/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 86 The number of people arriving fo... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The number of people arriving for treatment at an emergency room can be modeled by a Poisson process with a rate parameter of five per hour. a. What is the probability that exactly four arrivals occur during a particular hour? b. What is the probability that at least four people arrive during a particular hour? c. How many people do you expect to arrive during a 45 min period?

Short Answer

Expert verified
(a) ≈ 0.1755, (b) ≈ 0.735, (c) 3.75 people

Step by step solution

01

Identify the Poisson Probability Formula

The formula for Poisson probability is \( P(X = k) = \frac{{e^{- ext{λ}} ext{λ}^k}}{{k!}} \), where \( \text{λ} \) is the average rate of occurrence (5 per hour), \( k \) is the exact number of events, \( e \) is approximately 2.71828, and \( k! \) is the factorial of \( k \).
02

Calculate Probability for Exactly Four Arrivals (Part a)

Use \( \text{λ} = 5 \), and \( k = 4 \) in the Poisson formula: \[ P(X = 4) = \frac{{e^{-5} imes 5^4}}{{4!}} \] Calculate \( 5^4 = 625 \) and \( 4! = 24 \). Thus, \( e^{-5} \approx 0.0067 \) and the probability becomes:\[ P(X = 4) = \frac{{0.0067 \times 625}}{{24}} \approx 0.1755 \]
03

Determine Probability for At Least Four Arrivals (Part b)

The probability of at least four arrivals is the sum of probabilities of having four or more arrivals:\[ P(X \geq 4) = 1 - P(X < 4) \] Where \( P(X < 4) \) includes \( P(X = 0, 1, 2, 3) \). Calculate each using the Poisson formula, sum them, and subtract from 1:
04

Step 3.1: Calculate P(X < 4)

Compute for each: \[ P(X = 0) = \frac{{e^{-5} \times 5^0}}{{0!}} = 0.0067 \] \[ P(X = 1) = \frac{{e^{-5} \times 5^1}}{{1!}} = 0.0337 \] \[ P(X = 2) = \frac{{e^{-5} \times 5^2}}{{2!}} = 0.0842 \] \[ P(X = 3) = \frac{{e^{-5} \times 5^3}}{{3!}} = 0.1404 \] Add these: \( 0.0067 + 0.0337 + 0.0842 + 0.1404 \approx 0.265 \).
05

Step 3.2: Subtract from 1 for P(X ≥ 4)

Subtract the result from Step 3.1 from 1:\[ P(X \geq 4) = 1 - 0.265 = 0.735 \]
06

Determine Expected Arrivals in 45 Minutes (Part c)

Since the rate \( \text{λ} = 5 \) per hour, for 45 minutes (i.e., \( \frac{3}{4} \) of an hour), use:\[ \text{Expected Arrivals} = \text{λ} \times \frac{3}{4} = 5 \times 0.75 = 3.75 \]
07

Conclusion

The answers to the problems are: (a) Probability for exactly four arrivals is approximately \(0.1755\), (b) Probability for at least four arrivals is approximately \(0.735\), (c) Expected number of arrivals in 45 minutes is \(3.75\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Calculation
Calculating probability in the context of a Poisson process can be particularly insightful. A Poisson process generally helps in modeling events that occur randomly over a fixed period of time. If you want to find the probability of a specific number of events happening, you apply the Poisson probability formula. The probability that exactly \( k \) events occur in a time period is given by:\[P(X = k) = \frac{e^{-\lambda} \lambda^k}{k!}\]- **\( \lambda \)** is the rate parameter, which denotes the average number of occurrences in the given interval.- **\( e \)** is Euler’s number, approximately equal to 2.71828.- **\( k! \)** signifies the factorial of \( k \), indicating that every positive integer up to \( k \) is multiplied together.Through this formula, you can assess how likely it is to have exactly four arrivals in one hour in an emergency room modeled by this process.
Rate Parameter
The rate parameter \( \lambda \) plays a crucial role in determining the likelihood of events in a Poisson distribution. Essentially, it provides the average rate of occurrences over a designated interval.- In real-world applications like the emergency room arrival model, \( \lambda = 5 \) conveys an average of 5 arrivals per hour. This parameter determines how frequently an event happens.When calculating probabilities for different time intervals, you might need to adjust \( \lambda \) to fit the period of interest. For example, if you're calculating over 45 minutes, multiply \( \lambda \) by \( 0.75 \) (since 45 minutes is \( 3/4 \) of an hour) to find the expected number of arrivals.
Factorial Calculation
Factorial calculation is central to the Poisson probability formula. For a given number \( k \), the factorial \( k! \) means multiplying all integers from 1 up to \( k \). It is denoted as:\[ k! = k \times (k-1) \times (k-2) \times \ldots \times 1 \]Here are a few quick considerations:- Factorial of zero \( (0!) \) is defined to be 1, an important concept for mathematical consistency.- For \( k = 4 \), \( 4! \) equals \( 24 \), calculated as \( 4 \times 3 \times 2 \times 1 = 24 \).Using factorials ensures that you leverage the correct weight for each probability calculation in a discrete distribution, capturing the unique differences among event counts.
Expected Value
Expected value is an important concept that helps us understand the average outcome expected over numerous trials of an event or experiment, particularly in stochastic or probabilistic settings.In the context of a Poisson process:- The expected value is exactly \( \lambda \), which means if you observe the process arrival rate \( \lambda \), that is the anticipated average count of events per interval.- For a 1-hour interval with \( \lambda = 5 \), the expected number of arrivals at the emergency room is 5. - If the time frame changes, such as calculating the expected arrivals over 45 minutes, you simply adjust by multiplying the fraction of the hour \((0.75)\), resulting in an expected arrival number of \( 3.75 \).Expected value provides a meaningful average-based summary of potential outcomes, integral in planning and resource allocation.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A friend recently planned a camping trip. He had two flashlights, one that required a single 6-V battery and another that used two size-D batteries. He had previously packed two 6-V and four size-D batteries in his camper. Suppose the probability that any particular battery works is \(p\) and that batteries work or fail independently of one another. Our friend wants to take just one flashlight. For what values of \(p\) should he take the 6-V flashlight?

Twenty percent of all telephones of a certain type are submitted for service while under warranty. Of these, \(60 \%\) can be repaired, whereas the other \(40 \%\) must be replaced with new units. If a company purchases ten of these telephones, what is the probability that exactly two will end up being replaced under warranty?

A particular type of tennis racket comes in a midsize version and an oversize version. Sixty percent of all customers at a certain store want the oversize version. a. Among ten randomly selected customers who want this type of racket, what is the probability that at least six want the oversize version? b. Among ten randomly selected customers, what is the probability that the number who want the oversize version is within 1 standard deviation of the mean value? c. The store currently has seven rackets of each version. What is the probability that all of the next ten customers who want this racket can get the version they want from current stock?

Give three examples of Bernoulli rv's (other than those in the text).

The negative binomial rv \(X\) was defined as the number of \(F\) 's preceding the \(r\) th \(S\). Let \(Y=\) the number of trials necessary to obtain the \(r\) th \(S\). In the same manner in which the pmf of \(X\) was derived, derive the pmf of \(Y\).

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.