/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 70 An aeronautical engineering stud... [FREE SOLUTION] | 91Ó°ÊÓ

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An aeronautical engineering student carried out an experiment to study how \(y=\) lift/drag ratio related to the variables \(x_{1}=\) position of a certain forward lifting surface relative to the main wing and \(x_{2}=\) tail placement relative to the main wing, obtaining the following data (Sratistics for Engineering Problem Solving, p. 133): \begin{tabular}{lcc} \(\boldsymbol{x}_{1}(\mathbf{i n .})\) & \(\boldsymbol{x}_{2}(\mathbf{i n} .)\) & \(\boldsymbol{y}\) \\ \hline\(-1.2\) & \(-1.2\) & \(.858\) \\ \(-1.2\) & 0 & \(3.156\) \\ \(-1.2\) & \(1.2\) & \(3.644\) \\ 0 & \(-1.2\) & \(4.281\) \\ 0 & 0 & \(3.481\) \\ 0 & \(1.2\) & \(3.918\) \\ \(1.2\) & \(-1.2\) & \(4.136\) \\ \(1.2\) & 0 & \(3.364\) \\ \(1.2\) & \(1.2\) & \(4.018\) \\ & & \(\bar{y}=3.428, \mathrm{SST}=8.55\) \end{tabular} a. Fitting the first-order model gives \(\mathrm{SSE}=5.18\), whereas including \(x_{3}=x_{1} x_{2}\) as a predictor results in \(\mathrm{SSE}=3.07\). Calculate and interpret the coefficient of multiple determination for each model. b. Carry out a test of model utility using \(\alpha=.05\) for each of the models described in part (a). Does either result surprise you?

Short Answer

Expert verified
The first-order model explains 39.4% of variance, the interaction model 64.1%. Only the interaction model is significant at \( \alpha = 0.05 \).

Step by step solution

01

Understand the Problem

We have a dataset that relates the lift/drag ratio (\( y \)) to two variables: position of a forward lifting surface (\( x_1 \)) and tail placement relative to the main wing (\( x_2 \)). We are to fit two models and analyze them: first-order and interaction (including \( x_3 = x_1x_2 \)). We calculate and interpret the coefficients of multiple determination \( R^2 \). We also test each model's utility with a significance level of \( \alpha = 0.05 \).
02

Calculate R-squared for the First-Order Model

The coefficient of multiple determination, \( R^2 \), is computed as \( R^2 = 1 - \frac{\text{SSE}}{\text{SST}} \). For the first-order model, \( \text{SSE} = 5.18 \) and \( \text{SST} = 8.55 \). Substitute these values to calculate \( R^2 \). \[R^2 = 1 - \frac{5.18}{8.55} = 0.394 \] This means that approximately 39.4% of the variability in \( y \) is explained by the first-order model.
03

Calculate R-squared for the Interaction Model

For the interaction model, \( \text{SSE} = 3.07 \). Use the same formula to compute \( R^2 \). \[R^2 = 1 - \frac{3.07}{8.55} = 0.641\]This indicates that 64.1% of the variability in \( y \) is explained by the interaction model.
04

Conduct Model Utility Test for the First-Order Model

To test the utility of the first-order model, compute the F-statistic: \[F = \frac{\frac{(\text{SST} - \text{SSE})}{p}}{\frac{\text{SSE}}{n-p-1}} \]where \( p \) is the number of predictors, \( n \) is the total number of observations. Here, \( p = 2 \) and \( n = 9 \).\[F = \frac{\frac{(8.55 - 5.18)}{2}}{\frac{5.18}{9-2-1}} = 2.958\]The critical F-value from the F-distribution table at \( \alpha=0.05 \), \( df1 = 2, df2 = 6 \) is approximately 5.14. Since 2.958 < 5.14, the model utility is not significant.
05

Conduct Model Utility Test for the Interaction Model

Similarly, compute the F-statistic for the interaction model where \( p = 3 \):\[F = \frac{\frac{(8.55 - 3.07)}{3}}{\frac{3.07}{9-3-1}} = 5.237\]The critical F-value from the F-distribution table at \( \alpha=0.05 \), \( df1 = 3, df2 = 5 \) is approximately 4.76. Since 5.237 > 4.76, the interaction model is significant.
06

Interpretation of Results

For the first-order model, the test shows a lack of significance, indicating the model's predictors do not adequately explain the variance in lift/drag ratio. In contrast, the interaction model is significant, suggesting the inclusion of the interaction term \( x_3 \) meaningfully improves the model fit. Despite the relatively higher SSE, the interactive model captures interactions between lift surface position and tail placement that are crucial to explaining the lift/drag ratio.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coefficient of Determination
When evaluating the efficiency of a regression model, the Coefficient of Determination, commonly denoted as \( R^2 \), plays a crucial role. This coefficient tells us the proportion of the variance in the dependent variable, in this case, the lift/drag ratio \( y \), that can be explained by the independent variables in the model. In simpler terms, \( R^2 \) measures how well our chosen variables can predict the behavior of \( y \).

To calculate \( R^2 \), we use the formula: \[ R^2 = 1 - \frac{\text{SSE}}{\text{SST}} \] where SST is the total sum of squares, representing the total variation in \( y \), and SSE is the sum of squared errors, which accounts for the unexplained variance by the model.

For the first-order model (without interaction), with SSE of 5.18 and SST of 8.55, the \( R^2 \) comes out to be 0.394. This means that the model explains approximately 39.4% of the variability in the lift/drag ratio, leaving the rest unexplained. When we add the interaction term \( x_3 = x_1x_2 \), the SSE drops to 3.07, increasing \( R^2 \) to 0.641. Hence, the interaction model explains 64.1% of the variance, showing a significant improvement in prediction power.

The larger the value of \( R^2 \), the better the model fits the data. In this case, adding the interaction term greatly enhances the model's explanatory power.
Interaction Model
An interaction model in regression analysis incorporates both the main effects of the predictors and the interaction between them. The term interaction refers to the scenario where the effect of one independent variable on the dependent variable changes depending on the level of another independent variable.

In our aeronautical engineering experiment, the interaction model includes an additional term \( x_3 = x_1 x_2 \). This interaction term is crucial because it captures the combined effects of the position of the forward lifting surface and the tail placement relative to the main wing. By considering the interaction between these two variables, we can uncover relationships that aren't apparent when observing them independently.

Using an interaction model is particularly useful when you suspect that the relationship between the predictors and the outcome variable is not merely additive. For instance, the effect of the tail placement \( x_2 \) on lift/drag ratio \( y \) might be stronger when the forward lifting surface \( x_1 \) is at a specific position. Incorporating \( x_3 \) helps in better capturing such nuances.

In this example, introducing the interaction term reduced the sum of squared errors from 5.18 to 3.07, evidenced by a higher \( R^2 \) in the interaction model. This clearly illustrates the value and insight gained by modeling these variables together rather than in isolation.
Model Utility Test
The model utility test is used to determine whether a regression model provides significant predictions for the dependent variable from the independent variables. Essentially, this test helps us confirm if the model is useful.

To perform this test, we use an F-statistic calculated from the ratio of explained variance by the model to the unexplained variance. This formula is: \[ F = \frac{\frac{(\text{SST} - \text{SSE})}{p}}{\frac{\text{SSE}}{n-p-1}} \] where \( p \) is the number of predictors, and \( n \) is the total number of observations.

For the first-order model, the F-statistic calculated was 2.958, which is less than the critical F-value of 5.14 for a significance level \( \alpha = 0.05 \). This result suggests that the predictors in the first-order model do not provide a significant explanation of the variance in lift/drag ratio. In other words, the model might not be very useful in its current form.

Conversely, the interaction model significantly improves the prediction capability, with an F-statistic of 5.237, surpassing the critical value of 4.76. Therefore, the interaction model is considered significant and useful for explaining the variability in the data.

In summary, a model utility test is crucial in regression analysis to gauge whether the models are effective, highlighting the importance and value added by including an interaction term in this particular analysis.

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Most popular questions from this chapter

Feature recognition from surface models of complicated parts is becoming increasingly important in the development of efficient computer-aided design (CAD) systems. The article "A Computationally Efficient Approach to Feature Abstraction in Design-Manufacturing Integration" (J. of Engr: for Industry, 1995: 16-27) contained a graph of logadtotal recognition time), with time in sec, versus \(\log _{10}\) (number of edges of a part), from which the following representative values were read: \(\begin{array}{lrrrrrr}\text { Log(edges) } & 1.1 & 1.5 & 1.7 & 1.9 & 2.0 & 2.1 \\ \text { Log(time) } & .30 & .50 & .55 & .52 & .85 & .98 \\ \text { Log(edges) } & 2.2 & 2.3 & 2.7 & 2.8 & 3.0 & 3.3 \\ \text { Log(time) } & 1.10 & 1.00 & 1.18 & 1.45 & 1.65 & 1.84 \\ \text { Log(edges) } & 3.5 & 3.8 & 4.2 & 4.3 & & \\ \text { Log(time) } & 2.05 & 2.46 & 2.50 & 2.76 & & \end{array}\) a. Does a scatter plot of \(\log (\) time \()\) versus \(\log (\) edges) suggest an approximate linear relationship between these two variables? b. What probabilistic model for relating \(y=\) recognition time to \(x=\) number of edges is implied by the simple linear regression relationship between the transformed variables? c. Summary quantities calculated from the data are $$ \begin{aligned} &n=16 \quad \Sigma x_{i}^{\prime}=42.4 \quad \Sigma y_{i}^{\prime}=21.69 \\ &\Sigma\left(x_{i}^{\prime}\right)^{2}=126.34 \quad \Sigma\left(y_{i}^{\prime}\right)^{2}=38.5305 \\ &\Sigma x_{i}^{\prime} y_{i}^{\prime}=68.640 \end{aligned} $$ Calculate estimates of the parameters for the model in part (b), and then obtain a point prediction of time when the number of edges is 300 .

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