/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 82 A manufacturer of a flu vaccine ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A manufacturer of a flu vaccine is concerned about the quality of its flu serum. Batches of serum are processed by three different departments having rejection rates of \(0.10,0.08,\) and \(0.12,\) respectively. The inspections by the three departments are sequential and independent. (a) What is the probability that a batch of serum survives the first departmental inspection but is rejected by the second department? (b) What is the probability that a batch of serum is rejected by the third department?

Short Answer

Expert verified
(a) The probability that a batch of serum survives the first departmental inspection but is rejected by the second department is 0.072. (b) The probability that a batch of serum is rejected by the third department is 0.09984.

Step by step solution

01

Calculate Probability of surviving first inspection

The probability that a batch of serum survives the first departmental inspection is \(1-0.10 = 0.90\) because the rejection rate is \(0.10\) and hence, surviving rate would be \(1-0.10\).
02

Calculate Probability of getting rejected in second inspection

The probability that the batch is rejected at the second department right after surviving the first department is the product of the probability of it surviving the first department and the rejection rate at the second department. So, it is given by \(0.90*0.08 = 0.072\).
03

Calculate Probability of getting rejected in the third inspection

The probability that a batch is rejected by the third department is given by: the product of the probability that it survives the first and second (which is \(1-0.08 = 0.92\), using the same logic as the first step), and the rejection rate at the third department. So, this would be \(0.90*0.92*0.12 = 0.09984.\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conditional Probability
Understanding conditional probability is crucial when dealing with scenarios where one event's outcome affects the likelihood of another. In the exercise provided, the survival of a flu vaccine batch through the successive departmental inspections is a classic example of conditional probability at play.

To reiterate, conditional probability assesses the chance of an event happening, given that another event has already occurred. For instance, the question posed in the exercise, about the batch getting rejected by the second department after passing the first, requires us to calculate the probability conditioned on the initial success at the first checkpoint.

Students often confuse this concept with mere multiplication of probabilities, but it's important to realize that the key lies in the understanding that the second event's probability is contingent on the first event's outcome. In our case, the survival through the first step is required before we even consider the second step's rejection probability. This sequential dependency is what defines conditional probability.
Independent Events
When we say events are independent, we mean that the occurrence of one event does not influence the probability of the other event occurring. The exercise presents us with inspections at three departments, and it's specified that these inspections are independent.

This independence is essential because it allows us to calculate probabilities of sequential steps simply by multiplying their individual probabilities. For instance, the probability of passing the first inspection is not affected by the probability of passing the second or third inspection. They occur independently of each other.

As an improvement advice, remember that independence is a powerful assumption as it simplifies our calculations significantly. It negates the need for more complex probability theories that are necessary when events are interdependent. Always check whether events are truly independent before applying the rule of product in probability calculations.
Probability Calculation
The core mechanic of probability calculation is understanding and applying the right methods to evaluate the likelihood of events. The exercise demonstrates a scenario where both the concepts of conditional probability and independent events work hand in hand to calculate the overall probability of a batch of flu vaccine being rejected.

We start by calculating the probability of surviving individual inspections (essentially 1 minus the rejection rate). Then, because the inspections are independent, we multiply these probabilities sequentially to find the chances of a batch surviving up to a certain point or being rejected at a particular step.

It is important for students to not just memorize formulas but to grasp why we multiply these probabilities. For independent events, the compound probability is the product of their individual probabilities because each event occurs without influence from the others. This straight-forward approach allows one to determine the long-term likelihood of outcomes, which is a staple skill in fields like quality control, risk assessment, and even gambling.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Prove that \(P\left(A^{\prime} \mathrm{n} B^{\prime}\right)=1+P\\{A \cap B)-P(A)-P\\{B)\)

One overnight case contains 2 bottles of aspirin and 3 bottles of thyroid tablets. A second tote bag contains 3 bottles of aspirin, 2 bottles of thyroid tablets, and I bottle of laxative tablets. If 1 bottle of tablets is taken at random from each piece of luggage, find the probability that (a) both bottles contain thyroid tablets: (b) neither bottle contains thyroid tablets; (c) the 2 bottles contain different tablets.

A witness to a hit-and-run accident told the police that the license number contained the letters RLH followed by 3 digits, the first of which is a 5 . If the witness cannot recall the last 2 digits, but is certain that all 3 digits are different, find the maximum number of automobile registrations that the police may have to check

In how many ways can 5 starting positions on a basketball team be filled with 8 men who can play any of the positions?

As the situation of Exercise 2.73 might suggest, statistical procedures are often used for control of quality (i.e., industrial quality control). At times, the weight of a product is an important variable to control. Specifications are given for the weight, of a certain packaged product and a package is rejected if it is either too light or too heavy. Historical data suggest that 0.95 is the probability that the product meets weight specifications whereas 0.002 is the probability that the product is too light. For each single packaged product the manufacturer invests \(\$ 20.00\) in production and the purchase price by the consumer is \(\$ 25.00\). (a) What is the probability that a package chosen randomly from the production line it too heavy?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.