/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 91 A rock specimen from a particula... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A rock specimen from a particular area is randomly selected and weighed two different times. Let \(W\) denote the actual weight and \(X_{1}\) and \(X_{2}\) the two measured weights. Then \(X_{1}=\) \(W+E_{1}\) and \(X_{2}=W+E_{2}\), where \(E_{1}\) and \(E_{2}\) are the two measurement errors. Suppose that the \(E_{i} \mathrm{~s}\) are independent of one another and of \(W\) and that \(V\left(E_{1}\right)=V\left(E_{2}\right)=\sigma_{E^{2}}^{2}\). a. Express \(\rho\), the correlation coefficient between the two measured weights \(X_{1}\) and \(X_{2}\), in terms of \(\sigma_{W}^{2}\), the variance of actual weight, and \(\sigma_{X}^{2}\), the variance of measured weight. b. Compute \(\rho\) when \(\sigma_{W}=1 \mathrm{~kg}\) and \(\sigma_{E}=.01 \mathrm{~kg}\).

Short Answer

Expert verified
The correlation coefficient \( \rho \approx 0.9999 \).

Step by step solution

01

Understand the formula for correlation coefficient

The correlation coefficient \( \rho \) between two variables \( X_1 \) and \( X_2 \) is given by \( \rho = \frac{\text{cov}(X_1, X_2)}{\sigma_{X_1} \sigma_{X_2}} \), where \( \text{cov}(X_1, X_2) \) is the covariance between \( X_1 \) and \( X_2 \), and \( \sigma_{X_1} \) and \( \sigma_{X_2} \) are the standard deviations of \( X_1 \) and \( X_2 \), respectively. For this problem, since \( X_1 \) and \( X_2 \) arise from identical processes, we can focus on expressing these terms in terms of given variances.
02

Determine expressions for variance and covariance

Using the problem's definitions, we have \( X_1 = W + E_1 \) and \( X_2 = W + E_2 \). This implies \( \text{var}(X_1) = \sigma_W^2 + \sigma_E^2 \) and \( \text{var}(X_2) = \sigma_W^2 + \sigma_E^2 \). The covariance \( \text{cov}(X_1, X_2) \) is \( \text{cov}(W + E_1, W + E_2) = \text{var}(W) = \sigma_W^2 \) because the errors are independent of each other and of \( W \).
03

Substitute into the correlation coefficient formula

Substitute the variance and covariance expressions into the correlation coefficient formula: \[ \rho = \frac{\sigma_W^2}{\sqrt{(\sigma_W^2 + \sigma_E^2)(\sigma_W^2 + \sigma_E^2)}} = \frac{\sigma_W^2}{\sigma_W^2 + \sigma_E^2} \]. Simplified further, this gives us the correlation coefficient expression which depends solely on the given variances.
04

Calculate \( \rho \) for given values

Given \( \sigma_W = 1 \) kg and \( \sigma_E = 0.01 \) kg, square these values to get \( \sigma_W^2 = 1^2 = 1 \) and \( \sigma_E^2 = 0.01^2 = 0.0001 \). Substitute these into the expression for \( \rho \): \[ \rho = \frac{1}{1 + 0.0001} = \frac{1}{1.0001} \approx 0.9999 \].

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Measurement Errors
In experiments and observations, measurement errors can occur naturally. When weighing the same rock specimen, as in the exercise, there's a chance that the scale readings aren't exactly the same each time they're taken. These differences are what we refer to as "measurement errors".
Measurement errors can arise due to several reasons:
  • Instruments used for measuring may have mechanical imperfections.
  • Environmental conditions might affect the measurement, such as temperature or humidity.
  • Human error when reading the measurements can also be a factor.
In the context of the given problem, the errors are denoted as \( E_1 \) and \( E_2 \). It's important to note that these errors are assumed to be independent of each other and of the true weight \( W \). This means that they don't influence each other's values and they are not related to the actual weight being measured. Such assumptions are used to simplify the analysis and to allow us to focus on the statistical properties related to our measurements.
Variance
Variance is a key statistical concept that measures how much a set of data points differ from their mean value. It provides insight into the "spread" or "dispersion" of the data.
In the context of this exercise, variance plays a crucial role. We have:
  • \( \sigma_W^2 \) which represents the variance of the actual weight \( W \).
  • \( \sigma_E^2 \) which is the variance of the measurement errors \( E_1 \) or \( E_2 \).
Variance is calculated using the formula:\[ V(X) = \frac{1}{n} \sum (x_i - \bar{x})^2 \]where \( x_i \) are the individual data points and \( \bar{x} \) is the mean. This formula helps us comprehend how scattered our measured values are from what we assume to be the actual value.
Understanding variance is crucial for solving the exercise, as we learn that the total variance of the measured weight, \( \text{var}(X_1) \) and \( \text{var}(X_2) \), includes contributions from both the true variance of \( W \) and the error variance \( \sigma_E^2 \).
Covariance
Covariance is a measure that shows the extent to which two variables change together. If the variables tend to increase and decrease simultaneously, the covariance is positive. On the other hand, if one tends to increase when the other decreases, the covariance is negative.
Covariance can be calculated using the formula:\[ \text{cov}(X, Y) = \frac{1}{n} \sum (x_i - \bar{x})(y_i - \bar{y}) \]In this exercise, the covariance between the two measured weights \( X_1 \) and \( X_2 \) is calculated as \( \sigma_W^2 \), which implies that only the variance of the true weight \( W \) contributes to how these measurements change in relation to each other.
The assumption that \( E_1 \) and \( E_2 \) are independent of each other as well as from \( W \), simplifies the covariance to just being the variance of \( W \), as the errors do not have a joint effect on \( X_1 \) and \( X_2 \).
Standard Deviation
Standard deviation is a statistical measure that represents the dispersion or spread of a set of data points. It is the square root of the variance and provides a way to understand the average distance between each data point from the mean.
It's denoted as \( \sigma \) and is easier to interpret than variance, as it has the same unit as the data points. For example, if we consider weight measured in kilograms, standard deviation would also be in kilograms.
  • In the exercise, \( \sigma_{X_1} \) and \( \sigma_{X_2} \) represent the standard deviations of the measured weights \( X_1 \) and \( X_2 \).
  • \( \sigma_E \) is the standard deviation of the measurement errors.
Standard deviation is crucial for understanding the variability in our data and plays a key role in calculating the correlation coefficient. When calculating the correlation coefficient \( \rho \), it normalizes the covariance by dividing it by the product of the standard deviations \( \sigma_{X_1} \) and \( \sigma_{X_2} \), thus providing a dimensionless measure of the relationship between the two variables.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A surveyor wishes to lay out a square region with each side having length \(L\). However, because of measurement error, he instead lays out a rectangle in which the north-south sides both have length \(X\) and the east-west sides both have length \(Y\). Suppose that \(X\) and \(Y\) are independent and that each is uniformly distributed on the interval \([L-A, L+A]\) (where \(0

Five automobiles of the same type are to be driven on a 300-mile trip. The first two will use an economy brand of gasoline, and the other three will use a name brand. Let \(X_{1}, X_{2}\), \(X_{3}, X_{4}\), and \(X_{5}\) be the observed fuel efficiencies (mpg) for the five cars. Suppose these variables are independent and normally distributed with \(\mu_{1}=\mu_{2}=20, \mu_{3}=\mu_{4}=\mu_{5}=21\), and \(\sigma^{2}=4\) for the economy brand and \(3.5\) for the name brand. Define an rv \(Y\) by $$ Y=\frac{X_{1}+X_{2}}{2}-\frac{X_{3}+X_{4}+X_{5}}{3} $$ so that \(Y\) is a measure of the difference in efficiency between economy gas and name-brand gas. Compute \(P(0 \leq Y)\) and \(P(-1 \leq Y \leq 1) .\left[\right.\)

The mean weight of luggage checked by a randomly selected tourist-class passenger flying between two cities on a certain airline is \(40 \mathrm{lb}\), and the standard deviation is \(10 \mathrm{lb}\). The mean and standard deviation for a business-class passenger are \(30 \mathrm{lb}\) and \(6 \mathrm{lb}\), respectively. a. If there are 12 business-class passengers and 50 touristclass passengers on a particular flight, what are the expected value of total luggage weight and the standard deviation of total luggage weight? b. If individual luggage weights are independent, normally distributed rv's, what is the probability that total luggage weight is at most \(2500 \mathrm{lb}\) ?

The lifetime of a certain type of battery is normally distributed with mean value 10 hours and standard deviation 1 hour. There are four batteries in a package. What lifetime value is such that the total lifetime of all batteries in a package exceeds that value for only \(5 \%\) of all packages?

Each front tire on a particular type of vehicle is supposed to be filled to a pressure of 26 psi. Suppose the actual air pressure in each tire is a random variable- \(X\) for the right tire and \(Y\) for the left tire, with joint pdf $$ f(x, y)=\left\\{\begin{array}{cl} K\left(x^{2}+y^{2}\right) & 20 \leq x \leq 30,20 \leq y \leq 30 \\ 0 & \text { otherwise } \end{array}\right. $$ a. What is the value of \(K\) ? b. What is the probability that both tires are underfilled? c. What is the probability that the difference in air pressure between the two tires is at most 2 psi? d. Determine the (marginal) distribution of air pressure in the right tire alone. e. Are \(X\) and \(Y\) independent rv's?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.