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In an experiment to compare bearing strengths of pegs inserted in two different types of mounts, a sample of 14 observations on stress limit for red oak mounts resulted in a sample mean and sample standard deviation of \(8.48 \mathrm{MPa}\) and . \(79 \mathrm{MPa}\), respectively, whereas a sample of 12 observations when Douglas fir mounts were used gave a mean of \(9.36\) and a standard deviation of \(1.52\) ('Bearing Strength of White Oak Pegs in Red Oak and Douglas Fir Timbers," \(J\). of Testing and Evaluation, 1998, 109-114). Consider testing whether or not true average stress limits are identical for the two types of mounts. Compare df's and \(P\)-values for the unpooled and pooled \(t\) tests.

Short Answer

Expert verified
Pooled t-test: df = 24, p-value ≈ 0.061. Unpooled t-test: df ≈ 18, p-value ≈ 0.092. The tests suggest no significant difference in stress limits.

Step by step solution

01

Define the Hypotheses

Let's start by defining our null and alternative hypotheses. - Null hypothesis, \( H_0: \mu_1 = \mu_2 \) (The true averages of stress limits are equal for both mounts).- Alternative hypothesis, \( H_a: \mu_1 eq \mu_2 \) (The true averages of stress limits are different).
02

Pooled t-test Approach

First, consider the pooled \( t \)-test, which assumes equal variances. Calculate the test statistic and the degree of freedom. \[ s_p = \sqrt{\frac{(n_1 - 1)s_1^2 + (n_2 - 1)s_2^2}{n_1 + n_2 - 2}} \]Where \( n_1 = 14 \), \( s_1 = 0.79 \), \( n_2 = 12 \), and \( s_2 = 1.52 \).Compute \( s_p \): \[ s_p = \sqrt{\frac{(13)(0.79)^2 + (11)(1.52)^2}{24}} \approx 1.208 \]Compute the t-statistic:\[ t = \frac{\overline{x}_1 - \overline{x}_2}{s_p \sqrt{\frac{1}{n_1} + \frac{1}{n_2}}} \]\[ t = \frac{8.48 - 9.36}{1.208 \sqrt{\frac{1}{14} + \frac{1}{12}}} \approx -1.963 \]Degrees of freedom \( df = n_1 + n_2 - 2 = 24 \).
03

Compute P-value for Pooled t-test

Using a t-distribution table or technology with \( df = 24 \), find the \( p \)-value associated with the calculated \( t \)-value, \(-1.963\).- The two-tailed \( p \)-value is approximately 0.061.
04

Unpooled t-test Approach (Welch's t-test)

The unpooled (Welch's) t-test does not assume equal variances. Compute the test statistic:\[ t = \frac{\overline{x}_1 - \overline{x}_2}{\sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2}}} \]\[ t = \frac{8.48 - 9.36}{\sqrt{\frac{0.79^2}{14} + \frac{1.52^2}{12}}} \approx -1.789 \]Calculate the degrees of freedom using:\[ df = \frac{\left( \frac{s_1^2}{n_1} + \frac{s_2^2}{n_2} \right)^2}{\frac{(\frac{s_1^2}{n_1})^2}{n_1 - 1} + \frac{(\frac{s_2^2}{n_2})^2}{n_2 - 1}} \]\[ df \approx 18 \] (using Welch-Satterthwaite equation).
05

Compute P-value for Unpooled t-test

Using a t-distribution table or technology with \( df \approx 18 \), find the \( p \)-value for the calculated \( t \)-value, \(-1.789\).- The two-tailed \( p \)-value is approximately 0.092.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

t-test
The t-test is a statistical method used to determine if there is a significant difference between the means of two groups. In hypothesis testing, we compare a calculated t-statistic to a critical value from the t-distribution to decide whether to accept or reject the null hypothesis. For each t-test, the t-statistic is calculated using the formula:* With \( \overline{x}_1 \) and \( \overline{x}_2 \) as sample means* \( s \) as standard deviation, and \( n \) as sample size. The formula can vary slightly depending on the type of t-test but revolves around the difference between means and the variability within the data. When the calculated t-statistic is greater than the critical value, it suggests that the sample mean differences are significant. This is a key tool in statistical inference.
pooled t-test
The pooled t-test, also known as the independent samples t-test, is specifically used for comparing means from two independent samples that are assumed to have equal variances. This method takes the variance within each sample and combines them into a single estimate known as the pooled variance.The formula for pooled variance \( s_p \) is:\[ s_p = \sqrt{\frac{(n_1 - 1)s_1^2 + (n_2 - 1)s_2^2}{n_1 + n_2 - 2}} \]* Where the sample sizes and standard deviations are from the respective groups. The pooled approach provides an average measure of variability for both groups, under the assumption that they follow the same distribution. The degrees of freedom for this test are calculated as \( n_1 + n_2 - 2 \), guiding how we interpret the t-distribution tables. This method is efficient when variances are equal across samples, giving reliable results.
Welch's t-test
Welch's t-test is a variation of the t-test that does not require the assumption of equal variances. This test is more robust than the pooled t-test when the sample variances are significantly different, making it particularly useful in real-world data analysis where equality of variance cannot be guaranteed.The formula for the test statistic in Welch's t-test is: \[ t = \frac{\overline{x}_1 - \overline{x}_2}{\sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2}}} \] The degrees of freedom are calculated using the Welch-Satterthwaite equation:\[ df = \frac{\left( \frac{s_1^2}{n_1} + \frac{s_2^2}{n_2} \right)^2}{\frac{(\frac{s_1^2}{n_1})^2}{n_1 - 1} + \frac{(\frac{s_2^2}{n_2})^2}{n_2 - 1}} \] While more complex, this method adjusts for variations in sample size and variance, providing a more accurate result for unequal groups.
degrees of freedom
Degrees of freedom (df) refer to the number of independent pieces of information available to estimate a parameter. In statistical tests, they determine the shape of the t-distribution, which is critical in hypothesis testing.For a simple t-test, the degrees of freedom are typically calculated as the total number of observations minus the number of groups being compared, such as \( n - 1 \). In a pooled t-test, it is \( n_1 + n_2 - 2 \), reflecting the combined sample minus two parameters estimated (means of both groups).When using Welch’s t-test, the calculation of degrees of freedom becomes more complex due to the adjustments for unequal variances. It requires the Welch-Satterthwaite approximation.Understanding and calculating degrees of freedom is essential to interpreting a t-test properly as it affects the critical t-value used to determine statistical significance.

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Most popular questions from this chapter

Suppose a level 05 test of \(H_{0}: \mu_{1}-\mu_{2}=0\) versus \(H_{\mathrm{a}}: \mu_{1}-\mu_{2}>0\) is to be performed, assuming \(\sigma_{1}=\sigma_{2}=\) 10 and normality of both distributions, using equal sample sizes \((m=n)\). Evaluate the probability of a type II error when \(\mu_{1}-\mu_{2}=1\) and \(n=25,100,2500\), and 10,000 . Can you think of real problems in which the difference \(\mu_{1}-\mu_{2}=1\) has little practical significance? Would sample sizes of \(n=10,000\) be desirable in such problems?

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81\. The accompanying data on response time appeared in the article "The Extinguishment of Fires Using Low-Flow Water Hose Streams-Part 11" (Fire Technology, 1991: 291-320). Good visibility Poor visibility \(\begin{array}{llllllll}.43 & 1.17 & .37 & .47 & .68 & .58 & .50 & 2.75\end{array}\) \(\begin{array}{llllllll}1.47 & .80 & 1.58 & 1.53 & 4.33 & 4.23 & 3.25 & 3.22\end{array}\) The authors analyzed the data with the pooled \(t\) test. Does the use of this test appear justified? [Hint: Check for normality. The \(z\) percentiles for \(n=8\) are \(-1.53,-.89,-.49,-.15\), \(.15, .49, .89\), and 1.53.]

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