the z-scores for each specific problem: (a) \(Z_1 = \frac{{31.7 - 30}}{2}\), (b) \(Z_2 = \frac{{29.3 - 30}}{2}\) and \(Z_3 = \frac{{33.5 - 30}}{2}\), and (c) \(Z_4 = \frac{{25.5 - 30}}{2}\).
03

Use the standard normal distribution table

After getting the Z-scores, we have to refer to the Z-table (standard normal distribution table) to get the percentage of data related to these Z-scores. Remember, the Z-table gives us the percentage below the given Z-score. Therefore, we find the area under the normal curve up to the corresponding Z-scores.
04

Interpretation of the results

Finally, we interpret the results from the table. (a) For the loaves that are longer than 31.7cm, we find the percentage corresponding to above \(Z_1\) (since we're looking for the percentage that's longer than this value, i.e., in the right tail of the normal distribution). (b) For the loaves that are between 29.3cm and 33.5cm, we find the difference in percentages corresponding to \(Z_2\) and \(Z_3\) (since we're looking for the percentage that is in between these two lengths). (c) For the loaves that are shorter than 25.5cm, we find the percentage corresponding to below \(Z_4\) (since we're looking for the percentage that's less than this value, i.e., in the left tail of the normal distribution).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Z-Score
The Z-score is a measure that describes a value's position relative to the mean of a dataset, expressed in terms of standard deviations. To put it simply, it tells us how far away a specific data point is from the average. This helps us understand how unusual or typical a value is in a normal distribution.
For example, in the case of the rye bread, we want to know how long a loaf is compared to the average. By computing the Z-score, we can determine where a particular loaf length stands with respect to all other loaves.
  • A positive Z-score means the value is above the mean.
  • A negative Z-score means the value is below the mean.
  • A Z-score of zero indicates the value is at the mean.
The formula to calculate the Z-score is:
\[ Z = \frac{x - \mu}{\sigma} \]
Where:
  • \( x \) is the value of interest (e.g., loaf length).
  • \( \mu \) is the mean (average) of the distribution.
  • \( \sigma \) is the standard deviation.
Using this formula helps us easily compare and analyze different data points within a normally distributed dataset.
Standard Deviation
Standard deviation is a key concept in statistics that measures the amount of variation or spread in a set of data values. In simpler terms, it tells us how much the data points tend to deviate from the mean.
This is especially helpful when dealing with normal distributions, where data tends to cluster around a central value, the mean.
  • A small standard deviation means the data points are close to the mean.
  • A large standard deviation indicates the data points are spread out over a wider range.
In the problem involving the loaves of bread, the standard deviation of 2 cm indicates how varied the loaf lengths are around the average. Knowing the standard deviation allows us to understand how consistently sized the breads are. With a normal distribution, approximately 68% of the data lies within one standard deviation from the mean, 95% within two standard deviations, and 99.7% within three standard deviations. This provides a framework for predicting the probability of where a certain length of loaf might fall.
Mean
The mean, often referred to as the average, is a fundamental concept in statistics. It is calculated by summing all data points and then dividing by their count. This gives us a central value that represents the dataset as a whole.
The mean helps us understand the overall tendency of data. For example, in the context of the rye bread loaves, a mean length of 30 cm gives us a benchmark against which other loaf lengths are compared. Calculating the mean gives insights into the typical product size the bakery produces.
  • Calculating the mean: Add all the values together and divide by the number of values.
Mathematically, the mean is calculated as follows:
\[ \mu = \frac{1}{n}\sum_{i=1}^{n}x_i \]
Where:
  • \( n \) is the number of observations.
  • \( x_i \) is each individual data point.
Through the mean, we establish a foundation to further delve into variations and standards like standard deviation and Z-scores in a data set.

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Most popular questions from this chapter

In a chemical processing plant it is important that the yield of a certain type of batch product stay above \(80 \%\). If it stays below \(80 \%\) for an extended period of time, the company loses money. Occasional defective manufactured batches are of little concern. But if several batches per day are defective, the plant shuts down and adjustments are made. It is known that the yield is normally distributed with standard deviation \(4 \%\). (a) What is the probability of a "false alarm" (yield below \(80 \%\) ) when the mean yield is \(85 \% ?\) (b) What is the probability that a manufactured batch will have a yield that exceeds \(80 \%\) when in fact the mean yield is \(79 \% ?\)

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A pair of dice is rolled 180 times. What is the probability that a total of 7 occurs (a) at least 25 times? (b) between 33 and 41 times inclusive? (c) exactly 30 times?

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