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The accompanying observations on stabilized viscosity (cP) for specimens of a certain grade of asphalt with \(18 \%\) rubber added are from the article "Viscosity Characteristics of Rubber-Modified Asphalts" (J. of Materials in Civil Engr., 1996: 153-156): \(\begin{array}{lllll}2781 & 2900 & 3013 & 2856 & 2888\end{array}\) a. What are the values of the sample mean and sample median? b. Calculate the sample variance using the computational formula.

Short Answer

Expert verified
The sample mean is 2887.6, the median is 2888, and the variance is 76915.8 cP².

Step by step solution

01

Calculating the Sample Mean

The sample mean is calculated using the formula:\[ \bar{x} = \frac{1}{n} \sum_{i=1}^{n} x_i \]where \(n\) is the number of observations and \(x_i\) are the sample values.For the given data, we have:\[ \bar{x} = \frac{1}{5} (2781 + 2900 + 3013 + 2856 + 2888) \]\[ \bar{x} = \frac{1}{5} \times 14438 = 2887.6 \]
02

Calculating the Sample Median

To find the median, the data must be sorted in ascending order: 2781, 2856, 2888, 2900, 3013. The median is the middle value. Since there are 5 observations, the median is the third value. Thus, the median is 2888.
03

Calculating the Sample Variance - Computational Formula

The computational formula for variance is:\[ s^2 = \frac{1}{n-1} \left(\sum_{i=1}^{n} x_i^2 - \frac{(\sum_{i=1}^{n} x_i)^2}{n}\right) \]First, calculate \(\sum_{i=1}^{n} x_i^2\):\[ \sum_{i=1}^{5} x_i^2 = 2781^2 + 2900^2 + 3013^2 + 2856^2 + 2888^2 = 40296341 \]Substitute the values in the formula:\[ s^2 = \frac{1}{4} \left( 40296341 - \frac{14438^2}{5} \right) \]\[ s^2 = \frac{1}{4} \left( 40296341 - 41608404.8 \right) \]\[ s^2 = \frac{1}{4} \times 307663.2 = 76915.8 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Asphalt Viscosity Analysis
Asphalt viscosity analysis is crucial in evaluating the performance characteristics of asphalt, especially when modified with additives such as rubber. Viscosity refers to a fluid's resistance to flow. A higher viscosity means the fluid is thicker and flows less easily. In pavement engineering, ensuring the right viscosity can help maintain the integrity and longevity of a road surface.
Adding rubber to asphalt can affect its viscosity, potentially enhancing the material's durability and flexibility. This is particularly important in varying weather conditions where the pavement might contract or expand. Understanding how additives alter viscosity allows engineers to select appropriate materials for specific environments.
In our specific analysis, viscosity observations for asphalt samples with 18% rubber were recorded. The values are as follows: 2781, 2900, 3013, 2856, 2888. These measurements are used to derive statistical insights such as mean, median, and variance, helping researchers understand how consistent the viscosity characteristics are across different asphalt samples.
Sample Median Calculation
Sample median calculation is a straightforward statistical method used to determine the middle value of an ordered data set. For the asphalt viscosity data provided, sorting is the first step: 2781, 2856, 2888, 2900, 3013.
Once ordered, locating the median is simple since there is an odd number of values in our data set. The median is the third value. This method is especially useful when the dataset might have outliers, as the median can provide a better central measure than the mean. In our example, despite variances in the values, the median gives us a clear indication of the central tendency, which is 2888 cP.
The practical significance of finding the median in asphalt viscosity analysis is that it shows a typical value around which other measurements cluster, giving a tangible understanding of expected performance.
Computational Formula for Variance
The computational formula for variance is essential to quantify the spread or dispersion of a data set. Variance helps us understand the variability of viscosity measurements in asphalt samples. A higher variance indicates that the data points are spread out over a wider range of values, which can be critical in quality control processes. The formula used here is\[ s^2 = \frac{1}{n-1} \left(\sum_{i=1}^{n} x_i^2 - \frac{(\sum_{i=1}^{n} x_i)^2}{n}\right)\] where \(s^2\) represents the sample variance, \(n\) is the number of observations, and \(x_i\) are the sample values. For asphalt viscosity values of 2781, 2900, 3013, 2856, and 2888, we calculated \(s^2\) to be 76915.8. This detailed breakdown helps in understanding how each observation compares with the mean, guiding quality assessments and aiding in decision-making for material usage.
Such analyses are pivotal when comparing multiple batches or determining the impact of various additives on material performance.

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Most popular questions from this chapter

The value of Young's modulus (GPa) was determined for cast plates consisting of certain intermetallic substrates, resulting in the following sample observations ("Strength and Modulus of a Molybdenum-Coated Ti-25Al-10Nb-3U1Mo Intermetallic," J. of Materials Engr: and Performance, \(1997: 46-50)\) \(\begin{array}{lllll}116.4 & 115.9 & 114.6 & 115.2 & 115.8\end{array}\) a. Calculate \(\bar{x}\) and the deviations from the mean. b. Use the deviations calculated in part (a) to obtain the sample variance and the sample standard deviation. c. Calculate \(s^{2}\) by using the computational formula for the numerator \(S_{x x}\) d. Subtract 100 from each observation to obtain a sample of transformed values. Now calculate the sample variance of these transformed values, and compare it to \(s^{2}\) for the original data.

The article "Oxygen Consumption During Fire Suppression: Error of Heart Rate Estimation" (Ergonomics, 1991: 1469-1474) reported the following data on oxygen consumption ( \(\mathrm{mL} / \mathrm{kg} / \mathrm{min}\) ) for a sample of ten firefighters performing a fire-suppression simulation: \(\begin{array}{llllllllll}29.5 & 49.3 & 30.6 & 28.2 & 28.0 & 26.3 & 33.9 & 29.4 & 23.5 & 31.6\end{array}\) Compute the following: a. The sample range b. The sample variance \(s^{2}\) from the definition (i.e., by first computing deviations, then squaring them, etc.) c. The sample standard deviation d. \(s^{2}\) using the shortcut method

Consider the following observations on shear strength (MPa) of a joint bonded in a particular manner (from a graph in the article "Diffusion of Silicon Nitride to Austenitic Stainless Steel without Interlayers," Metallurgical Trans., 1993: 1835-1843). \(\begin{array}{rrrrrr}22.2 & 40.4 & 16.4 & 73.7 & 36.6 & 109.9 \\ 30.0 & 4.4 & 33.1 & 66.7 & 81.5 & \end{array}\) a. What are the values of the fourths, and what is the value of \(f_{s}\) ? b. Construct a boxplot based on the five-number summary, and comment on its features. c. How large or small does an observation have to be to qualify as an outlier? As an extreme outlier? d. By how much could the largest observation be decreased without affecting \(f_{s}\) ?

Temperature transducers of a certain type are shipped in batches of 50 . A sample of 60 batches was selected, and the number of transducers in each batch not conforming to design specifications was determined, resulting in the following data: \(\begin{array}{llllllllllllllllllll}2 & 1 & 2 & 4 & 0 & 1 & 3 & 2 & 0 & 5 & 3 & 3 & 1 & 3 & 2 & 4 & 7 & 0 & 2 & 3 \\ 0 & 4 & 2 & 1 & 3 & 1 & 1 & 3 & 4 & 1 & 2 & 3 & 2 & 2 & 8 & 4 & 5 & 1 & 3 & 1 \\ 5 & 0 & 2 & 3 & 2 & 1 & 0 & 6 & 4 & 2 & 1 & 6 & 0 & 3 & 3 & 3 & 6 & 1 & 2 & 3\end{array}\) a. Determine frequencies and relative frequencies for the observed values of \(x=\) number of nonconforming transducers in a batch. b. What proportion of batches in the sample have at most five nonconforming transducers? What proportion have fewer than five? What proportion have at least five nonconforming units? c. Draw a histogram of the data using relative frequency on the vertical scale, and comment on its features.

The article "'Snow Cover and Temperature Relationships in North America and Eurasia" (J. Climate and Applied Meteorology, 1983: 460-469) used statistical techniques to relate the amount of snow cover on each continent to average continental temperature. Data presented there included the following ten observations on October snow cover for Eurasia during the years \(1970-1979\) (in million \(\mathrm{km}^{2}\) ): \(\begin{array}{llllllllll}6.5 & 12.0 & 14.9 & 10.0 & 10.7 & 7.9 & 21.9 & 12.5 & 14.5 & 9.2\end{array}\) What would you report as a representative, or typical, value of October snow cover for this period, and what prompted your choice?

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