/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 21 The desired percentage of \(\mat... [FREE SOLUTION] | 91Ó°ÊÓ

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The desired percentage of \(\mathrm{SiO}_{2}\) in a certain type of aluminous cement is 5.5. To test whether the true average percentage is \(5.5\) for a particular production facility, 16 independently obtained samples are analyzed. Suppose that the percentage of \(\mathrm{SiO}_{2}\) in a sample is normally distributed with \(\sigma=.3\) and that \(\bar{x}=5.25\). a. Does this indicate conclusively that the true average percentage differs from \(5.5\) ? b. If the true average percentage is \(\mu=5.6\) and a level \(\alpha=.01\) test based on \(n=16\) is used, what is the probability of detecting this departure from \(H_{0}\) ? c. What value of \(n\) is required to satisfy \(\alpha=.01\) and \(\beta(5.6)=.01 ?\)

Short Answer

Expert verified
a) The true average percentage likely differs from 5.5. b) The power of detecting µ = 5.6 is very high. c) Require a sample size of approximately 84.

Step by step solution

01

Formulate the Hypotheses

First, we need to set up the null and alternative hypotheses. The null hypothesis, \(H_0\), is that the true average percentage \(\mu\) is 5.5: \(H_0: \mu = 5.5\). The alternative hypothesis, \(H_a\), is that the true average percentage is not 5.5: \(H_a: \mu eq 5.5\).
02

Compute the Test Statistic

To determine if there is a significant difference from the null hypothesis, we proceed to calculate the test statistic using the formula \(Z = \frac{\bar{x} - \mu_0}{\sigma/\sqrt{n}}\), where \(\bar{x} = 5.25\), \(\mu_0 = 5.5\), \(\sigma = 0.3\), and \(n = 16\). Substituting these values, \(Z = \frac{5.25 - 5.5}{0.3/\sqrt{16}} = \frac{-0.25}{0.075} = -3.33\).
03

Determine Critical Values for the Test

For a two-tailed test at significance level \(\alpha = 0.01\), the critical Z-values are found in the standard normal distribution table as approximately \(\pm 2.576\).
04

Make a Decision Based on Z-Test

Since \(Z = -3.33\) falls beyond the critical value of \(\pm 2.576\), we reject the null hypothesis \(H_0: \mu = 5.5\). This statistically indicates the true mean possibly differs from 5.5.
05

Compute Power of the Test for \(\mu = 5.6\)

To find the probability of detecting \(\mu = 5.6\), calculate the non-centrality parameter using the formula \(\Delta = \frac{\mu - \mu_0}{\sigma/\sqrt{n}}\), which results in \(Z = \frac{5.6 - 5.5}{0.3/\sqrt{16}} = 1.33\). Adjust for \(Z = -1.33\) and find the detection probability as the complement of \(\beta\), which corresponds to rejecting \(H_0\) at the critical values. The calculation results in high power close to significance of \(\beta(5.6)\).
06

Calculate Sample Size \(n\) for Desired \(\alpha\) and \(\beta\)

We need \(n\) to ensure \(\alpha = 0.01\) and \(\beta = 0.01\). Use the sample size formula based on given \(\alpha\) and \(\beta\): \(n = (Z_{\alpha/2} + Z_{\beta})^2 \times \frac{\sigma^2}{(\mu - \mu_0)^2}\). Solve by substituting \(Z_{0.005} = 2.576\) and \(Z_{0.01} = 2.33\), obtaining \(n = (2.576 + 2.33)^2 \times \frac{0.09}{0.01} = 83.4216\), thus \(n \approx 84\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Significance Level
In hypothesis testing, the significance level, denoted by \(\alpha\), is a critical concept. It represents the probability of rejecting the null hypothesis when it is actually true. Common significance levels are 0.01, 0.05, or 0.10, which correspond to 1%, 5%, and 10% probabilities of making a Type I error.

- A smaller \(\alpha\) indicates stronger evidence is needed to reject the null hypothesis.
- In this exercise, with \(\alpha = 0.01\), the test is very stringent, requiring strong evidence to conclude that the true average percentage differs from the hypothesized 5.5.

When determining critical values for the test, this significance level helps define the rejection region. For a two-tailed test at \(\alpha = 0.01\), we look for critical Z-values from the standard normal distribution, approximately \(\pm 2.576\). If the test statistic falls into this rejection region, the null hypothesis is rejected, as seen in this case with a test statistic of \(-3.33\). The decision to reject confirms that the observed sample mean significantly deviates from the expected value.
Test Statistic
The test statistic is a standardized value that is used to decide whether to reject the null hypothesis. It measures how far the sample statistic is from the expected value under the null hypothesis, labeled as \(H_0\).

The calculation for the test statistic in this scenario uses the formula:
\[Z = \frac{\bar{x} - \mu_0}{\sigma/\sqrt{n}}\]
where \(\bar{x}\) is the sample mean, \(\mu_0\) the population mean under \(H_0\), \(\sigma\) the standard deviation, and \(n\) the sample size.

For this exercise:
  • \(\bar{x} = 5.25\), the observed sample mean.
  • \(\mu_0 = 5.5\), the hypothesized population mean.
  • \(\sigma = 0.3\), indicating the variability.
  • \(n = 16\), reflecting the sample size.
Substituting these values gives a \(Z\) score of \(-3.33\). This score tells us how many standard deviations the observed mean is from the hypothesized mean.

In summary, a larger absolute value of the test statistic indicates that the sample results significantly deviate from \(H_0\), leading to a decision that likely the true average percentage is different from 5.5.
Sample Size Calculation
Determining the right sample size is crucial for designing experiments that are both efficient and have satisfactory statistical power. Sample size affects the reliability of hypothesis tests, particularly influencing Type I and Type II errors.

To achieve a desired significance level \(\alpha\) and a specific \(\beta\) (Type II error rate), we use the sample size formula:
\[n = (Z_{\alpha/2} + Z_{\beta})^2 \times \frac{\sigma^2}{(\mu - \mu_0)^2}\]

  • \(Z_{\alpha/2}\) is the Z-value corresponding to the desired significance level's half. For \(\alpha = 0.01\), it is 2.576.
  • \(Z_{\beta}\) is the Z-value corresponding to the allowable Type II error. For \(\beta = 0.01\), it is 2.33.
  • \(\sigma\) is the population standard deviation.
  • \(\mu - \mu_0\) is the minimum detectable difference.

In this case, calculating with given values, the required sample size \(n\) is around 84, ensuring the test has the power to detect the specified effects at given significance and power thresholds. Thus, this thorough calculation prepares the experiment to reliably conclude differences in the cement's \(\mathrm{SiO}_2\) percentage.

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Most popular questions from this chapter

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