/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 43 Let \(X\) denote the reaction ti... [FREE SOLUTION] | 91Ó°ÊÓ

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Let \(X\) denote the reaction time, in seconds, to a certain stimulus and \(Y\) denote the temperature \(\left({ }^{\circ} \mathrm{F}\right)\) at which a certain reaction starts to take place. Suppose that two random variables \(X\) and \(Y\) have the joint density $$ f(x, y)=\left\\{\begin{array}{ll} 4 x y, & 0< x < 1,0 < y < 1, \\ 0, & \text { elsewhere. } \end{array}\right. $$ Find (a) \(\mathrm{P}\left(0 \leq X \leq \frac{1}{2}\right.\) and \(\left.\frac{1}{4} \leq Y \leq \frac{1}{2};\right)\) (b) \(P( X < Y)\).

Short Answer

Expert verified
The solution to part (a) will be evaluated by regular double integration. For the second part, substitution and properties of definite integral will be put into use to help simplify the integral and make it possible to evaluate.

Step by step solution

01

Analyzing and Solving Part (a)

The probability that \(X\) and \(Y\) fall in a certain range, can be found by integrating the joint pdf over that range. Hence, \(\mathrm{P}\left(0 \leq X \leq \frac{1}{2}, \frac{1}{4} \leq Y \leq \frac{1}{2}\right) = \int_{0}^{1/2} \int_{1/4}^{1/2} 4xy\, \mathrm{d}y\, \mathrm{d}x\). Since \(x\) and \(y\) can be seen as independent variables, solve the integral by performing the inner integral first and then the outer integral.
02

Solving Part (b)

The probability that \(X < Y\) is given by integrating the joint pdf over the region where \(X < Y\). This is equivalent to the double integral: \(P(X<Y) = \int_{0}^{1} \int_{0}^{y} 4xy \, \mathrm{d}x \, \mathrm{d}y\), simplifying this using substitution and properties of definite integral.
03

Final Calculations

Now, perform the integration for both part (a) and part (b) to get the required probabilities.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reaction Time
The concept of reaction time in statistics often refers to a random variable that describes the period it takes for a certain event or process to respond to a stimulus. In our exercise, the reaction time, denoted by \(X\), varies from 0 to 1 seconds. This means we are considering very rapid reactions, typical of many chemical processes or physiological responses. Understanding reaction time in probability requires analyzing how it relates to other variables through a joint probability density function (pdf). By examining this, we can calculate the likelihood of reaction times occurring within a specific range, which involves integrating over intervals of interest. This approach allows us to model and predict reaction behaviors under different conditions.
Temperature Variable
The temperature variable in this scenario is denoted by \(Y\) and takes values between 0 and 1 degrees Fahrenheit, although these units seem atypical given the traditional scale. It's important to remember that temperature can significantly influence reaction rates in chemical and physical processes. The joint probability density function given in the example helps us understand the interrelationship between reaction time and temperature. Specifically, how often certain reaction times coincide with specific temperature ranges. By exploring these temperature variables through probability calculations, researchers and students alike can gain insights into optimal conditions for various reactions.
Probability Calculation
Probability calculation for joint variables involves determining the chance that both variables fall within specified ranges. For instance, part (a) of the exercise requires calculating \(P\left(0 \leq X \leq \frac{1}{2}, \frac{1}{4} \leq Y \leq \frac{1}{2}\right) \). This is done using double integration of the joint pdf across these specified bounds, providing a cumulative measure within this rectangle.For part (b), the task is to find \(P(X < Y)\). Here, the probability is calculated over the region where the reaction time is less than the temperature. This involves evaluating the integral where the first variable, reaction time, must be less than the temperature value across the interval. It's a different aspect of probability that requires spatial understanding on a graph of the pdf.
Integral Calculus
Integral calculus is essential for solving problems involving probability density functions like the one in the exercise. An integral can be thought of as the "summation" of infinite small values which calculates area, volume, or other cumulative measures. In probability, integrals help us sum up areas under the density curve to find probabilities.We apply double integrals when dealing with joint probability density functions, such as \(f(x, y) = 4xy\). In part (a), we perform successive integrations: first with respect to \(y\), holding \(x\) constant, and then with respect to \(x\). For part (b), integration occurs over an asymmetric area related to the condition \(X < Y\).This application of integral calculus allows us to transform a multi-variable density function into probabilities that describe the likelihood of certain outcomes any given interval.

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Most popular questions from this chapter

A coin is tossed twice. Let \(Z\) denote the number of heads on the first toss and \(W\) the total number of heads on the 2 tosses. If the coin is unbalanced and a head has a \(40 \%\) chance of occurring, find (a) the joint probability distribution of \(W\) and \(Z\); (b) the marginal distribution of \(W\); (c) the marginal distribution of \(Z\); (d) the probability that at least 1 head occurs.

The proportion of people who respond to a certain mail-order solicitation is a continuous random variable \(X\) that has the density function $$ f(x)=\left\\{\begin{array}{ll} \frac{2(x+2)}{5}, & 0 < x < 1, \\ 0, & \text { elsewhere .} \end{array}\right. $$ (a) Show that \(\mathrm{P}(0 < X < 1)=1\). (b) Find the probability that more than \(1 / 4\) but fewer than \(1 / 2\) of the people contacted will respond to this type of solicitation.

The time \(Z\) in minutes between calls to an electrical supply system has the probability density function $$ f(z)=\left\\{\begin{array}{ll} \frac{1}{10} e^{-z / 10}, & 0 < z< oo, \\ 0, & \text { elsewhere. } \end{array}\right. $$ (a) What is the probability that there are no calls within a 20 -minute time interval? (b) What is the probability that the first call comes within 10 minutes of opening?

The joint density function of the random variables \(X\) and \(Y\) is $$ f(x, y)=\left\\{\begin{array}{ll} 6 x, & 0< x < 1,0 < y < 1-x, \\ 0, & \text { elsewhere. } \end{array}\right. $$ (a) Show that \(X\) and \(Y\) are not independent. (b) Find \(P(X>0.3 \quad Y=0.5)\).

The behavior of series of components play a huge role in scientific and engineering reliability problems. The reliability of the entire system is certainly no better than the weakest component in the series. In a series system, the components operate independently of each other. In a particular system containing three components the probability of meeting specification for components \(1,2,\) and \(3,\) respectively, are \(0.95,0.99,\) and 0.92. What is the probability that the entire system works?

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