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Show that the cdf \(F(x)\) is a nondecreasing function; that is, \(x_{1}

Short Answer

Expert verified
The CDF is nondecreasing because \( F(x_1) \leq F(x_2) \). Equality holds if there's no probability mass between \( x_1 \) and \( x_2 \).

Step by step solution

01

Understand the CDF

A cumulative distribution function (CDF), denoted as \( F(x) \), gives the probability that a random variable \( X \) is less than or equal to \( x \). Mathematically, it is represented as \( F(x) = P(X \leq x) \). The CDF ranges from 0 to 1, increasing as \( x \) increases.
02

Define the property to be proven

We need to demonstrate that for any two points \( x_1 < x_2 \), it holds that \( F(x_1) \leq F(x_2) \). This means that CDF is a nondecreasing function.
03

Consider two points \( x_1 \) and \( x_2 \)

Given that \( x_1 < x_2 \), we look at the probabilities \( P(X \leq x_1) \) and \( P(X \leq x_2) \). Because if an event is part of another event with more cases, its probability will be less than or equal to it.
04

Relate the probabilities

\( P(X \leq x_1) \) is a subset of \( P(X \leq x_2) \) due to \( x_1 < x_2 \). Therefore, \( F(x_1) = P(X \leq x_1) \leq P(X \leq x_2) = F(x_2) \), satisfying the condition \( F(x_1) \leq F(x_2) \).
05

Determine the condition for equality

For \( F(x_1) = F(x_2) \), the probability of \( X \) falling between \( x_1 \) and \( x_2 \) must be zero. This occurs when there is no probability mass between these two points, typically happening when \( x_1 \) and \( x_2 \) fall within a single jump in a discontinuous distribution or within a continuous segment of no probability in a mixed-type distribution.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

The Nature of Nondecreasing Functions
A nondecreasing function is one where the value of the function does not decrease as the input value increases. This means that for any two points \( x_1 \) and \( x_2 \) such that \( x_1 < x_2 \), the function value at \( x_1 \) is less than or equal to the function value at \( x_2 \).
For cumulative distribution functions (CDF), this nondecreasing nature is crucial. It ensures that as we move to higher values along the x-axis (i.e., considering larger possible outcomes for our random variable), the probability of the random variable being less than or equal to a given value increases or stays the same. This is because we are accumulating probability as we consider more possible outcomes. Thus, \( F(x) \) is inherently a nondecreasing function because probabilities accumulate and never decrease.
Understanding Probability
Probability measures the likelihood of a certain event occurring. The CDF \( F(x) = P(X \leq x) \) quantifies the probability that a random variable \( X \) is less than or equal to \( x \).
This concept of probability is fundamental when dealing with random variables since it encapsulates all possible outcomes of an experiment. For a continuous random variable, these probabilities are expressed as areas under the probability density function curve up to \( x \).
It's also essential to remember that probabilities range from 0 to 1, where 0 indicates impossibility and 1 indicates certainty. Hence, CDFs start from 0 and, at the end of their range, tend towards 1 as we include all possible values of the random variable.
The Role of Random Variables
A random variable is a numerical quantity whose value is subject to variations due to chance. In a CDF, random variables help in quantifying the variations and depict the likelihood of various outcomes.
In probability theory, we often categorize random variables as either discrete or continuous, affecting the shape of their respective distribution functions.
A random variable's CDF offers a comprehensive overview by summarizing these likelihoods up to any given point \( x \). This makes CDFs a powerful tool in statistics, as they tell us the probability a random variable takes a value less than or equal to \( x \), thus providing insights across entire distributions.
Continuous Distributions Explained
Continuous distributions describe random variables that can take any value within a specified range. One well-known example is the normal distribution.
CDFs of continuous distributions are especially important as they provide the probabilities associated with these ranges and are represented by smooth, nondecreasing curves.
Since continuous distributions deal with uncountably infinite outcomes, individual outcomes have zero probability. Instead, we focus on intervals and calculate probabilities within those ranges. This is why the probability of a random variable falling between two points, say \( x_1 \) and \( x_2 \), is determined by evaluating the CDF at these points: \( P(x_1 < X \leq x_2) = F(x_2) - F(x_1) \).
This interpretation is fundamental for statistical applications that involve forecasting, risk assessment, and decision making in environments of uncertainty.

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Most popular questions from this chapter

Airlines sometimes overbook flights. Suppose that for a plane with 50 seats, 55 passengers have tickets. Define the random variable \(Y\) as the number of ticketed passengers who actually show up for the flight. The probability mass function of \(Y\) appears in the accompanying table. \begin{tabular}{l|lllllllllll} \(y\) & 45 & 46 & 47 & 48 & 49 & 50 & 51 & 52 & 53 & 54 & 55 \\ \hline\(p(y)\) & \(.05\) & \(.10\) & \(.12\) & \(.14\) & 25 & \(.17\) & \(.06\) & \(.05\) & \(.03\) & \(.02\) & \(.01\) \end{tabular} a. What is the probability that the flight will accommodate all ticketed passengers who show up? b. What is the probability that not all ticketed passengers who show up can be accommodated? c. If you are the first person on the standby list (which means you will be the first one to get on the plane if there are any seats available after all ticketed passengers have been accommodated), what is the probability that you will be able to take the flight? What is this probability if you are the third person on the standby list?

Starting at a fixed time, each car entering an intersection is observed to see whether it turns left \((L)\), right \((R)\), or goes straight ahead \((A)\). The experiment terminates as soon as a car is observed to turn left. Let \(X=\) the number of cars observed. What are possible \(X\) values? List five outcomes and their associated \(X\) values.

Twenty percent of all telephones of a certain type are submitted for service while under warranty. Of these, \(60 \%\) can be repaired, whereas the other \(40 \%\) must be replaced with new units. If a company purchases ten of these telephones, what is the probability that exactly two will end up being replaced under warranty?

Suppose that the number of drivers who travel between a particular origin and destination during a designated time period has a Poisson distribution with parameter \(\mu=20\) (suggested in the article "Dynamic Ride Sharing: Theory and Practice," J. of Transp. Engr., 1997: 308-312). What is the probability that the number of drivers will a. Be at most 10 ? b. Exceed 20? c. Be between 10 and 20 , inclusive? Be strictly between 10 and 20 ? d. Be within 2 standard deviations of the mean value?

Suppose that \(p=P(\) male birth \()=.5\). A couple wishes to have exactly two female children in their family. They will have children until this condition is fulfilled. a. What is the probability that the family has \(x\) male children? b. What is the probability that the family has four children? c. What is the probability that the family has at most four children? d. How many male children would you expect this family to have? How many children would you expect this family to have?

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