/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 2 The value of Young's modulus (GP... [FREE SOLUTION] | 91Ó°ÊÓ

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The value of Young's modulus (GPa) was determined for cast plates consisting of certain intermetallic substrates, resulting in the following sample observations ("Strength and Modulus of a Molybdenum-Coated Ti-25Al10Nb-3U-1Mo Intermetallic," \(J\). of Materials Engr. and Performance, 1997: 46-50): \(\begin{array}{lllll}116.4 & 115.9 & 114.6 & 115.2 & 115.8\end{array}\) a. Calculate \(\bar{x}\) and the deviations from the mean. b. Use the deviations calculated in part (a) to obtain the sample variance and the sample standard deviation. c. Calculate \(s^{2}\) by using the computational formula for the numerator \(S_{x x}\) d. Subtract 100 from each observation to obtain a sample of transformed values. Now calculate the sample variance of these transformed values, and compare it to \(s^{2}\) for the original data.

Short Answer

Expert verified
The sample mean is 115.58. The variance and standard deviation are 0.705 and 0.840, respectively. The variance of transformed values remains 0.705.

Step by step solution

01

Calculate the Mean

To find the mean \(\bar{x}\), sum all observations and divide by the number of observations.\[\bar{x} = \frac{116.4 + 115.9 + 114.6 + 115.2 + 115.8}{5} = 115.58\]
02

Calculate Deviations from the Mean

Subtract the mean from each observation to find the deviations. Deviations are: \(116.4 - 115.58 = 0.82\), \(115.9 - 115.58 = 0.32\), \(114.6 - 115.58 = -0.98\), \(115.2 - 115.58 = -0.38\), \(115.8 - 115.58 = 0.22\).
03

Calculate Sample Variance and Standard Deviation

The sample variance \(s^2\) is the average of the squared deviations from the mean, divided by \(n - 1\).\[s^2 = \frac{(0.82)^2 + (0.32)^2 + (-0.98)^2 + (-0.38)^2 + (0.22)^2}{4} = 0.705\]The sample standard deviation \(s\) is the square root of the variance.\[s = \sqrt{0.705} = 0.840\]
04

Use the Computational Formula for Variance

The computational formula for the numerator \(S_{xx}\) is \(S_{xx} = \sum x_i^2 - \frac{(\sum x_i)^2}{n}\).\[S_{xx} = (116.4^2 + 115.9^2 + 114.6^2 + 115.2^2 + 115.8^2) - \frac{(577.9)^2}{5}\]Calculating gives \(S_{xx} = 2.82\) and dividing it by \(n - 1 = 4\) confirms \(s^2 = 0.705\).
05

Transform the Data and Calculate Transformed Variance

Transform the values by subtracting 100 from each: \[16.4, 15.9, 14.6, 15.2, 15.8\]Calculate the mean of the transformed data: \[\bar{x}_{\text{transformed}} = \frac{16.4 + 15.9 + 14.6 + 15.2 + 15.8}{5} = 15.58\]Find deviations \(0.82, 0.32, -0.98, -0.38, 0.22\), and calculate variance as previously: \[s^2_{\text{transformed}} = 0.705\]Since variance is independent of the shift, \(s^2\) remains the same.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Variance
Sample variance is a way to quantify the spread of data points around the mean. It helps in understanding how much the data points deviate from the average value. To calculate the sample variance, follow these simple steps:
  • First, determine the mean of your data set, which is the average of all the values.
  • Next, subtract the mean from each data point to find the deviations.
  • Square each of these deviations to ensure all values are positive.
  • Finally, sum up all the squared deviations and divide by the number of data points minus one (n-1). This step accounts for the fact that you're working with a sample, not an entire population.
By using the formula, \[s^2 = \frac{\sum (x_i - \bar{x})^2}{n-1}\]you can easily compute the sample variance, which is crucial for many statistical analyses.
Standard Deviation
Standard deviation is derived from the sample variance and represents the typical amount by which individual data points differ from the mean. It provides a valuable insight into the variability or consistency of a data set.
To calculate the standard deviation, simply take the square root of the sample variance. This is because variance is calculated in squared units, and taking the square root converts it back to the original unit, making it easier to understand and interpret. The formula for standard deviation is:
  • Calculate the sample variance (\(s^2\)).
  • Use the formula \(s = \sqrt{s^2}\) to find the standard deviation.
Understanding the standard deviation helps in assessing risk and variability in different fields such as finance, science, and research. It's a key metric for determining how spread out the values in a data set are around the mean.
Mean Calculation
Mean, also known as the average, is one of the most fundamental concepts in statistics. It provides a central value for a given data set, offering a summary of the data's central tendency. Mean calculation is simple but vital for further statistical analyses.
Here’s how to calculate the mean:
  • Add all the values or data points together.
  • Count the number of data points in the set.
  • Divide the total sum by the number of data points.
The formula is:\[\bar{x} = \frac{\sum x_i}{n}\]
The mean is used as the foundation for calculating both variance and standard deviation, making it an indispensable part of statistical analysis. Knowing the mean helps to get a general idea about the data set's overall performance and is the starting point for more intricate data analyses.

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Most popular questions from this chapter

Grip is applied to produce normal surface forces that compress the object being gripped. Examples include two people shaking hands, or a nurse squeezing a patient's forearm to stop bleeding. The article "Imvestigation of Grip Force, Normal Force, Contact Area, Hand Size, and Handle Size for Cylindrical Handles" (Human Factors, 2008: 734-744) included the following data on grip strength (N) for a sample of 42 individuals: \(\begin{array}{rrrrrrrrrrrrr}16 & 18 & 18 & 26 & 33 & 41 & 54 & 56 & 66 & 68 & 87 & 91 & 95 \\ 98 & 106 & 109 & 111 & 118 & 127 & 127 & 135 & 145 & 147 & 149 & 151 & 168 \\ 172 & 183 & 189 & 190 & 200 & 210 & 220 & 229 & 230 & 233 & 238 & 244 & 259 \\ 294 & 329 & 403 & & & & & & & & & & \end{array}\) a. Construct a stem-and-leaf display based on repeating each stem value twice, and comment on interesting features. b. Determine the values of the fourths and the fourthspread. c. Construct a boxplot based on the five-number summary, and comment on its features. d. How large or small does an observation have to be to qualify as an outlier? An extreme outlier? Are there any outliers? e. By how much could the observation 403 , currently the largest, be decreased without affecting \(f_{5}\) ?

Exposure to microbial products, especially endotoxin, may have an impact on vulnerability to allergic diseases. The article "Dust Sampling Methods for EndotoxinAn Essential, But Underestimated Issue" (Indoor Air, 2006: 20-27) considered various issues associated with determining endotoxin concentration. The following data on concentration (EU/mg) in settled dust for one sample of urban homes and another of farm homes was kindly supplied by the authors of the cited article. \(\begin{array}{lrrrrrrrrrrr}\mathrm{U}: & 6.0 & 5.0 & 11.0 & 33.0 & 4.0 & 5.0 & 80.0 & 18.0 & 35.0 & 17.0 & 23.0 \\ \mathrm{~F}: & 4.0 & 14.0 & 11.0 & 9.0 & 9.0 & 8.0 & 4.0 & 20.0 & 5.0 & 8.9 & 21.0 \\ & 9.2 & 3.0 & 2.0 & 0.3 & & & & & & & \end{array}\) a. Determine the sample mean for each sample. How do they compare? b. Determine the sample median for each sample. How do they compare? Why is the median for the urban sample so different from the mean for that sample? c. Calculate the trimmed mean for each sample by deleting the smallest and largest observation. What are the corresponding trimming percentages? How do the values of these trimmed means compare to the corresponding means and medians?

The following data on distilled alcohol content (\%) for a sample of 35 port wines was extracted from the article "A Method for the Estimation of Alcohol in Fortified Wines Using Hydrometer Baumé and Refractometer Brix" (Amer. J. Enol. Vitic., 2006: \(486-490\) ). Each value is an average of two duplicate measurements. $$ \begin{array}{lllllllll} 16.35 & 18.85 & 16.20 & 17.75 & 19.58 & 17.73 & 22.75 & 23.78 & 23.25 \\ 19.08 & 19.62 & 19.20 & 20.05 & 17.85 & 19.17 & 19.48 & 20.00 & 19.97 \\ 17.48 & 17.15 & 19.07 & 19.90 & 18.68 & 18.82 & 19.03 & 19.45 & 19.37 \\ 19.20 & 18.00 & 19.60 & 19.33 & 21.22 & 19.50 & 15.30 & 22.25 & \end{array} $$ Use methods from this chapter, including a boxplot that shows outliers, to describe and summarize the data.

Observations on burst strength \(\left(\mathrm{lb} / \mathrm{in}^{2}\right)\) were obtained both for test nozzle closure welds and for production cannister nozzle welds (4proper Procedures Are the Key to Welding Radioactive Waste Cannisters, Welding \(J .\) Aug. 1997: 61-67). \(\begin{array}{lllllll}\text { Test } & 7200 & 6100 & 7300 & 7300 & 8000 & 7400 \\ & 7300 & 7300 & 8000 & 6700 & 8300 & \\ \text { Cannister } & 5250 & 5625 & 5900 & 5900 & 5700 & 6050 \\ & 5800 & 6000 & 5875 & 6100 & 5850 & 6600\end{array}\) Construct a comparative boxplot and comment on interesting features (the cited article did not include such a picture, but the authors commented that they had looked at one).

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