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Suppose that \(p=P\) (male birth \()=.5\). A couple wishes to have exactly two female children in their family. They will have children until this condition is fulfilled. a. What is the probability that the family has \(x\) male children? b. What is the probability that the family has four children? c. What is the probability that the family has at most four children? d. How many male children would you expect this family to have? How many children would you expect this family to have?

Short Answer

Expert verified
a. \( P(X = x) = (x+1) (0.5)^{x+2} \). b. 0.1875 c. 0.6875 d. 2 male children, 4 total children.

Step by step solution

01

Identify the Problem Type

This exercise deals with a special type of probability distribution known as the Negative Binomial Distribution. Specifically, it involves determining the number of male children ("failures") before achieving exactly two female children ("successes").
02

Define the Variables

Let's denote the probability of a child being female (success) as \( p = 0.5 \) and the number of female children desired as \( r = 2 \). Thus, the probability of a child being male (failure) is also \( q = 1 - p = 0.5 \).
03

Calculate the Probability of Having x Male Children (Part a)

The random variable \( X \) represents the number of male children. The probability of having \( x \) male children before having 2 female children is given by the Negative Binomial probability formula: \( P(X = x) = \binom{x+r-1}{r-1} p^r q^x = \binom{x+1}{1} (0.5)^2 (0.5)^x \). Simplifying, \( P(X = x) = (x+1) (0.5)^{x+2} \).
04

Calculate the Probability of Four Children Total (Part b)

For the family to have four total children, they must have 2 female and 2 male children. We use the result from part a for \( x = 2 \): \( P(X = 2) = (2+1) (0.5)^4 = 3 \times 0.0625 = 0.1875 \).
05

Calculate Probability of At Most Four Children (Part c)

We sum the probabilities of having up to four children (two female and up to two male): \( P(X \leq 2) = P(X=0) + P(X=1) + P(X=2) \). Calculate each: \( P(0) = (1)(0.5)^2 = 0.25 \), \( P(1) = (2)(0.5)^3 = 0.25 \), \( P(2) = 0.1875 \). Thus, \( P(X \leq 2) = 0.25 + 0.25 + 0.1875 = 0.6875 \).
06

Calculate Expected Number of Male Children (Part d)

The expected number of male children in a Negative Binomial distribution with \( r=2 \) and \( p=0.5 \) is \( \frac{rq}{p} = \frac{2 \times 0.5}{0.5} = 2 \).
07

Calculate Expected Total Number of Children

The expected total number of children is the expected number of male and female children together, \( r + \frac{rq}{p} = 2 + 2 = 4 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Theory
Probability Theory helps us understand and analyze different random events in our daily lives. It's like a tool that lets us measure uncertainty and make predictions based on various outcomes. In this exercise, having children is a kind of random event. When we talk about probabilities, we're dealing with the likelihood of particular outcomes, like the chance a couple will have a boy or a girl with each birth. This is important to determine the chances of having a certain number of male children before the birth of a specified number of female children, which ties into our example of planning a family.
Statistics
Statistics involves organizing and interpreting data collected from random events. It helps us make sense of complex data by summarizing it into meaningful information. In this exercise, we use statistics to calculate probabilities and expected values based on the past data of birth rates. Using these statistics, one can make informed guesses about the likelihood of future events, such as the birth order in a family or the total number of children a couple might have. The Negative Binomial Distribution is a statistical model that simplifies decision-making by providing insights from past occurrences.
Expected Value
Expected Value in probability tells us what average result we can anticipate from a random event after many trials. Think of it like a long-term average waiting at the end of a game. In this scenario, if a family continues to have children until they have two daughters, the expected number of male children they will have can be calculated. With the formula \[ \text{Expected male children} = \frac{rq}{p} \] where \( r \) is the number of female children desired, \( q \) is the probability of having a male child, and \( p \) is the probability of having a female child, we find that the expected number of male children before getting two female children is 2.
Probability Distribution
A Probability Distribution shows all the possible outcomes of a random variable and their probabilities. In this exercise, we focus on the Negative Binomial Distribution, which deals with finding the number of failures (male children) before a certain number of successes (female children) happens. The probability formula used is: \[ P(X = x) = \binom{x+r-1}{r-1} p^r q^x \] This allows us to calculate the probability of having a specific number of male children before the desired number of female children is reached. It guides us to know outcomes like the probability of having exactly four children or at most four children in total, providing deep insights through a structured framework of possibilities.

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