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The manufacturer of a tricycle for children has received complaints about defective: brakes in the product. According to the design of the product and considerable preliminary testing, it had been determined that the probability of the kind of defect in the complaint was 1 in 10000 (i.e., 0001 ). After a thorough investigation of the complaints, it was determined that during a certain period of time, 200 products were randomly chosen from production and 5 experienced defective brakes. (a) Comment on the "1 in \(10,000^{\prime \prime}\) claim by the manufacturer. Use a probabilistic argument. Use the binomial distribution for your calculations. (b) Do the work using the Poisson approximation.

Short Answer

Expert verified
To comment on the manufacturer's claim, calculate the probabilities of finding defective items using both the binomial distribution and the Poisson approximation, and compare these results with the manufacturer's claimed probability of 0.0001.

Step by step solution

01

Calculate Using Binomial Distribution

In this case, the number of trials \( n \) is 200 (the total number of tested products), the number of successes \( k \) is 5 (the number of defective items) and the success probability \( p \) for each trial is 0.0001. The formula for the binomial distribution is given by:\[B_{k; n, p} = C_{n}^{k} \cdot p^{k} \cdot (1-p)^{n-k}\]Where \( C_{n}^{k} \) is the binomial coefficient, which can be calculated as \( n! / k!(n-k)! \). The probability can be computed using these values.
02

Calculate Using Poisson Approximation

The Poisson distribution can be used as an approximation of the binomial distribution for large n and small p. The parameter \( \lambda \) is equal to \( n \cdot p \). Therefore, for this case, it is \( \lambda = 200 \cdot 0.0001 = 0.02 \).The Poisson probability formula is given by:\[P(x; \lambda) = \frac{\lambda^{x} \cdot e^{-\lambda}}{x!}\]This formula gives the probability of having exactly x defective items. You can use these values to calculate the probability according to the Poisson approximation.
03

Compare The Results

Comparison of the two obtained results will enable the comment on the manufacturer's claim. If the results show that the probability to have 5 or more defective items is significantly larger than the claimed 0.0001 probability of a defect, the claim by the manufacturer would be considered unreasonably optimistic.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Binomial Distribution
When studying probability and statistics for engineers, the binomial distribution stands out as a fundamental concept that helps in understanding the behavior of a fixed number of independent experiments, known as Bernoulli trials. Let's take the provided exercise where a manufacturer experiences defective brakes. Here, each tricycle represents a Bernoulli trial with two possible outcomes: defective or not defective.

In this scenario, the binomial distribution helps to address the probability of observing a certain number of defective products out of the total sample. The formula for the binomial distribution is given as:\[B_{k; n, p} = C_{n}^{k} \times p^{k} \times (1-p)^{n-k}\]where \(B_{k; n, p}\) is the probability of having exactly \(k\) defects in \(n\) trials, and \(p\) is the probability of a defect in a single trial. The term \(C_{n}^{k}\) represents the number of combinations of \(n\) items taken \(k\) at a time.

Engineering professionals often use this formula to evaluate the reliability and quality control of their products. By comprehending the nuances of the binomial distribution, students can better assess the validity of claims such as the '1 in 10,000' defect rate put forth by the tricycle manufacturer.
Poisson Approximation
The Poisson approximation is a practical method applied within probability theory, particularly when dealing with rare events in a large population. In our exercise, the use of the Poisson distribution to approximate the binomial distribution results from a large number of products (n) and a very small probability of defect (p). This simplifies the computation, especially when the binomial calculations become unwieldy.

With the Poisson approximation, the key parameter is \(\lambda\), which is the expected number of occurrences over the interval, calculated as \(\lambda = n \cdot p\). The probability of having exactly \(x\) defective items is then calculated using:\[P(x; \lambda) = \frac{\lambda^{x} \cdot e^{-\lambda}}{x!}\]The elegance of the Poisson approximation lies in its simplicity and the ease with which it deals with processes involving a large number of trials and a small probability of success—a scenario commonly encountered by engineers in quality testing and reliability analysis. By mastering this approximation, students can more efficiently tackle probability calculations pertinent to real-world engineering situations.
Probability Theory
At its core, probability theory is the mathematical framework that enables us to quantify uncertainty and make informed predictions about random phenomena. It comprises a set of principles and models that find extensive applications across various fields, including engineering. This theory is the foundation upon which statistical models, like the binomial and Poisson distributions, are built.

Understanding probability theory is imperative for anyone in the field of engineering. It allows them to model and analyze the likelihood of potential outcomes and make decisions based on statistical evidence. Whether evaluating the reliability of manufacturing processes, like in our tricycle manufacturer's case, or anticipating the failure rates of systems, proficiency in probability theory empowers engineers with the tools necessary to mitigate risks and improve designs.

In educational contexts, illustrating probability theory through exercises involving real-world scenarios, like product defect rates, greatly enhances the learning experience. It provides students with a tangible connection between abstract concepts and their practical applications, fostering deeper comprehension and retention of the material.

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Most popular questions from this chapter

A company is interested in evaluating its current inspection procedure on shipments of 50 identical items. The procedure is to take a sample of 5 and pass the shipment if no more than 2 are found to be defective. What proportion of \(20 \%\) defective shipments will be accepted?

A government task force suspects that some manufacturing companies are in violation of federal pollution regulations with regard to dumping a certain type of product. Twenty firms are under suspicion but all cannot be inspected. Suppose that 3 of the firms are; in violation. (a) What is the probability that inspection of 5 firms finds no violations? (b) What is the probability that the plan above will find two violations?

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Suppose that for a very large shipment of integrated-circuit chips, the probability of failure for any one chip is \(0.10 .\) Assuming that the assumptions underlying the binomial distributions are met, find the probability that at most 3 chips fail in a random sample of 20.

An electronic switching device occasionally malfunctions and may need to be replaced. It is known that the device is satisfactory if it makes, on the average, no more than 0.20 error per hour. A particular 5-hour period is chosen as a "test" on the device. If no more than 1 error occurs, the device is considered satisfactory. (a) What is the probability that a satisfactory device will be considered unsatisfactory on the basis of the rest? Assume that a Poisson process exists. (b) What is the probability that a device will be accepted as satisfactory when, in fact, the mean number of errors is \(0.25 ?\) Again, assume that a Poisson process exists.

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