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A concrete beam may fail either by shear \((S)\) or flexure \((F)\). Suppose that three failed beams are randomly selected and the type of failure is determined for each one. Let \(X=\) the number of beams among the three selected that failed by shear. List each outcome in the sample space along with the associated value of \(X\).

Short Answer

Expert verified
The sample space with associated X values: (SSS, 3), (SSF, 2), (SFS, 2), (FSS, 2), (SFF, 1), (FSF, 1), (FFS, 1), (FFF, 0).

Step by step solution

01

Understanding the Problem

We have three beams, and each can fail by either shear (S) or flexure (F). We need to determine the possible outcomes for these failures and count how many beams fail by shear for each outcome.
02

Constructing Outcomes in the Sample Space

List all possible combinations of shear (S) and flexure (F) failures for the three beams. The outcomes are: SSS, SSF, SFS, FSS, SFF, FSF, FFS, and FFF.
03

Assigning Values to X for Each Outcome

For each outcome, count the number of S's (shear failures). This will be the value of the random variable X. Assign values as follows: - SSS: X = 3 - SSF: X = 2 - SFS: X = 2 - FSS: X = 2 - SFF: X = 1 - FSF: X = 1 - FFS: X = 1 - FFF: X = 0.
04

Listing Outcomes with Associated Values of X

Now list the outcomes with their corresponding values of X: - (SSS, 3) - (SSF, 2) - (SFS, 2) - (FSS, 2) - (SFF, 1) - (FSF, 1) - (FFS, 1) - (FFF, 0).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Random Variables
A random variable is a concept within probability theory that assigns a numerical value to each outcome in a sample space. It helps us quantify the results of a random process. In the context of the original exercise about concrete beam failures, the random variable, labeled as \(X\), counts how many of the three randomly selected beams fail by shear. This allows us to transition from describing outcomes in words (like ‘SSS’ for three shear failures) to assigning a quantitative measure (such as \(X = 3\)). By doing so, we can more easily analyze and interpret the data.
For example:
  • If all three beams fail by shear, \(X = 3\).
  • If two beams fail by shear and one by flexure, \(X = 2\).
  • And if none fail by shear, \(X = 0\).
This facilitates calculations like determining probabilities for different numbers of shear failures. The random variable forms the basis for further statistical analysis and helps us understand the behavior of the system under study.
Sample Space
The sample space is the set of all possible outcomes in a probability experiment. In the beam failure exercise, the sample space consists of all possible combinations of shear and flexure failures. These outcomes represent each scenario of how the beams can fail. The sample space for the exercise consists of the following outcomes: SSS, SSF, SFS, FSS, SFF, FSF, FFS, and FFF.
Understanding the sample space is crucial because it allows us to account for every potential event that can occur. By listing all possible outcomes, we ensure that our analysis of the random variable \(X\) is complete. This is essential in probability theory, as overlooking even a single outcome can lead to incorrect conclusions.
Combinatorics
Combinatorics is a branch of mathematics concerned with counting, arranging, and analyzing possible combinations of items. It plays a fundamental role in constructing the sample space. In this exercise, combinatorics helps us determine how many different ways three beams can fail either by shear (S) or flexure (F).
The combination of each beam failing by either S or F gives us the sample space. Mathematically, since each beam has two possible outcomes and there are three beams, we have \(2^3 = 8\) possible combinations.
  • Examples of these combinations include (S, S, S), (S, S, F), (S, F, S), etc.
Combinatorics simplifies the process of enumerating these cases and is invaluable in many areas of probability theory. It allows us to systematically explore all potential arrangements and helps ensure a complete and accurate sample space.
Failure Analysis
Failure analysis in the context of this exercise involves examining the types and frequencies of failures among the beams. This is a key aspect of probability theory as it relates to understanding and predicting system performance under different conditions. Here, we focus specifically on failures by shear and what that implies for overall structural integrity.
Analyzing the data on shear failures allows engineers to assess risks and modify designs to prevent such occurrences. By using the values of \(X\), engineers can make informed decisions based on the likelihood of certain failure modes. If a high number of shear failures are observed, it might indicate a need for design reevaluation.
  • This can improve safety and reliability by addressing key weaknesses in a structure.
  • Failure analysis contributes to better resource allocation by focusing efforts on the most problematic areas.
Through exercises like these, students can learn how to apply probability theory to real-world scenarios, equipping them with tools to tackle practical engineering problems.

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Most popular questions from this chapter

Suppose that you read through this year's issues of the New York Times and record each number that appears in a news article-the income of a CEO, the number of cases of wine produced by a winery, the total charitable contribution of a politician during the previous tax year, the age of a celebrity, and so on. Now focus on the leading digit of each number, which could be \(1,2, \ldots, 8\), or 9 . Your first thought might be that the leading digit \(X\) of a randomly selected number would be equally likely to be one of the nine possibilities (a discrete uniform distribution). However, much empirical evidence as well as some theoretical arguments suggest an alternative probability distribution called Benford's law: \(p(x)=P(1\) st digit is \(x)=\log _{10}\left(\frac{x+1}{x}\right) \quad x=1,2, \ldots, 9\) a. Without computing individual probabilities from this formula, show that it specifies a legitimate pmf. b. Now compute the individual probabilities and compare to the corresponding discrete uniform distribution. c. Obtain the cdf of \(X\). d. Using the cdf, what is the probability that the leading digit is at most 3 ? At least 5 ? [Note: Benford's law is the basis for some auditing procedures used to detect fraud in financial reporting-for example, by the Internal Revenue Service.]

a. Show that \(b(x ; n, 1-p)=b(n-x, n, p)\). b. Show that \(B(x ; n, 1-p)=1-B(n-x-1 ; n, p)\). [Hint: At most \(x S\) s is equivalent to at least \((n-x) F\) s.] c. What do parts (a) and (b) imply about the necessity of including values of \(p\) greater than \(.5\) in Appendix Table A.1?

A very large batch of components has arrived at a distributor. The batch can be characterized as acceptable only if the proportion of defective components is at most .10. The distributor decides to randomly select 10 components and to accept the batch only if the number of defective components in the sample is at most 2 . a. What is the probability that the batch will be accepted when the actual proportion of defectives is .01? .05?.10? 20 ?.25? b. Let \(p\) denote the actual proportion of defectives in the batch. A graph of \(P\) (batch is accepted) as a function of \(p\), with \(p\) on the horizontal axis and \(P\) (batch is accepted) on the vertical axis, is called the operating characteristic curve for the acceptance sampling plan. Use the results of part (a) to sketch this curve for \(0 \leq p \leq 1\). c. Repeat parts (a) and (b) with " 1 " replacing " 2 " in the acceptance sampling plan. d. Repeat parts (a) and (b) with " 15 " replacing " \(10 "\) in the acceptance sampling plan. e. Which of the three sampling plans, that of part (a), (c), or (d), appears most satisfactory, and why?

An electronics store has received a shipment of 20 table radios that have connections for an iPod or iPhone. Twelve of these have two slots (so they can accommodate both devices), and the other eight have a single slot. Suppose that six of the 20 radios are randomly selected to be stored under a shelf where the radios are displayed, and the remaining ones are placed in a storeroom. Let \(X=\) the number among the radios stored under the display shelf that have two slots. a. What kind of a distribution does \(X\) have (name and values of all parameters)? b. Compute \(P(X=2), P(X \leq 2)\), and \(P(X \geq 2)\). c. Calculate the mean value and standard deviation of \(X\).

If the sample space \(S\) is an infinite set, does this necessarily imply that any rv \(X\) defined from \(\&\) will have an infinite set of possible values? If yes, say why. If no, give an example.

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