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Physical properties of six flame-retardant fabric samples were investigated in the article "Sensory and Physical Properties of Inherently Flame-Retardant Fabrics" (Textile Research, 1984: 61-68). Use the accompanying data and a \(.05\) significance level to determine whether a linear relationship exists between stiffness \(x\) (mg-cm) and thickness \(y(\mathrm{~mm})\). Is the result of the test surprising in light of the value of \(r\) ? $$ \begin{array}{r|rrrrrr} x & 7.98 & 24.52 & 12.47 & 6.92 & 24.11 & 35.71 \\ \hline y & .28 & .65 & .32 & .27 & .81 & .57 \end{array} $$

Short Answer

Expert verified
No significant linear relationship at 0.05 level; small sample size affects result.

Step by step solution

01

State the Hypotheses

We need to test if there is a significant linear relationship between the stiffness \(x\) and thickness \(y\) using a correlation test. The null hypothesis \(H_0\) is that there is no linear relationship, i.e., the correlation coefficient \(\rho = 0\). The alternative hypothesis \(H_a\) is that there is a linear relationship, i.e., \(\rho eq 0\).
02

Compute the Correlation Coefficient

Calculate the correlation coefficient \(r\) using the formula: \[ r = \frac{n(\sum xy) - (\sum x)(\sum y)}{\sqrt{[n\sum x^2 - (\sum x)^2][n\sum y^2 - (\sum y)^2]}} \]. For the given data, the calculated value of \(r\) is \(0.6017\).
03

Determine the Test Statistic

The test statistic \(t\) is calculated using \( t = \frac{r\sqrt{n-2}}{\sqrt{1-r^2}} \). Substituting the values, \(n = 6\) and \(r = 0.6017\), the test statistic is approximately \( t = 1.662 \).
04

Find the Critical Value

Using a \(\alpha = 0.05\) significance level for a two-tailed test with \(n - 2 = 4\) degrees of freedom, the critical values are \( \pm 2.776 \) from the t-distribution table.
05

Make a Decision

Compare the test statistic \(t\) to the critical value. Since \(1.662\) is less than \(2.776\), we fail to reject the null hypothesis \(H_0\). This indicates there is not enough evidence to suggest a linear relationship between stiffness and thickness.
06

Interpret the Result

The correlation coefficient \(r = 0.6017\) suggests a moderate linear relationship, yet the significance test fails to prove its significance at \(\alpha = 0.05\). Hence, the result is not surprising given the sample size is quite small.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Relationship
A linear relationship exists when two variables move in conjunction with one another; as one increases, so does the other, or vice versa. When testing fabric stiffness against thickness, we aim to know whether a consistent trend of increase or decrease is noticeable. In the context of this exercise, if we consider stiffness as our independent variable \( x \) and thickness as the dependent variable \( y \), a linear relationship would imply that a change in stiffness is associated with a proportionate change in thickness of the fabric. This foundational understanding is integral as it frames the way through which data is analyzed for potential correlations. Moreover, even if a plot seems to have dots trending upwards or downwards, we need statistical tools to confirm this visual interpretation.
Hypothesis Testing
Hypothesis testing is a procedure that allows us to make inferences about populations using sample data. In this exercise, for hypothesis testing, we first establish two contrasting hypotheses: the null hypothesis \( H_0 \) and the alternative hypothesis \( H_a \). The null hypothesis posits that no linear relationship exists between our variables (stiffness and thickness), which translates to the correlation coefficient \( \rho = 0 \). Conversely, the alternative hypothesis suggests a linear relationship does exist \( \rho eq 0 \). Our task is to test these hypotheses using a correlation test. We use statistical measures and comparisons to either reject \( H_0 \) (indicating evidence supporting \( H_a \)) or fail to reject \( H_0 \) (lacking sufficient evidence to support \( H_a \)).
Significance Level
The significance level, denoted by alpha \( \alpha \), quantifies the risk one is willing to accept when making a statistical decision. Usually set at \( 0.05 \), it represents a 5% risk of concluding that a relationship exists when it does not. In our analysis, the significance level sets the threshold for the critical value comparison. With a significance level of 0.05, we determine critical values for hypothesis testing using the t-distribution table. If our test statistic exceeds these critical thresholds, we reject the null hypothesis. However, in our exercise, the test statistic \( t = 1.662 \) falls short of the necessary critical value \( \pm 2.776 \), meaning we do not have sufficient evidence to reject \( H_0 \).
Correlation Coefficient
The correlation coefficient, \( r \), is a numerical measure that describes the direction and strength of a linear relationship between two variables. Calculated from sample data, it ranges between \(-1\) and \(1\). An \( r \) close to \( 1 \) or \(-1\) indicates a strong linear relationship, while an \( r \) near \( 0 \) suggests little to no linear association. In our exercise, \( r = 0.6017 \), meaning a moderate positive relationship exists; as stiffness increases, thickness tends to increase. Despite this result, the hypothesis test assesses the significance of \( r \). Given the calculated \( t \) was insufficient to reject the null hypothesis, the correlation is deemed not statistically significant given the sample size, leading to the interpretation that while a moderate correlation exists, its statistical validation is weak with the current data set.

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Most popular questions from this chapter

Suppose an investigator has data on the amount of shelf space \(x\) devoted to display of a particular product and sales revenue \(y\) for that product. The investigator may wish to fit a model for which the true regression line passes through \((0,0)\). The appropriate model is \(Y=\beta_{1} x+\epsilon\). Assume that \(\left(x_{1}, y_{1}\right), \ldots,\left(x_{n}, y_{n}\right)\) are observed pairs generated from this model, and derive the least squares estimator of \(\beta_{1}\). [Hint: Write the sum of squared deviations as a function of \(b_{1}\), a trial value, and use calculus to find the minimizing value of \(b_{1}\).]

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