/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 105 The purchaser of a power-generat... [FREE SOLUTION] | 91Ó°ÊÓ

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The purchaser of a power-generating unit requires \(c\) consecutive successful start-ups before the unit will be accepted. Assume that the outcomes of individual startups are independent of one another. Let \(p\) denote the probability that any particular start-up is successful. The random variable of interest is \(X=\) the number of start-ups that must be made prior to acceptance. Give the pmf of \(X\) for the case \(c=2\). If \(p=.9\), what is \(P(X \leq 8)\) ? [Hint: For \(x \geq 5\), express \(p(x)\) "recursively" in terms of the pmf evaluated at the smaller values \(x-3, x-4, \ldots, 2\).] (This problem was suggested by the article "Evaluation of a Start-Up Demonstration Test," J. Quality Technology, 1983: \(103-106 .)\)

Short Answer

Expert verified
The pmf uses a geometric distribution with adjustments for consecutive success. For \(p=0.9\), \(P(X \leq 8) \approx 0.387\).

Step by step solution

01

Understanding the PMF

The random variable in question, \(X\), is the number of start-ups attempted until the unit is accepted after 2 consecutive successful start-ups are achieved. This is modeled using a geometric framework where the unit is accepted only after two consecutive successes.
02

Probability Mass Function Using Convolution

For the case \(c = 2\), the probability mass function (pmf) can be determined by realizing that getting two consecutive successes at the \(x\)-th attempt can only happen after a failure at the \((x-2)\)-th attempt and success at the \((x-1)\)-th attempt. Therefore, the pmf is given by \(p(x) = (1-p)p^{x-2}\cdot p^2 = (1-p)p^{x}\) for \(x = 2, 3, \ldots\), where the first \(x-2\) are failures.
03

Calculate P(X ≤ 8)

To calculate \(P(X \leq 8)\), we need the probability that the unit is accepted after at most 8 start-ups. This can be obtained by summing the probabilities from 2 to 8: \[P(X \leq 8) = \sum_{x=2}^{8} (1-p)p^{x}\] Given the probability \(p = 0.9\), the calculation is:\[P(X \leq 8) = (0.1 \cdot 0.9^2 \cdot (1+0.9+ \cdots +0.9^6))\].
04

Perform the Calculation

Calculate the geometric series, knowing \(\sum_{k=0}^{n} r^k = \frac{1-r^{n+1}}{1-r}\) for \(r = 0.9\) and \(n = 6\), which is:\[\sum_{k=0}^{6} 0.9^k = \frac{1 - 0.9^7}{0.1}\].Substitute this sum into the expression:\[P(X \leq 8) = 0.1 \cdot 0.9^2 \cdot \frac{1 - 0.9^7}{0.1} = 0.9^2 \cdot (1 - 0.9^7) = 0.81 \cdot 0.4782969\approx 0.387\].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Geometric Distribution
The geometric distribution is a fascinating probability distribution that models the number of trials required to achieve the first success in a sequence of independent Bernoulli trials. Each trial in a Bernoulli process has exactly two outcomes: success with probability \( p \) and failure with probability \( 1-p \). Hence, the geometric distribution focuses on the idea of waiting until the first success occurs.
In our problem, we have a slight twist. We are asked to consider the situation where two consecutive successes are needed before we accept the power-generating unit. While a typical geometric distribution models waiting for a single success, here, we adapt the concept to calculate the probability of obtaining exactly two successes in a row, or two consecutive successful start-ups. This leads to a variation where the probability mass function (pmf) is derived based on ensuring not just one, but two sequential successes by a certain trial.
Consecutive Successes
Achieving consecutive successes forms the core aspect of this exercise. In probability, consecutive successes refer to obtaining success in multiple trials without any failures intervening. For the case of two consecutive successes, as given by \(c = 2\), it is important to track the last two trials.
  • Firstly, all trials before the last two must end in failure. This means, if you want the last two trials to be successes at the \(x\)-th position, every trial before \(x-2\) must be a failure.
  • Secondly, for a trial at \(x\) to be successful after \(x-1\), \(x-1\) must also be a success.
  • Last and most crucially, the failure at \(x-2\) helps ensure that successes at \(x-1\) and \(x\) are indeed consecutive.
This sequential requirement affects how we calculate the probability mass function (pmf). The likelihood of achieving these two successes becomes the events leading up to it, specifically: the probability of failing repeatedly followed by two successes.
Acceptance Testing
Acceptance testing is a crucial phase in quality assurance processes, particularly when assessing products like a power-generating unit. In this context, acceptance testing involves a criteria, or threshold, that must be fulfilled before a product can be considered reliable. For our problem, the unit is not accepted until it achieves two consecutive successful operational starts.
Acceptance testing can ensure that products do not just perform once, but successfully meet standards consistently. This is reflected in the requirement of consecutive successes—the unit should operate correctly not just once, but display an ability to reliably produce multiple successful start-ups.
When calculating probabilities like \( P(X \leq 8) \), the concept ensures that the unit's reliability is not an anomaly, but a dependable feature demonstrated through several start-up trials. Thus, acceptance testing, with its reliance on statistical measures of success, reinforces quality assurance practices through quantitative validation mechanisms.

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Most popular questions from this chapter

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