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A box contains six \(40-\mathrm{W}\) bulbs, five \(60-\mathrm{W}\) bulbs, and four \(75-\mathrm{W}\) bulbs. If bulbs are selected one by one in random order, what is the probability that at least two bulbs must be selected to obtain one that is rated \(75 \mathrm{~W}\) ?

Short Answer

Expert verified
The probability is \(\frac{11}{15}\).

Step by step solution

01

Determine Total Bulbs and Target

Firstly, calculate the total number of bulbs in the box: there are 6 bulbs rated at 40 W, 5 bulbs at 60 W, and 4 bulbs at 75 W. So, the total number of bulbs is \(6 + 5 + 4 = 15\). We are interested in finding the probability that at least two bulbs must be selected to get a 75 W bulb. This means the first bulb selected is not 75 W.
02

Calculate Probability of Not Selecting a 75 W Bulb First

The probability of not selecting a 75 W bulb with the first pick is the probability of picking either a 40 W or a 60 W bulb first. There are \(6 + 5 = 11\) non-75 W bulbs. Therefore, the probability of not picking a 75 W bulb first is \(\frac{11}{15}\).
03

Conclusion with Complementary Probability

Since we are interested in the event that at least two bulbs must be selected to get a 75 W bulb, the scenario complementary to selecting a 75 W bulb on the first try has occurred. Hence, no further calculations are necessary. Therefore, the probability that at least two bulbs must be selected is \(\frac{11}{15}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Random Selection
Random selection is a fundamental concept in probability that involves selecting items from a set without any preference or bias. In the context of the bulb selection problem, it means each bulb has an equal chance of being picked from the box. When we say the bulbs are selected in a random order, we mean that any bulb, regardless of its wattage, has the same likelihood of being chosen.
  • If there are 15 bulbs in total, each individual bulb has a probability of \( \frac{1}{15} \) of being selected first.
  • This ensures fairness in selection and is key to applying probability calculations correctly.
  • Understanding random selection is crucial as it ensures there is no bias in probability scenarios like games, lotteries, or in this case, picking light bulbs from a box.
This concept indicates that any predictions we make about the bulbs must account for this even chance at every stage of selection.
Bulb Selection Problem
The bulb selection problem presents a scenario where you want to determine the likelihood of a specific outcome while selecting bulbs. In this exercise, you're tasked with finding the probability of needing to pick more than one bulb to get a 75 W bulb.
The key steps to solving this problem are:
  • First, identify all types of bulbs and their quantities: 6 bulbs at 40 W, 5 bulbs at 60 W, and 4 bulbs at 75 W.
  • Total bulbs: 40 W and 60 W bulbs combined make up the non-target bulbs, which are 11 bulbs in total.
  • The objective is to find the probability of not drawing a 75 W bulb on the first try, which would necessitate multiple selections.
This problem requires a clear understanding of how to calculate probability based on the knowledge of different categories and their respective totals.
Complementary Probability
Complementary probability is used to solve problems by focusing on the opposite of the desired outcome.
Instead of calculating the probability of the desired event directly, you find the probability of the event not happening, and then use that to determine the probability of the desired outcome.
In the bulb selection problem, the goal was to find the chance that more than one bulb is needed to get a 75 W bulb. Instead of directly calculating this, we calculate the probability of not selecting a 75 W bulb first (which is the undesirable event). This complementary probability is found by calculating the chances of picking something other than a 75 W bulb first:
  • There are 11 non-75 W bulbs, giving a probability of \( \frac{11}{15} \) for the first pick being a non-75 W bulb.
By using complementary probability, it becomes much easier to solve complex problems without lengthy calculations. This technique is especially useful in real-world problems where the direct probability might be challenging to compute.

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Most popular questions from this chapter

In five-card poker, a straight consists of five cards with adjacent denominations (e.g., 9 of clubs, 10 of hearts, jack of hearts, queen of spades, and king of clubs). Assuming that aces can be high or low, if you are dealt a five-card hand, what is the probability that it will be a straight with high card 10? What is the probability that it will be a straight? What is the probability that it will be a straight flush (all cards in the same suit)?

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