/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 47 Efficient design of certain type... [FREE SOLUTION] | 91Ó°ÊÓ

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Efficient design of certain types of municipal waste incinerators requires that information about energy content of the waste be available. The authors of the article "Modeling the Energy Content of Municipal Solid Waste Using Multiple Regression Analysis" (J. of the Air and Waste Mgmnt. Assoc., 1996: 650-656) kindly provided us with the accompanying data on \(y=\) energy content (kcal/ \(\mathrm{kg}\) ), the three physical composition variables \(x_{1}=\%\) plastics by weight, \(x_{2}=\%\) paper by weight, and \(x_{3}=\%\) garbage by weight, and the proximate analysis variable \(x_{4}=\%\) moisture by weight for waste specimens obtained from a certain region. a. Interpret the values of the estimated regression coefficients \(\hat{\beta}_{1}\) and \(\hat{\beta}_{4}\). b. State and test the appropriate hypotheses to decide whether the model fit to the data specifies a useful linear relationship between energy content and at least one of the four predictors. c. Given that \(\%\) plastics, \(\%\) paper, and \(\%\) water remain in the model, does \% garbage provide useful information about energy content? State and test the appropriate hypotheses using a significance level of .05. d. Use the fact that \(s_{\hat{Y}}=7.46\) when \(x_{1}=20, x_{2}=25\), \(x_{3}=40\), and \(x_{4}=45\) to calculate a \(95 \%\) confidence interval for true average energy content under these circumstances. Does the resulting interval suggest that mean energy content has been precisely estimated? e. Use the information given in part (d) to predict energy content for a waste sample having the specified characteristics, in a way that conveys information about precision and reliability.

Short Answer

Expert verified
Perform regression analysis and hypothesis tests for predictors, specifically interpreting coefficients and confidence intervals.

Step by step solution

01

Interpreting Coefficients

To interpret the coefficients \( \hat{\beta}_{1} \) and \( \hat{\beta}_{4} \), we consider what each coefficient represents in a multiple regression model. \( \hat{\beta}_{1} \) is the estimated change in energy content (kcal/kg) for each additional percent of plastics by weight, holding other variables constant. \( \hat{\beta}_{4} \) represents the change in energy content for each additional percent of moisture by weight, holding other variables constant.
02

Hypothesis Testing for the Model

We perform an F-test to determine if the model provides a better fit than a model with no predictors. The null hypothesis \( H_0 \) states that all the regression coefficients are zero (\( \beta_{1} = \beta_{2} = \beta_{3} = \beta_{4} = 0 \)), while the alternative hypothesis \( H_a \) is that at least one coefficient is non-zero. We compute the F-statistic and compare it against a critical value or use the p-value. If the p-value is less than 0.05, we reject \( H_0 \), indicating the model specifies a useful relationship.
03

Testing the Value of Garbage Predictor

To determine the usefulness of \( x_{3} \) (\% garbage), we perform a t-test for the coefficient \( \hat{\beta}_{3} \). The null hypothesis \( H_0 \) is \( \beta_{3} = 0 \) (no effect), against the alternative \( H_a \), \( \beta_{3} eq 0 \). Using the standard error of \( \hat{\beta}_{3} \) and the t-statistic, we calculate the p-value. If the p-value is less than 0.05, we reject \( H_0 \), suggesting \% garbage has a significant impact on energy content.
04

Calculating 95% Confidence Interval

Given \( s_{\hat{Y}} = 7.46 \), confidence interval for true mean energy content is \( \hat{Y} \pm t_{\alpha/2, n-k-1} \times s_{\hat{Y}} \), where \( \hat{Y} \) is the predicted energy, \( t_{\alpha/2, n-k-1} \) is the t-value for \( 95\% \) confidence, and \( n \) is sample size. Substitute the given values to compute the interval. If the range is narrow, it suggests precise estimates of mean energy content.
05

Predicting Energy Content with Prediction Interval

To predict energy content for a new sample, calculate \( \hat{Y} \), the predicted value, and derive a prediction interval instead of just a point estimate. Use \( \hat{Y} \pm t_{\alpha/2, n-k-1} \times s_{\text{pred}} \), where \( s_{\text{pred}} \) considers both estimate variance and additional uncertainty for new predictions. A narrow interval indicates high precision and reliability in prediction.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Energy Content Prediction
Energy content prediction in the context of municipal waste is about estimating how much energy can be derived from various types of waste. Multiple regression analysis is a common tool used for this purpose.
It helps us understand how different characteristics of waste contribute to its overall energy content.

Imagine you have information about the percentage of plastics, paper, garbage, and moisture in waste samples. Each of these components affects the energy content differently. By using multiple regression analysis, you create a model that can predict the energy content from these variables.
This model includes coefficients for each variable, which show how much the energy content changes for a one-unit increase in the respective waste component, while keeping all other factors constant.

For instance, if you increase the percentage of plastics in a waste sample, the energy content might go up or down, depending on the coefficient. Similarly, moisture usually lowers the energy content, which is indicated by a negative coefficient for the moisture variable.
This way, the model allows for precise predictions based on the waste composition.
Hypothesis Testing
Hypothesis testing in multiple regression analysis helps us determine the usefulness of a model. It answers the question: Does the relationship between the variables and the energy content really exist, or is it just due to random variation?

We commonly set up a null hypothesis \( H_0 \) suggesting there’s no relationship, meaning all coefficients are zero. Against this, an alternative hypothesis \( H_a \) proposes that at least one coefficient is significantly different from zero, indicating a real relationship.
By performing an F-test, we obtain a p-value, which tells us the probability the observed data fits into the null hypothesis.
If this p-value is below a certain significance level (often 0.05), we reject the null hypothesis, meaning our model with its variables offers a better fit than a model without them.

This statistical procedure assures us that the links we observe in our data are reliable and not mere random occurrences.
Confidence Intervals
Confidence intervals provide a range within which we expect the true mean energy content to fall, given our prediction. They give us a measure of precision and reliability.
When you're estimating the mean energy content of waste under specific conditions, calculate the confidence interval using the standard error of prediction \( s_{\hat{Y}} \). This is given by \( \hat{Y} \pm t_{\alpha/2, n-k-1} \times s_{\hat{Y}} \), where \( \hat{Y} \) is the predicted energy content.
The term \( t_{\alpha/2, n-k-1} \) corresponds to the t-value for the desired confidence level (like 95%) with the appropriate degrees of freedom.

If the confidence interval is narrow, this suggests that the model’s estimates are precise.
Such intervals help us not just in understanding where the true average energy content lies but also in determining how much we should trust our model's predictions.
Moreover, for future predictions, utilize prediction intervals. They are similar to confidence intervals but consider more variability, thus being wider, to account for additional uncertainty related to new data.

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Most popular questions from this chapter

Let \(y=\) wear life of a bearing, \(x_{1}=\) oil viscosity, and \(x_{2}=\) load. Suppose that the multiple regression model relating life to viscosity and load is $$ Y=125.0+7.75 x_{1}+.0950 x_{2}-.0090 x_{1} x_{2}+\epsilon $$ a. What is the mean value of life when viscosity is 40 and load is 1100 ? b. When viscosity is 30 , what is the change in mean life associated with an increase of 1 in load? When viscosity is 40 , what is the change in mean life associated with an increase of 1 in load?

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A plot in the article "Thermal Conductivity of Polyethylene: The Effects of Crystal Size, Density, and Orientation on the Thermal Conductivity" (Polymer Engr: and Science, 1972: 204-208) suggests that the expected value of thermal conductivity \(y\) is a linear function of \(10^{4} \cdot 1 / x\), where \(x\) is lamellar thickness. \begin{tabular}{l|rrrrrrrr} \(x\) & 240 & 410 & 460 & 490 & 520 & 590 & 745 & 8300 \\ \hline\(y\) & \(12.0\) & \(14.7\) & \(14.7\) & \(15.2\) & \(15.2\) & \(15.6\) & \(16.0\) & \(18.1\) \end{tabular} a. Estimate the parameters of the regression function and the regression function itself. b. Predict the value of thermal conductivity when lamellar thickness is \(500 \AA \AA\).

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