/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 5 A college professor never finish... [FREE SOLUTION] | 91Ó°ÊÓ

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A college professor never finishes his lecture before the end of the hour and always finishes his lectures within \(2 \mathrm{~min}\) after the hour. Let \(X=\) the time that elapses between the end of the hour and the end of the lecture and suppose the pdf of \(X\) is $$ f(x)=\left\\{\begin{array}{cc} k x^{2} & 0 \leq x \leq 2 \\ 0 & \text { otherwise } \end{array}\right. $$ a. Find the value of \(k\) and draw the corresponding density curve. b. What is the probability that the lecture ends within 1 min of the end of the hour? c. What is the probability that the lecture continues beyond the hour for between 60 and \(90 \mathrm{sec}\) ? d. What is the probability that the lecture continues for at least \(90 \mathrm{sec}\) beyond the end of the hour?

Short Answer

Expert verified
a) k = 3/8. b) 1/8. c) 0.296875. d) 0.578125.

Step by step solution

01

Find the value of k

We know that the total probability must equal 1, so we integrate the given probability density function across its range.\[\int_0^2 kx^2 \, dx = 1\]Calculating the integral:\[\left[\frac{kx^3}{3}\right]_0^2 = \frac{k(2)^3}{3} = \frac{8k}{3}\]Set the integral equal to 1:\[\frac{8k}{3} = 1\]Solving for \(k\):\[k = \frac{3}{8}\]
02

Draw the density curve

The pdf is given by:\[f(x) = \frac{3}{8}x^2\text{ for }0 \le x \le 2\]This is a parabolic curve opening upwards starting from 0 to 2 on the x-axis.
03

Find probability for X ≤ 1

To find the probability that the lecture ends within 1 minute of the end of the hour, we integrate the pdf from 0 to 1:\[P(0 \leq X \leq 1) = \int_0^1 \frac{3}{8}x^2 \, dx\]Calculating the integral:\[= \left[\frac{3}{8} \cdot \frac{x^3}{3}\right]_0^1\]\[= \left[\frac{x^3}{8}\right]_0^1\]\[= \frac{1^3}{8} - \frac{0^3}{8}\]\[= \frac{1}{8}\]
04

Find probability for 1 ≤ X ≤ 1.5

Convert from seconds to minutes: 60 seconds = 1 minute, 90 seconds = 1.5 minutes. Now, find the probability for 60 to 90 seconds (1 to 1.5 minutes):\[P(1 \leq X \leq 1.5) = \int_1^{1.5} \frac{3}{8}x^2 \, dx\]Calculating the integral:\[= \left[\frac{x^3}{8}\right]_1^{1.5}\]\[= \frac{(1.5)^3}{8} - \frac{(1)^3}{8}\]\[= \frac{3.375}{8} - \frac{1}{8}\]\[= \frac{2.375}{8} = 0.296875\]
05

Find probability for X ≥ 1.5

To find the probability that the lecture continues for at least 1.5 minutes beyond the hour, we calculate the integral from 1.5 to 2:\[P(X \geq 1.5) = \int_{1.5}^{2} \frac{3}{8}x^2 \, dx\]Calculating the integral:\[= \left[\frac{x^3}{8}\right]_{1.5}^{2}\]\[= \frac{(2)^3}{8} - \frac{(1.5)^3}{8}\]\[= \frac{8}{8} - \frac{3.375}{8}\]\[= \frac{4.625}{8} = 0.578125\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Continuous Random Variable
A continuous random variable is a type of random variable that can take any value within a given range. This means it is not restricted to any discrete set of values, such as integers. Instead, it can be any number, including fractions or decimals, within an interval.
In the context of probability, we often deal with continuous random variables when modeling real-world scenarios, like the time taken by a professor to finish a lecture.
Here, the time, denoted as \(X\), is considered a continuous random variable because it represents a measurement of time that can take any value from 0 to 2 minutes. The randomness enters as the exact end time of the lecture varies each session.
Continuous random variables are integral to many statistical models because they offer a complete and nuanced description of uncertainty. They allow us to calculate probabilities for a range of outcomes, using probability density functions (PDFs) as shown in this example with the professor's lecture end times.
Integration in Probability
Integration in probability is an essential technique used when dealing with continuous random variables. It allows us to find the probability of a random variable being within a certain range by integrating the probability density function (PDF) over that range.
In our scenario, the PDF is given by \(f(x) = kx^2\) for \(0 \leq x \leq 2\). The goal is to integrate this function over certain intervals to find the required probabilities.
For instance, the process of finding the value of \(k\) requires setting the integral of the PDF over the full range to 1, reflecting the total probability of all outcomes:
  • Calculate the integral of \(kx^2\) from 0 to 2
  • Set the integral equal to 1 to solve for \(k\)
This integration tells us how probability accumulates over different times, offering insights into the likelihood of the professor finishing his lecture at various points within the 2-minute window.
Uniform Distribution
The concept of a uniform distribution might come to mind in certain probability problems, but it differs significantly from our current example. A uniform distribution is characterized by having equal probability across all possible values within its range, often simplified as a flat line in its PDF.
However, the given PDF for the lecture's ending time is not uniform. Instead of a constant value, the PDF here follows a quadratic function, \(f(x) = kx^2\). This indicates that while some times are more likely than others, it increases smoothly based on the square of the time.
In simple terms, this tells us that as \(x\) increases from 0 to 2 minutes, the probability density (or likelihood) for that time to be the ending time also increases. Thus, later times in this interval are more likely than earlier times, opposite to what we'd see in a uniform distribution.
Parabolic Curve in Statistics
A parabolic curve in statistics often describes relationships where changes aren't constant but instead follow a pattern increasing or decreasing more rapidly at certain intervals.
In this case, the probability density function (PDF) \(f(x) = kx^2\) creates a parabolic curve when graphed, opening upwards over the range 0 to 2 minutes. This shape reflects how probability density increases as time progresses.
The parabolic PDF stands out because it indicates that the likelihood of an event (like finishing the lecture) is not distributed evenly. Instead, there's an acceleration in likelihood as time moves on from 0 to 2. The curve starts at zero when the hour ends and rises to its peak at 2 minutes, representing the professor's tendency to finish closer to the end of the interval.
This type of curve offers an intuitive visual representation of probabilities, highlighting how certain outcomes are more likely based on the function's configuration.

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