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Do teachers find their work rewarding and satisfying? The article "Work- Related Attitudes" (Psychological Reports, 1991: \(443-450)\) reports the results of a survey of 395 elementary school teachers and 266 high school teachers. Of the elementary school teachers, 224 said they were very satisfied with their jobs, whereas 126 of the high school teachers were very satisfied with their work. Estimate the difference between the proportion of all elementary school teachers who are very satisfied and all high school teachers who are very satisfied by calculating and interpreting a \(\mathrm{CI}\).

Short Answer

Expert verified
Elementary school teachers are 0.5% to 18.1% more satisfied than high school teachers.

Step by step solution

01

Define the Variables and Proportions

Let \( p_1 \) represent the proportion of elementary school teachers who are very satisfied and \( p_2 \) represent the proportion of high school teachers who are very satisfied. From the given data, we have that out of 395 elementary school teachers, 224 are very satisfied. Hence, \( \hat{p}_1 = \frac{224}{395} \). Similarly, out of 266 high school teachers, 126 are very satisfied, so \( \hat{p}_2 = \frac{126}{266} \).
02

Calculate the Sample Proportions

Compute the sample proportions for each group.\[ \hat{p}_1 = \frac{224}{395} \approx 0.567 \]\[ \hat{p}_2 = \frac{126}{266} \approx 0.474 \]
03

Find the Estimated Difference Between Proportions

Calculate the estimated difference between the two sample proportions:\[ \hat{p}_1 - \hat{p}_2 = 0.567 - 0.474 = 0.093 \]
04

Compute the Standard Error for the Difference in Proportions

The formula for the standard error \( SE \) of the difference between two independent proportions is:\[ SE = \sqrt{\frac{\hat{p}_1 (1 - \hat{p}_1)}{n_1} + \frac{\hat{p}_2 (1 - \hat{p}_2)}{n_2}} \]Substitute the values:\[ SE = \sqrt{\frac{0.567 \times 0.433}{395} + \frac{0.474 \times 0.526}{266}} \approx 0.045 \]
05

Calculate the Confidence Interval

Using a \(95\%\) confidence level, the critical value of \( z \) is approximately 1.96. The confidence interval for the difference is:\[ \hat{p}_1 - \hat{p}_2 \pm z \cdot SE \]Substitute the values:\[ 0.093 \pm 1.96 \times 0.045 \approx 0.093 \pm 0.088 \]Thus, the confidence interval is approximately \( (0.005, 0.181) \).
06

Interpret the Confidence Interval

The confidence interval \((0.005, 0.181)\) suggests that with \(95\%\) confidence, the proportion of elementary school teachers who are very satisfied is between \(0.5\%\) and \(18.1\%\) higher than that of high school teachers. This interval does not include zero, indicating a statistically significant difference.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Proportions
When tackling a problem involving proportions, the starting point is to determine the sample proportions for each group involved. In this case, we have two groups: elementary and high school teachers. To find out how many teachers are very satisfied with their jobs, we take the number of satisfied teachers from each group and divide it by the total number of teachers surveyed in that group. This results in the sample proportion for each group.
For elementary school teachers, the sample proportion, \( \hat{p}_1 \), is calculated as \( \hat{p}_1 = \frac{224}{395} \approx 0.567 \). Similarly, for high school teachers, the sample proportion, \( \hat{p}_2 \), is \( \hat{p}_2 = \frac{126}{266} \approx 0.474 \).
These values give us an initial sense of the level of satisfaction among teachers in each group. It is important to accurately find these proportions as they lay the foundation for further calculations, such as the difference between proportions and their confidence intervals.
Standard Error
The Standard Error (SE) is crucial in statistics as it measures the variability or dispersion of sample proportions. It tells us how much the sample proportions \( \hat{p}_1 \) and \( \hat{p}_2 \) are expected to fluctuate from one sample to another.
To compute the SE for the difference between two sample proportions, we use the formula: \[ SE = \sqrt{\frac{\hat{p}_1 (1 - \hat{p}_1)}{n_1} + \frac{\hat{p}_2 (1 - \hat{p}_2)}{n_2}} \] where \( n_1 \) and \( n_2 \) are the sizes of the two samples.
This ensures that our results reflect a true picture of both teacher groups. In our case, the SE comes out to be approximately \( 0.045 \). A lower SE indicates that the sample mean is close to the population mean, providing confidence in the reliability of our sample estimates.
Difference Between Proportions
Estimating the difference between two sample proportions can reveal insightful details about comparative satisfaction levels. The difference between proportions for elementary and high school teachers shows the gap in job satisfaction.
In our example, the difference between the sample proportions is computed as \( \hat{p}_1 - \hat{p}_2 = 0.567 - 0.474 = 0.093 \). This outcome suggests that a higher proportion of elementary school teachers are very satisfied with their jobs compared to high school teachers.
Understanding this difference allows educators and policymakers to identify where satisfaction is lacking and make necessary adjustments to improve overall teacher satisfaction. The magnitude of this difference, whether it's small or large, gives insights into the general satisfaction dynamics of the teacher workforce.
Statistical Significance
Statistical significance helps us determine if the observed difference between groups is not just due to chance. It gives us confidence that our findings are representative of the larger population.
In statistical terms, the difference between the observed sample proportions is statistically significant if the confidence interval does not include zero. For this specific study, the 95% confidence interval of the difference is calculated to be approximately \( (0.005, 0.181) \).
This interval indicates that the proportion of elementary school teachers who are very satisfied is between 0.5% and 18.1% higher than that of high school teachers. Since zero is not within this interval, the difference is considered statistically significant.
  • This means that there's a genuine disparity in satisfaction levels between the two groups.
  • Statistical significance gives us a strong ground to believe that our calculated difference is valid and meaningful.
Understanding significance helps us make informed decisions based on our data analysis.

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