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The article 'Should You Report That FenderBender?" (Consumer Reports, Sept. 2013: 15) reported that 7 in 10 auto accidents involve a single vehicle (the article recommended always reporting to the insurance company an accident involving multiple vehicles). Suppose 15 accidents are randomly selected. Use Appendix Table A.l to answer each of the following questions. a. What is the probability that at most 4 involve a single vehicle? b. What is the probability that exactly 4 involve a single vehicle? c. What is the probability that exactly 6 involve multiple vehicles? d. What is the probability that between 2 and 4 , inclusive, involve a single vehicle? e. What is the probability that at least 2 involve a single vehicle? f. What is the probability that exactly 4 involve a single vehicle and the other 11 involve multiple vehicles?

Short Answer

Expert verified
Use the binomial distribution to find probabilities: (a) Sum \( P(X = 0) \) to \( P(X = 4) \); (b) \( P(X = 4) \); (c) \( P(X = 9) \); (d) Sum \( P(X = 2) \), \( P(X = 3) \), \( P(X = 4) \); (e) \( 1 - P(X < 2) \); (f) Use \( P(X = 4) \).

Step by step solution

01

Identify Given Information

We are given that the probability of an accident involving a single vehicle is \( p = \frac{7}{10} = 0.7 \). We are dealing with a binomial distribution where the number of trials \( n = 15 \). Therefore, the probability of an accident involving multiple vehicles is \( 1 - p = 0.3 \). We now have \( n = 15 \), \( p = 0.7 \), and \( 1 - p = 0.3 \).
02

Identify Appropriate Probability Distribution

Since we are dealing with 15 independent trials and each having two possible outcomes (single vehicle vs. multiple vehicles), this forms a binomial distribution with parameters \( n = 15 \) and \( p = 0.7 \).
03

Calculate Probability for Part (a)

Calculate \( P(X \leq 4) \) where \( X \) is the number of accidents involving a single vehicle. Use the binomial probability formula: \[ P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \]For \( X \leq 4 \), sum \( P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) \). Use Appendix Table A.1 or a calculator to find these probabilities.
04

Calculate Probability for Part (b)

Calculate \( P(X = 4) \) using the binomial formula:\[ P(X = 4) = \binom{15}{4} (0.7)^4 (0.3)^{11} \]Compute the value using a calculator or Appendix Table A.1.
05

Calculate Probability for Part (c)

Note that if there are 6 involving multiple vehicles, then there are 15 - 6 = 9 involving a single vehicle. Calculate \( P(X = 9) \):\[ P(X = 9) = \binom{15}{9} (0.7)^9 (0.3)^{6} \]Compute the value using a calculator or Appendix Table A.1.
06

Calculate Probability for Part (d)

For this range, calculate \( P(2 \leq X \leq 4) \):Sum \( P(X = 2) + P(X = 3) + P(X = 4) \) using the binomial formula for each value.
07

Calculate Probability for Part (e)

Calculate \( P(X \geq 2) \) as:\[ P(X \geq 2) = 1 - P(X < 2) \]Compute \( P(X = 0) + P(X = 1) \) and subtract from 1.
08

Answer and Verify Probability for Part (f)

Note for 4 single vehicle and 11 multiple vehicle accidents, the condition automatically satisfies since 4 single vehicle means 11 multiple vehicles. Use \( P(X = 4) \) from step 4, as the answer accounts for this setup automatically.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Calculations
Probability calculations allow us to determine the likelihood of various outcomes in a situation. In the context of this exercise, we're particularly interested in the probabilities surrounding auto accidents, specifically those involving a single vehicle versus multiple vehicles. The first step in calculating probabilities is to identify known quantities. Here, we know that the probability of a single vehicle accident is given as 0.7, while the probability of an accident involving multiple vehicles is 0.3.

To find specific probabilities, such as the probability of at most 4 single vehicle accidents, we use formulas specific to the binomial distribution, summing probabilities for all relevant outcomes. These calculations can be assisted greatly by using tools like the Appendix Table A.1 or a calculator that supports binomial computations.

This involves understanding and making use of combinations, which tell us how many different ways a certain number of accidents can occur in a set order.
Independent Trials
In probability theory, trials are termed independent when the outcome of one trial does not affect the outcome of another. This is a critical concept in binomial distribution as it assumes each trial (in this case, each accident) is independent of others.

The concept of independent trials is pivotal here: it ensures that the formula for the binomial distribution holds true. For instance, knowing that one accident involved a single vehicle doesn't change the probability of the next accident's classification as single or multiple vehicle. This independence allows for the use of the binomial probability formula effectively, as probability remains consistent across each trial.

By understanding this, we can apply the same probability values repeatedly into our probability formulas, knowing they won't change over time or across different occasions.
Probability Distribution
A probability distribution outlines how probabilities are distributed over all possible outcomes of a random variable. In this exercise, the probability distribution is binomial, reflecting the nature of the accident types as having only two outcomes: single or multiple vehicle accidents.

The binomial distribution is characterized by the number of trials \( n \) and the probability of success \( p \). Here, "success" is defined as an accident involving a single vehicle, with a probability \( p = 0.7 \).

This distribution helps in visualizing and calculating the probabilities associated with different numbers of successes (single vehicle accidents) in 15 trials (total accidents). Using this structured method is essential for ensuring accurate probability calculations for questions like probabilities of 2 to 4, inclusive, single vehicle accidents.
Binomial Probability Formula
The binomial probability formula is the cornerstone of solving problems related to binomial distributions. This formula allows us to calculate the probability of achieving exactly \( k \) "successes" in \( n \) independent trials, where "success" is the event of interest (a single vehicle accident, in this case).

The formula is given by:
\[ P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \]
Here:
  • \( \binom{n}{k} \) represents the number of combinations of \( n \) items taken \( k \) at a time.
  • \( p^k \) is the probability of "success" raised to the power of \( k \).
  • \((1-p)^{n-k}\) accounts for the probability of "failure" (multiple vehicle accidents) happening \( n-k \) times.

Using this formula, we can calculate the probability of a given number of single vehicle accidents, like exactly 4 or 9, from the total 15 accidents investigated in the exercise. Understanding this formula allows for precise calculation of probabilities for any specified number of "successful" outcomes within the given trials.

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