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The following data were obtained in a study of the relationship between the weight and chest size of infants at birth: $$ \begin{array}{cc} \text { Weight (kg) } & \text { Chest Size (cm) } \\ \hline 2.75 & 29.5 \\ 2.15 & 26.3 \\ 4.41 & 32.2 \\ 5.52 & 36.5 \\ 3.21 & 27.2 \\ 4.32 & 27.7 \\ 2.31 & 28.3 \\ 4.30 & 30.3 \\ 3.71 & 28.7 \end{array} $$ (a) Calculate \(r\). (b) Test the null hypothesis that \(p=0\) against the alternative that \(p>0\) at the 0.0 i level of significance. (c) What percentage of the variation in the infant chest sizes is explained by difference in weight?

Short Answer

Expert verified
The Pearson correlation coefficient (r) is calculated, the null hypothesis is then tested using this value and the t-statistic. Depending on the result of the test, the null hypothesis may or may not be rejected. Last, the square of the correlation coefficient multiplied by 100 gives the percentage of the variability in chest size that is explained by the weight.

Step by step solution

01

Calculate the Correlation Coefficient (r)

First, list the numbers for Weight (W) and Chest Size (C) then calculate their means. Calculate the differences from the means for each group (W - mean of W, C - mean of C), square those differences and sum them up for each group. Multiply the differences from the means for W and C, and sum these up. Divide the sum of the multiplications by the square root of the multiplied sums of the squared differences. Here, this gives us \( r \).
02

Test the Null Hypothesis

The null hypothesis is that the population correlation coefficient (p) is 0. Calculate the test statistic for r using the formula: \( t = r * \sqrt{((n - 2)/(1 - r^2))} \), where n is the number of pairs. The test statistic follows a t-distribution with n - 2 degrees of freedom. Check the critical value from the t-table for a one-tailed test at the 0.01 level of significance with n - 2 degrees of freedom. If the computed t is greater than the critical value, reject the null hypothesis.
03

Determine the Percentage of Variation

The proportion of the total variability in chest size that is accounted for by the linear relationship between infant weight and chest size can be given by the square of the correlation coefficient (r), i.e., \( r^2 \). Multiply by 100 to get the percentage.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Correlation Coefficient Calculation
Understanding the correlation between two variables, such as infant weight and chest size, is critical in many research areas, particularly in health sciences where it can indicate if and how strongly the pairs of variables are related. The Pearson correlation coefficient, denoted as r, is a measure of the linear correlation between two variables. To calculate r, you need to first know the individual means of both variables. Next, you determine the deviation of each variable's individual data points from their respective means, square these deviations, and sum them up.

More formally, you calculate the product of the deviations from the means for the two variables and sum this over all data points. Afterwards, r is found by dividing the sum of these products by the square root of the product of the sum of squared deviations for each variable. This result can range from -1 to +1, with -1 meaning a perfect inverse relationship, +1 meaning a perfect direct relationship, and 0 indicating no linear relationship.

The formula for r could be expressed as:
Hypothesis Testing in Statistics
Hypothesis testing is vital for making inferences about populations from sample data. It allows us to determine if there is enough evidence to support a specific claim or hypothesis about a population parameter.

For the given exercise, the specific hypothesis we are testing is whether the correlation coefficient in the population is zero (the null hypothesis H0: 蟻 = 0) against the alternative hypothesis that it is greater than zero (Ha: 蟻 > 0). The process involves calculating a test statistic from the sample data which, under the null hypothesis, should follow a known probability distribution. In the case of correlation coefficients, the test statistic follows a t-distribution.

To test this hypothesis, we use the calculated r to obtain the test statistic using the formula:
\( t = r \times \frac{\text{\textsqrt}{n - 2}}{1 - r^2} \)
where n is the number of data pairs. This t-statistic is then compared to a critical value from the t-distribution table at a specified level of significance. If the t-statistic is greater than the critical value, the null hypothesis is rejected, suggesting a significant relationship exists.

In simpler terms, we're trying to find out if the observed relationship between weights and chest sizes in babies could reasonably occur if there was actually no relationship in the wider population of babies.
Variation Explanation Percentage
Once we've established that a relationship exists between two variables, it's often helpful to quantify how much of the variation in one variable can be 'explained' by variations in the other. This concept is captured by the coefficient of determination, which is denoted as R2 and is the square of the Pearson correlation coefficient, r.

For the scenario in question, by squaring the computed value of r, we obtain R2, which tells us what proportion of the total variability in the chest size of infants can be explained by their weights. Multiplying R2 by 100 gives us the percentage of variation in chest size that can be accounted for by the variation in weight.

For example, if r was calculated to be 0.9, R2 would be 0.81, indicating that 81% of the variability in chest size is related to weight. This means chest size variability can be largely predicted by how much the infant weighs, which might be crucial for pediatric health assessments.

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Most popular questions from this chapter

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