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To avoid detection at customs, a traveler places 6 narcotic tablets in a bottle containing 9 vitamin pills that are similar in appearance. If the customs official selects 3 of the tablets at random for analysis, what is the probability that the traveler will be arrested for illegal possession of narcotics?

Short Answer

Expert verified
The probability that the traveler will be arrested for illegal possession of narcotics may be calculated by dividing the number of ways to select 3 tablets such that at least 1 is a narcotic, by the total number of ways to select any 3 tablets from the total. This involves calculations of combinations and applying the probability formula.

Step by step solution

01

Identify the total number of outcomes

We start by identifying the total number of ways we can choose 3 tablets out of 15. This can be calculated using the combination formula \(\binom{n}{r} = \frac{n!}{r!(n-r)!}\). Here, \(n = 15\) (the total number of tablets) and \(r = 3\) (the number of tablets being selected). So, total outcomes will be \(\binom{15}{3}= \frac{15!}{3!(15-3)!}\).
02

Calculate the desired outcomes

The customs official will arrest the traveler if he selects at least one narcotic tablet. So, we calculate the number of ways to select 3 tablets such that at least 1 is narcotic. This will be the sum of the combinations for 1, 2, and 3 narcotic tablets. So, desired outcomes will be \(\binom{6}{1}\binom{9}{2} + \binom{6}{2}\binom{9}{1}+ \binom{6}{3}\binom{9}{0}\).
03

Apply the probability formula

Finally, we calculate the probability. The formula for probability is \(\frac{Number\: of\: Desired\: Outcomes}{Total\: Number\: of\: Outcomes}\). By plugging our calculated values into this formula, we can find the probability that the traveler will be arrested for illegal possession of narcotics.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Combinatorial Analysis
Combinatorial analysis helps us determine the number of possible arrangements in a set when the order of the arrangements doesn't matter, often referred to as combinations. In our exercise, the customs official is not concerned with the order in which the three tablets are selected, only the content of the selection.

Consider a simple example: selecting a team of 3 people from a group of 10. It doesn't matter if Tom, Dick, or Harry are chosen first, second, or third; all that matters is whether they are on the team. The combination is represented using binomial coefficients, which look like \( \binom{n}{r} \) and read as 'n choose r'. These coefficients are a part of combinatorial analysis and are essential for solving our original problem.

The traveler's mix of vitamin and narcotic pills can be seen as two separate groups from which we are making selections. By determining the combinations possible with 6 narcotic and 9 vitamin pills when picking 3, we are applying combinatorial analysis to assess the probability of a specific outcome – in this case, getting caught.
Probability Formula
The probability formula is a fundamental concept in statistics and probability theory, expressing the likelihood of a specific event occurring. It is represented as \( P(E) = \frac{Number\: of\: Desired\: Outcomes}{Total\: Number\: of\: Outcomes} \).

In our exercise, the event 'E' is the traveler getting arrested, contingent upon at least one narcotic pill being chosen. 'Desired outcomes' may feel misleading—certainly, the traveler doesn't desire arrest—but in probability terminology, these are simply the outcomes that fulfill the condition for event E to occur.

To determine the probability that an event will occur, calculate the possible ways that event can occur and divide it by the total number of possible outcomes. The challenge often lies in accurately determining these outcomes, as you must consider all possibilities that fit the criteria of the event.
Factorial Notation
Factorial notation is pervasive in combinatorial analysis and probability. The factorial of a non-negative integer 'n', denoted by \(n!\), is the product of all positive integers less than or equal to 'n'. For example, \(5! = 5 \times 4 \times 3 \times 2 \times 1 = 120\).

Factorials are crucial when calculating permutations and combinations because they provide the total number of ways 'n' different items can be arranged, which is the foundation of combinatorial problems like our exercise. Importantly, \(0!\) is defined to be 1, which is consistent with the convention for an empty product. This convention ensures that formulae involving factorials remain valid even for situations where no items are selected, as seen in the \( \binom{9}{0} \) term of our desired outcomes calculation.

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