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Before agreeing to purchase a large order of polyethylene sheaths for a particular type of high-pressure oil-filled submarine power cable, a company wants to see conclusive evidence that the true standard deviation of sheath thickness is less than \(.05 \mathrm{~mm}\). What hypotheses should be tested, and why? In this context, what are the type I and type II errors?

Short Answer

Expert verified
Test \( H_0: \sigma \geq 0.05 \) vs. \( H_a: \sigma < 0.05 \). Type I error: concluding \( \sigma < 0.05 \) when it's not; Type II error: failing to conclude \( \sigma < 0.05 \) when it is.

Step by step solution

01

Define Hypotheses

In hypothesis testing, we start by defining the null and alternative hypotheses. Here, the company is checking whether the true standard deviation of the sheath thickness is less than 0.05 mm. Therefore, the null hypothesis (abla_0dataabla_0abla_0) should state that the standard deviation is equal to or greater than 0.05 mm, while the alternative hypothesis (abla_adataabla_aabla_a) would state that the standard deviation is less than 0.05 mm. Formally, these can be written as: \( H_0: \sigma \geq 0.05 \) and \( H_a: \sigma < 0.05 \).
02

Identify Type I Error

A type I error occurs when the null hypothesis is rejected when it is actually true. In this context, a type I error would mean the company concludes that the standard deviation of sheath thickness is less than 0.05 mm, when in fact, it is equal to or greater than 0.05 mm.
03

Identify Type II Error

A type II error occurs when the null hypothesis is not rejected when it is actually false. In this scenario, a type II error would occur if the company fails to conclude that the standard deviation of the sheath thickness is less than 0.05 mm, even though it truly is less than this.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Type I Error
In hypothesis testing, a Type I error is an important concept to understand. It occurs when we reject a true null hypothesis. Think of it as a "false alarm". In the context of the polyethylene sheaths, a Type I error would happen if the company concludes that the standard deviation of the sheath thickness is less than 0.05 mm, even though it actually isn't.

This mistake is serious because it leads to an incorrect decision, suggesting that the product meets the required specifications when it does not. This can have costly implications, as the company might accept defective goods.

To minimize Type I errors, statisticians set a significance level, denoted as alpha (\(\alpha\)). The typical values for \(\alpha\) are 0.05 or 0.01, representing a 5% or 1% chance of incorrectly rejecting the null hypothesis. Setting a lower \(\alpha\) decreases the likelihood of a Type I error, but may increase the chance of another error, known as a Type II error.
Type II Error
A Type II error is another kind of error that can occur during hypothesis testing. It happens when we fail to reject a false null hypothesis. In simple terms, it's like missing out on an "opportunity". For the company testing polyethylene sheaths, a Type II error would mean that they overlook the fact that the standard deviation is indeed less than 0.05 mm.

This error can lead to delayed actions or missed improvements, as the company might pass on an acceptable product under more stringent conditions unnecessarily. In this case, they may reject a satisfactory product believing it's not meeting standards, which could mean losing a valuable supplier.

The probability of a Type II error is denoted by beta (\(\beta\)). It is indirectly influenced by the choice of \(\alpha\). Striking a balance between \(\alpha\) and \(\beta\) is essential for designing tests that have sufficient power to detect true effects.
Null Hypothesis
The null hypothesis, denoted as \(H_0\), is the statement being tested in a hypothesis test. It represents the "status quo" or baseline scenario we aim to assess. In every hypothesis test, the null hypothesis assumes no effect or no difference.

For the polyethylene sheath thickness, the null hypothesis is that the standard deviation is equal to or greater than 0.05 mm (\(H_0: \sigma \geq 0.05\)). This hypothesis suggests that there isn't enough evidence to claim the quality meets the company's specific requirements.

The goal of hypothesis testing isn't necessarily to prove \(H_0\) is true, but rather to challenge this assumption by evaluating the data. By statistically testing \(H_0\), a company can determine if there is enough evidence to support an alternative claim.
Alternative Hypothesis
The alternative hypothesis, denoted as \(H_a\), is the statement we aim to support with evidence gathered. It's essentially the opposite of the null hypothesis, representing a new effect or difference that we suspect might be the case.

In the polyethylene sheaths example, the alternative hypothesis is that the standard deviation is less than 0.05 mm (\(H_a: \sigma < 0.05\)). It expresses the company's specific concern regarding sheath thickness consistency.

Supporting the alternative hypothesis means providing enough statistical evidence to suggest that \(H_0\) doesn't hold. If the data supports \(H_a\), the company can conclude with considerable confidence that their product specifications are met. Therefore, \(H_a\) is crucial because it defines the potential actionable insights or changes based on testing results.

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Most popular questions from this chapter

For the following pairs of assertions, indicate which do not comply with our rules for setting up hypotheses and why (the subscripts 1 and 2 differentiate between quantities for two different populations or samples): a. \(H_{0}: \mu=100, H_{\mathrm{a}}: \mu>100\) b. \(H_{0}: \sigma=20, H_{\mathrm{a}}: \sigma \leq 20\) c. \(H_{0}: p \neq .25, H_{\mathrm{a}}: p=.25\) d. \(H_{0}: \mu_{1}-\mu_{2}=25, H_{\mathrm{a}}: \mu_{1}-\mu_{2}>100\) e. \(H_{0}: S_{1}^{2}=S_{2}^{2}, H_{\mathrm{a}}: S_{1}^{2} \neq S_{2}^{2}\) f. \(H_{0}: \mu=120, H_{\mathrm{a}}: \mu=150\) g. \(H_{0}: \sigma_{1} / \sigma_{2}=1, H_{\mathrm{a}}: \sigma_{1} / \sigma_{2} \neq 1\) h. \(H_{0}: p_{1}-p_{2}=-.1, H_{\mathrm{a}}: p_{1}-p_{2}<-.1\)

Let \(\mu\) denote the mean reaction time to a certain stimulus. For a large- sample \(z\) test of \(H_{0}: \mu=5\) versus \(H_{\mathrm{a}}: \mu>5\), find the \(P\)-value associated with each of the given values of the \(z\) test statistic. a. \(1.42\) b. \(.90\) c. \(1.96\) d. \(2.48\) e. \(-.11\)

Minor surgery on horses under field conditions requires a reliable short-term anesthetic producing good muscle relaxation, minimal cardiovascular and respiratory changes, and a quick, smooth recovery with minimal aftereffects so that horses can be left unattended. The article "A Field Trial of Ketamine Anesthesia in the Horse" (Equine Vet. J., 1984: 176-179) reports that for a sample of \(n=73\) horses to which ketamine was administered under certain conditions, the sample average lateral recumbency (lying-down) time was \(18.86 \mathrm{~min}\) and the standard deviation was \(8.6 \mathrm{~min}\). Does this data suggest that true average lateral recumbency time under these conditions is less than \(20 \mathrm{~min}\) ? Test the appropriate hypotheses at level of significance . 10 .

The article "Orchard Floor Management Utilizing SoilApplied Coal Dust for Frost Protection" (Agri. and Forest Meteorology, 1988: 71-82) reports the following values for soil heat flux of eight plots covered with coal dust. \(\begin{array}{llllllll}34.7 & 35.4 & 34.7 & 37.7 & 32.5 & 28.0 & 18.4 & 24.9\end{array}\) The mean soil heat flux for plots covered only with grass is 29.0. Assuming that the heat-flux distribution is approximately normal, does the data suggest that the coal dust is effective in increasing the mean heat flux over that for grass? Test the appropriate hypotheses using \(\alpha=.05\).

A common characterization of obese individuals is that their body mass index is at least 30 [BMI \(=\) weight/(height \()^{2}\), where height is in meters and weight is in kilograms]. The article "The Impact of Obesity on Illness Absence and Productivity in an Industrial Population of Petrochemical Workers" (Annals of Epidemiology, 2008: 8-14) reported that in a sample of female workers, 262 had BMIs of less than 25,159 had BMIs that were at least 25 but less than 30 , and 120 had BMIs exceeding 30 . Is there compelling evidence for concluding that more than \(20 \%\) of the individuals in the sampled population are obese? a. State and test appropriate hypotheses using the rejection region approach with a significance level of \(.05\). b. Explain in the context of this scenario what constitutes type I and II errors c. What is the probability of not concluding that more than \(20 \%\) of the population is obese when the actual percentage of obese individuals is \(25 \%\) ?

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