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Let \(X\) be the damage incurred (in \$) in a certain type of accident during a given year. Possible \(X\) values are 0,1000 , 5000 , and 10000 , with probabilities .8, .1, .08, and \(.02\), respectively. A particular company offers a \(\$ 500\) deductible policy. If the company wishes its expected profit to be \(\$ 100\), what premium amount should it charge?

Short Answer

Expert verified
Charge a premium of $700.

Step by step solution

01

Define the Problem

We need to determine the premium amount that a company should charge for an insurance policy with a $500 deductible, given certain probabilities for different damage amounts. The company aims for an expected profit of $100.
02

Calculate the Expected Payout

The payout is the difference between the damage and the deductible for damages above $500. The expected payout is given by \(E[P] = \sum (P(X_i) \cdot \max(0, X_i - 500))\). Calculate it for each damage amount X: 0, 1000, 5000, and 10000.
03

Calculate Individual Payout Contributions

1. For \(X = 0\), payout \(= \max(0, 0 - 500) = 0\). Probability is 0.8, so contribution is \(0.8 \times 0 = 0\).2. For \(X = 1000\), payout \(= \max(0, 1000 - 500) = 500\). Contribution is \(0.1 \times 500 = 50\).3. For \(X = 5000\), payout \(= 4500\). Contribution is \(0.08 \times 4500 = 360\).4. For \(X = 10000\), payout \(= 9500\). Contribution is \(0.02 \times 9500 = 190\).
04

Sum the Expected Payouts

Total expected payout is the sum of individual contributions: \(0 + 50 + 360 + 190 = 600\). The expected payout is \($600\).
05

Calculate the Required Premium

To achieve a profit of \($100\), the expected premium must satisfy: \(\text{Expected Premium} - \text{Expected Payout} = 100\). Therefore, \(\text{Expected Premium} = 600 + 100 = 700\).
06

Conclusion

The company should charge a premium of \(\(700\) to achieve the desired expected profit of \(\)100\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Insurance Premium
An insurance premium is the amount charged by an insurer to provide coverage under an insurance policy. This is the cost you pay for being protected against potential risks or losses, such as damage in the event of an accident. Insurance companies calculate premiums based on several factors, including the level of risk they are taking on.
The goal of the insurer is to collect enough in premiums to cover anticipated payouts, administrative costs, and achieve a desired profit. For instance, if the expected payout (claims to be paid to policyholders) is estimated at $600, and the company wants a $100 profit, they will need to charge a total expected premium of $700.

The premium amount is heavily influenced by the probability distribution of loss events, meaning an insurer must carefully estimate the likelihood and extent of damages they will need to cover. This allows them to price their premiums competitively while covering expected costs.
Deductible Policy
A deductible policy involves a specified amount that the insured must pay out-of-pocket before insurance coverage takes effect. In simple terms, it is the portion of a claim that a policyholder must pay before the insurer pays the remaining expenses.

Deductible policies help reduce the cost of insurance by decreasing the likelihood and size of payouts. In the example, the insurance company sets a deductible of $500. This means for any claim that exceeds $500, the insured pays the initial $500, and the insurer provides coverage for the remaining amount.
Having a deductible:
  • Encourages policyholders to prevent small claims or minor damages since they bear part of the cost.
  • Promotes responsible behavior among insured individuals, potentially lowering risks.
For instance, in an accident causing $5,000 of damage, the payout from the insurer would be $5,000 - $500 = $4,500. This setup balances the insured's contribution and the insurer's risk.
Expected Payout
Expected payout is a critical metric in insurance as it signifies the average amount an insurer anticipates paying out for claims on a policy. Rather than being a definite figure, it represents a weighted average calculated using the probabilities of different outcomes and the respective payouts.

We calculate the expected payout by summing the product of each payout's likelihood and its monetary value. For example, consider several possible damages: 0, 1000, 5000, and 10000. The expected payout (E[P]) can be calculated as follows: \[ E[P] = 0.8 \times 0 + 0.1 \times 500 + 0.08 \times 4500 + 0.02 \times 9500 = 600 \]Thus, the expected payout is $600 in this scenario. This figure helps insurance companies set premiums that secure enough revenue to cover potential claims.
Probability Distribution
Probability distribution is a statistical function that illustrates all the possible values and occurrences a random variable can take within a given range. In insurance, it helps in assessing the risk associated with different levels of potential losses.

By understanding the probability distribution of damage amounts, insurers can anticipate expected payouts accurately. This allows them to set only reasonable and profitable premium charges.
In the given scenario, damages and their probabilities are:
  • 0 damage with a probability of 0.8
  • 1000 damage with a probability of 0.1
  • 5000 damage with a probability of 0.08
  • 10000 damage with a probability of 0.02
The weighted nature of a probability distribution takes into account how likely each scenario is to occur. Understanding probability distribution is essential for designing financially sound insurance policies and is a core part of actuarial science.

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Most popular questions from this chapter

Of all customers purchasing automatic garage-door openers, \(75 \%\) purchase a chain-driven model. Let \(X=\) the number among the next 15 purchasers who select the chain-driven model. a. What is the pmf of \(X\) ? b. Compute \(P(X>10)\). c. Compute \(P(6 \leq X \leq 10)\). d. Compute \(\mu\) and \(\sigma^{2}\). e. If the store currently has in stock 10 chaindriven models and 8 shaft- driven models, what is the probability that the requests of these 15 customers can all be met from existing stock?

A \(k\)-out-of-n system is one that will function if and only if at least \(k\) of the \(n\) individual components in the system function. If individual components function independently of one another, each with probability \(.9\), what is the probability that a 3 -out-of-5 system functions?

Customers at a gas station pay with a credit card \((A)\), debit card \((B)\), or cash \((C)\). Assume that successive customers make independent choices, with \(P(A)=.5, P(B)=.2\), and \(P(C)=.3 .\) a. Among the next 100 customers, what are the mean and variance of the number who pay with a debit card? Explain your reasoning. b. Answer part (a) for the number among the 100 who don't pay with cash.

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A contractor is required by a county planning department to submit one, two, three, four, or five forms (depending on the nature of the project) in applying for a building permit. Let \(Y=\) the number of forms required of the next applicant. The probability that \(y\) forms are required is known to be proportional to \(y\)-that is, \(p(y)=k y\) for \(y=1, \ldots, 5\). a. What is the value of \(k\) ? [Hint: \(\sum_{y=1}^{5} p(y)=1\).] b. What is the probability that at most three forms are required? c. What is the probability that between two and four forms (inclusive) are required? d. Could \(p(y)=y^{2} / 50\) for \(y=1, \ldots, 5\) be the pmf of \(Y\) ?

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