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Let \(\mu\) denote the true average radioactivity level (picocuries per liter). The value \(5 \mathrm{pCi} / \mathrm{L}\) is considered the dividing line between safe and unsafe water. Would you recommend testing \(H_{0}: \mu=5\) versus \(H_{\mathrm{a}}: \mu>5\) or \(H_{0}: \mu=5\) versus \(H_{a}: \mu<5\) ? Explain your reasoning. [Hint: Think about the consequences of a type I and type II error for each possibility.]

Short Answer

Expert verified
Test \(H_{0}: \mu = 5\) versus \(H_{a}: \mu > 5\) to prioritize detecting unsafe conditions.

Step by step solution

01

Define Hypotheses

The hypotheses are about testing whether the true average radioactivity level, \(\mu\), is greater than 5 pCi/L (unsafe) or less than 5 pCi/L (safe). We consider two scenarios: \(H_{0}: \mu = 5\) versus \(H_{a}: \mu > 5\) and \(H_{0}: \mu = 5\) versus \(H_{a}: \mu < 5\).
02

Analyze Consequences of Type I Error

In hypothesis testing, a Type I error occurs when we reject the null hypothesis \(H_{0}\) when it is actually true. For \(H_{0}: \mu = 5\) versus \(H_{a}: \mu > 5\), a Type I error means we conclude that the water is unsafe (\(\mu > 5\)) when in fact it is safe (\(\mu = 5\)). This could lead to unnecessary alarm and possibly costly actions to rectify an assumed problem. In the opposite direction (\(H_{0}: \mu = 5\) versus \(H_{a}: \mu < 5\)), a Type I error is concluding the water is safer than it actually is, which might be less alarming but still unsatisfactory.
03

Analyze Consequences of Type II Error

A Type II error occurs when we fail to reject the null hypothesis when the alternative hypothesis is true. For \(H_{0}: \mu = 5\) versus \(H_{a}: \mu > 5\), a Type II error occurs if we conclude the water level is safe (\(\mu = 5\)) when it is actually unsafe (\(\mu > 5\)), posing a potential risk to public health. In the reverse scenario, a Type II error means we fail to identify safer than threshold levels when they really are, causing no immediate danger.
04

Recommend Hypothesis to Test

Given the potential consequences of errors, \(H_{0}: \mu = 5\) versus \(H_{a}: \mu > 5\) is the preferred option because determining if we are in an unsafe condition is critical to avoid public health risks. Type II errors in this case would make a significant impact by missing a dangerous situation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Type I error
In the context of hypothesis testing, a Type I error happens when we reject the null hypothesis, falsely concluding the alternative hypothesis is true.
This means we think there's an effect or a difference when there really isn't one.
For the problem of radioactivity levels in water, this can have specific implications.

Consider testing the hypothesis \( H_{0}: \mu = 5 \) against \( H_{a}: \mu > 5 \).
If a Type I error occurs here, we conclude that the water has unsafe levels of radioactivity above 5 pCi/L, when it's actually at the safe threshold.
  • This kind of error could lead to unnecessary steps to "fix" what isn't actually a problem, causing both alarm and unnecessary expenditure.
However, making a Type I error when testing \( H_{0}: \mu = 5 \) versus \( H_{a}: \mu < 5 \) means thinking the water is safer than it actually is.
Although less dire in terms of public perception, this error is not desired as it overestimates the safety of the water.
Type II error
While a Type I error involves a false positive, a Type II error involves missing an effect or difference when there actually is one.
In hypothesis testing, this happens when we accept the null hypothesis when the alternative is actually true.

With our problem, if \( H_{0}: \mu = 5 \) is tested against \( H_{a}: \mu > 5 \), a Type II error would mean we falsely believe the water is safe when the radioactivity actually exceeds 5 pCi/L.
  • This is critical because we could overlook a genuine public safety hazard, putting people's health at risk.
On the other hand, when testing \( H_{0}: \mu = 5 \) versus \( H_{a}: \mu < 5 \), a Type II error occurs if we miss identifying water that's actually safer than the threshold.
Here, the impact is less severe as it doesn't put public health at risk, but it can prevent acknowledgment of improved water conditions.
Public health risk
Public health risk is a considerable factor in environmental safety assessments, especially with elements like water radioactivity.
Any analyses of water quality must prioritize preventing health hazards over other concerns.
When conducting hypothesis tests concerning the safety of drinking water, understanding the consequences of errors is essential.
Choosing the right hypothesis test minimizes these public health risks by ensuring potentially unsafe conditions are not mistakenly perceived as safe.
For the exercise:
  • Testing \( H_{0}: \mu = 5 \) against \( H_{a}: \mu > 5 \) is advisable to make sure unsafe water isn't mistakenly identified as safe.
An incorrect conclusion in this scenario could result in continued exposure to harmful levels of radioactivity in drinking water, leading to potential health issues in the community.
Radioactivity in water
Radioactivity in water refers to the presence of radioactive substances, measured in picocuries per liter (pCi/L).
This is a pressing concern because long-term exposure to radioactivity can lead to severe health issues such as cancer.
In water safety regulation, a threshold of 5 pCi/L is typically used to demarcate safe from unsafe water. Understanding and applying this threshold correctly in hypothesis testing ensures that water supplies remain healthy.
The decision of whether to prioritize finding greater-than-threshold levels (testing \( H_{0}: \mu = 5 \) against \( H_{a}: \mu > 5 \)) ensures that any potential increased radioactivity that could negatively affect public health is quickly identified.
Taking a proactive approach helps protect populations from unseen health dangers in water supplies, ensuring they remain safe and healthy.

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