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a. Show that if \(X\) has a normal distribution with parameters \(\mu\) and \(\sigma\), then \(Y=a X+b\) (a linear function of \(X\) ) also has a normal distribution. What are the parameters of the distribution of \(Y\) [i.e., \(E(Y)\) and \(V(Y)]\) ? b. If, when measured in \({ }^{\circ} \mathrm{C}\), temperature is normally distributed with mean 115 and standard deviation 2 , what can be said about the distribution of temperature measured in \({ }^{\circ} \mathrm{F}\) ?

Short Answer

Expert verified
Temperature in Fahrenheit is normally distributed with mean 239 and standard deviation 3.6.

Step by step solution

01

Understanding the Problem

We need to show that a linear transformation of a normally distributed random variable results in a normally distributed variable. Given that X~N(\(\mu,\ \sigma^2\)), we need to show that Y=aX+b is also normally distributed and find its mean \(E(Y)\) and variance \(V(Y)\).
02

Apply Linear Transformation to the Expected Value

The expected value of \(Y=aX+b\) can be found using the linearity of expectation. Since \(E(X) = \mu\), we have:\[E(Y) = E(aX + b) = aE(X) + b = a\mu + b.\]
03

Apply Linear Transformation to the Variance

The variance of \(Y\) can be calculated using the property \(V(aX+b) = a^2 V(X)\), where \(V(X) = \sigma^2\). Therefore:\[V(Y) = V(aX+b) = a^2\sigma^2.\]
04

Conclude Distribution of Y

From steps 2 and 3, since the mean and variance follow the properties of a normal distribution, the random variable \(Y = aX + b\) is also normally distributed with mean \(a\mu+b\) and variance \(a^2\sigma^2\).
05

Convert Celsius to Fahrenheit

Given temperature in Celsius is normally distributed with mean 115 and standard deviation 2, we convert to Fahrenheit using the formula \(F=\frac{9}{5}C+32\). Thus, \(a=\frac{9}{5}\) and \(b=32\).
06

Determine Fahrenheit Parameters

Using the conversion formula in step 4 and applying the results from steps 2 and 3, the mean and variance of the temperature in Fahrenheit can be determined. The mean is:\[E(F) = \frac{9}{5} \times 115 + 32 = 239.\]The standard deviation is:\[\sigma_F = \frac{9}{5} \times 2 = 3.6.\]Thus, temperature in Fahrenheit is normally distributed with mean 239 and standard deviation 3.6.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Normal Distribution Properties
The normal distribution is a continuous probability distribution characterized by its bell-shaped curve, also called the Gaussian curve. This distribution is symmetrical about its mean, showing that values near the mean are more frequent in occurrence than values far from the mean.
The properties of the normal distribution that make it universally applicable include:
  • Mean, Median, Mode Equality: In a normal distribution, the mean, median, and mode are all equal, lying at the center of the distribution.
  • Symmetry: The distribution is perfectly symmetrical about the mean, such that the area under the curve is distributed equally between the left and right sides.
  • 68-95-99.7 Rule: Approximately 68% of the data falls within one standard deviation of the mean, 95% within two, and 99.7% within three.
  • Inflection Points: These points are located one standard deviation away from the mean on either side, marking where the curve changes concavity.
The behavior of a normally distributed variable makes it a fundamental building block in probability and statistics.
Linear Transformation in Probability
Linear transformation in probability involves changing a random variable using an equation of the form \(Y = aX + b\), where \(X\) is a random variable, \(a\) and \(b\) are constants. This transformation is crucial in changing the scale or location (mean) of a distribution.
Transformations impact the random variable as follows:
  • Mean Change: The transformation alters the mean by a factor of \(a\) and translates it by \(b\). Thus, the new mean becomes \(a\mu + b\).
  • Variance Change: Variance changes based on \(a^2\) and does not involve \(b\), resulting in a new variance of \(a^2\sigma^2\).
When a linear transformation is applied to a normally distributed variable, the result is another normal distribution. This is due to the transformation maintaining linearity, which implies the underlying distribution shape remains unchanged. The impact is merely on its parameters—mean and variance—transforming to reflect the new scale and shift.
Expected Value and Variance
Expected value, often denoted as \(E(X)\), provides the average or mean outcome of a random variable over numerous trials. It denotes the central tendency or 'long-term typical' value of the variable. For a normal distribution \(X\), the expected value is given by its mean \(\mu\).
Variance measures the spread of the random variable around the mean. It is represented by \(V(X)\) or \(\sigma^2\) for normal distributions. Variance quantifies variability, indicating how much the values deviate from the mean. A smaller variance means data is closely clustered around the mean, while a larger variance suggests more spread out data.For a linear transformation \(Y = aX + b\), the expected value and variance are computed as:
  • Expected value of \(Y\): \(E(Y) = a\mu + b\)
  • Variance of \(Y\): \(V(Y) = a^2\sigma^2\)
Both expected value and variance are crucial for understanding the behavior of transformed distributions, marking differences and consistencies in different contexts.
Temperature Conversion
Temperature conversion often requires transforming normal distributions, especially for processes using different measurement systems like Celsius and Fahrenheit. The formula for converting Celsius to Fahrenheit is given by \(F = \frac{9}{5}C + 32\). This linear transformation enables understanding temperature variations across scales.
When the temperature in Celsius has a normal distribution, one can determine its distribution in Fahrenheit by applying the conversion formula. Suppose a temperature \(C\) in Celsius is normally distributed with mean \(\mu_C = 115\) and standard deviation \(\sigma_C = 2\). Converting to Fahrenheit, we use:
  • Mean in Fahrenheit: \(E(F) = \frac{9}{5} \times 115 + 32 = 239\)
  • Standard Deviation in Fahrenheit: \(\sigma_F = \frac{9}{5} \times 2 = 3.6\)
Thus, the temperature in Fahrenheit is normally distributed with a mean of 239 and a standard deviation of 3.6, reflecting transformed parameters due to the linear nature of the equation.

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Most popular questions from this chapter

Stress is applied to a 20 -in. steel bar that is clamped in a fixed position at each end. Let \(Y=\) the distance from the left end at which the bar snaps. Suppose \(Y / 20\) has a standard beta distribution with \(E(Y)=10\) and \(V(Y)=\frac{100}{7}\). a. What are the parameters of the relevant standard beta distribution? b. Compute \(P(8 \leq Y \leq 12)\). c. Compute the probability that the bar snaps more than 2 in. from where you expect it to.

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What condition on \(\alpha\) and \(\beta\) is necessary for the standard beta pdf to be symmetric?

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