/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 27 An academic department with five... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

An academic department with five faculty membersAnderson, Box, Cox, Cramer, and Fisher-must select two of its members to serve on a personnel review committee. Because the work will be time-consuming, no one is anxious to serve, so it is decided that the representative will be selected by putting five slips of paper in a box, mixing them, and selecting two. a. What is the probability that both Anderson and Box will be selected? [Hint: List the equally likely outcomes.] b. What is the probability that at least one of the two members whose name begins with \(C\) is selected? c. If the five faculty members have taught for \(3,6,7,10\), and 14 years, respectively, at the university, what is the probability that the two chosen representatives have at least 15 years' teaching experience at the university?

Short Answer

Expert verified
a) \(\frac{1}{10}\), b) \(\frac{7}{10}\), c) \(\frac{1}{5}\).

Step by step solution

01

Identify the Total Outcomes

To find the total number of ways to choose two faculty members from five, use the combination formula: \( \binom{5}{2} \). This represents the number of combinations of 5 items taken 2 at a time.
02

Calculate the Total Possible Combinations

Calculate \( \binom{5}{2} = \frac{5 \times 4}{2 \times 1} = 10 \). So, there are 10 possible combinations of two faculties selected from five members.
03

Calculate Probability for Anderson and Box

Consider the very specific event where only Anderson and Box are chosen. There is just one way this can occur. Thus, the probability is \( \frac{1}{10} \), derived from 1 favorable combination out of 10 total combinations.
04

Probability for at Least One Name Beginning with "C"

Faculty names starting with 'C' are Cox and Cramer. We need to find combinations including at least Cox or Cramer. Calculate the complement by considering combinations that contain neither Cox nor Cramer; i.e., selecting from Anderson, Box and Fisher. This is \( \binom{3}{2} = 3 \). Thus, favorable outcomes = total outcomes - unfavorable outcomes = 10 - 3 = 7. Probability is \( \frac{7}{10} \).
05

Calculate Probability for at Least 15 Years Experience

Review each faculty member's years: Anderson (3), Box (6), Cox (7), Cramer (10), Fisher (14). Identify pairs whose combined experience is at least 15 years. The pairs are (Cramer, Fisher) and (Cox, Fisher). Thus, there are 2 favorable combinations. The probability is \( \frac{2}{10} = \frac{1}{5} \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Combination Formula
The combination formula is a mathematical way to determine how many ways you can select a group of items from a larger set, where the order of selection doesn't matter. This concept is frequently used in probability and statistics.

To express the combination formula, you use the symbol \( \binom{n}{r} \), which reads as "n choose r." It calculates the number of ways to choose \(r\) items from a set of \(n\) without regard to the order. The formula itself is:
  • \[ \binom{n}{r} = \frac{n!}{r! \times (n-r)!} \]
Here, "!" denotes a factorial, which is a product of all positive integers up to a specified number. For instance, \(5! = 5 \times 4 \times 3 \times 2 \times 1 = 120\).

In our exercise, by applying \( \binom{5}{2} \), we find there are 10 different ways to choose 2 faculty members out of 5. This lays the groundwork for calculating probability, as it tells us the total number of possible outcomes.
Probability Calculation
Probability calculation is at the heart of determining the likelihood of an event. It is expressed as a ratio of the number of favorable outcomes to the total number of possible outcomes.

The formula for probability is:
  • \[ P(Event) = \frac{\text{Number of Favorable Outcomes}}{\text{Total Number of Possible Outcomes}} \]
Using this, you can compute probabilities for different events, as demonstrated in the exercise.

For instance, the chance both Anderson and Box are selected is determined as one favorable outcome (Anderson and Box) out of the 10 possible combinations. Hence, the probability is \( \frac{1}{10} \).

Similarly for at least one name beginning with "C" being chosen, we initially worked out that there are 3 unfavorable outcomes. Thus, 7 favorable outcomes exist thus giving a probability of \( \frac{7}{10} \). Understanding this step is essential in solving diverse probability-related questions.
Faculty Selection
Faculty selection here refers to the random method of choosing faculty members for a committee. Here, it's done by drawing names randomly, assumed to be unbiased, from a pool of all candidates.

This method is itself an example of a combinatorial problem, where combinations of faculty members are computed using the combination formula. This ensures that each possible pair is equally likely to be selected.

In random selection cases, the aim is to ensure fairness and that each individual has an equal chance of being selected. Careful list-down and methodical calculations help in deriving probabilities and securing that no bias affects the selection.
Years of Experience
In the exercise, years of experience is used to add a more realistic layer to the problem, by associating additional characteristics to each faculty member. Here, each faculty member has a different number of years they’ve taught at the university.

To solve the probability that the selected faculty members have at least 15 years of combined experience, you need to consider only those pairs which achieve this requirement:
  • Cramer and Fisher, whose combined experience is 24 years.
  • Cox and Fisher, with 21 years of combined experience.
These factors make up the favorable outcomes for this specific probability query, with a combined probability of \( \frac{2}{10} = \frac{1}{5} \).

Including factors like experience brings about a practical aspect to combinatorial probability problems, as realistically, selections often consider these dimensions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Let \(A\) denote the event that the next request for assistance from a statistical software consultant relates to the SPSS package, and let \(B\) be the event that the next request is for help with SAS. Suppose that \(P(A)=.30\) and \(P(B)=.50\). a. Why is it not the case that \(P(A)+P(B)=1\) ? b. Calculate \(P\left(A^{\prime}\right)\). c. Calculate \(P(A \cup B)\). d. Calculate \(P\left(A^{\prime} \cap B^{\prime}\right)\).

Seventy percent of all vehicles examined at a certain emissions inspection station pass the inspection. Assuming that successive vehicles pass or fail independently of one another, calculate the following probabilities: a. \(P(\) all of the next three vehicles inspected pass) b. \(P\) (at least one of the next three inspected fails) c. \(P\) (exactly one of the next three inspected passes) d. \(P\) (at most one of the next three vehicles inspected passes) e. Given that at least one of the next three vehicles passes inspection, what is the probability that all three pass (a conditional probability)?

At a certain gas station, \(40 \%\) of the castomers use regular gas \(\left(A_{1}\right), 35 \%\) use plus gas \(\left(A_{2}\right)\), and \(25 \%\) use premium \(\left(A_{3}\right)\). Of those customers using regular gas, only \(30 \%\) fill their tanks (event \(B\) ). Of those customers using plus, \(60 \%\) fill their tanks, whereas of those using premium, \(50 \%\) fill their tanks. a. What is the probability that the next customer will request plus gas and fill the tank \(\left(A_{2} \cap B\right)\) ? b. What is the probability that the next customer fills the tank? c. If the next customer fills the tank, what is the probability that regular gas is requested? Plus? Premium?

A production facility employs 20 workers on the day shift, 15 workers on the swing shift, and 10 workers on the graveyard shift. A quality control consultant is to select 6 of these workers for in-depth interviews. Suppose the selection is made in such a way that any particular group of 6 workers has the same chance of being selected as does any other group (drawing 6 slips without replacement from among 45). a. How many selections result in all 6 workers coming from the day shift? What is the probability that all 6 selected workers will be from the day shift? b. What is the probability that all 6 selected workers will be from the same shift? c. What is the probability that at least two different shifts will be represented among the selected workers? d. What is the probability that at least one of the shifts will be unrepresented in the sample of workers?

An individual is presented with three different glasses of cola, labeled \(C, D\), and \(P\). He is asked to taste all three and then list them in order of preference. Suppose the same cola has actually been put into all three glasses. a. What are the simple events in this ranking experiment, and what probability would you assign to each one? b. What is the probability that \(C\) is ranked first? c. What is the probability that \(C\) is ranked first and \(D\) is ranked last?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.