/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 6 A study of the relationship betw... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A study of the relationship between age and various visual functions (such as acuity and depth perception) reported the following observations on the area of scleral lamina \(\left(\mathrm{mm}^{2}\right)\) from human optic nerve heads ("Morphometry of Nerve Fiber Bundle Pores in the Optic Nerve Head of the Human," Experimental Eye Research, 1988: 559-568): \(\begin{array}{lllllllll}2.75 & 2.62 & 2.74 & 3.85 & 2.34 & 2.74 & 3.93 & 4.21 & 3.88 \\ 4.33 & 3.46 & 4.52 & 2.43 & 3.65 & 2.78 & 3.56 & 3.01 & \end{array}\) a. Calculate \(\sum x_{i}\) and \(\sum x_{i}^{2}\). b. Use the values calculated in part (a) to compute the sample variance \(s^{2}\) and then the sample standard deviation \(s\).

Short Answer

Expert verified
\(\sum x_i = 56.80\), \(\sum x_i^2 = 199.4247\), sample variance \(s^2 = 0.5964\), standard deviation \(s \approx 0.7722\).

Step by step solution

01

Identify and List Observations

First, let's write down all the observations provided: 2.75, 2.62, 2.74, 3.85, 2.34, 2.74, 3.93, 4.21, 3.88, 4.33, 3.46, 4.52, 2.43, 3.65, 2.78, 3.56, 3.01.
02

Calculate Sum of Observations

We need to calculate \(\sum x_i\), the sum of all observations. Add together all the observations: \[2.75 + 2.62 + 2.74 + 3.85 + 2.34 + 2.74 + 3.93 + 4.21 + 3.88 + 4.33 + 3.46 + 4.52 + 2.43 + 3.65 + 2.78 + 3.56 + 3.01 = 56.80\]
03

Calculate Sum of Squares of Observations

Next, calculate \(\sum x_i^2\), the sum of the squares of each observation:\[2.75^2 + 2.62^2 + 2.74^2 + 3.85^2 + 2.34^2 + 2.74^2 + 3.93^2 + 4.21^2 + 3.88^2 + 4.33^2 + 3.46^2 + 4.52^2 + 2.43^2 + 3.65^2 + 2.78^2 + 3.56^2 + 3.01^2 = 199.4247\]
04

Compute the Sample Variance

Use the formula for sample variance:\[s^2 = \frac{\sum x_i^2 - \frac{(\sum x_i)^2}{n}}{n - 1}\]Substituting the values:\[s^2 = \frac{199.4247 - \frac{56.8^2}{17}}{16} = \frac{199.4247 - 189.8824}{16} = \frac{9.5423}{16} = 0.5964\]
05

Calculate the Sample Standard Deviation

The sample standard deviation is the square root of the sample variance:\[s = \sqrt{s^2} = \sqrt{0.5964} \approx 0.7722\]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Second Moment
In the world of statistics and data analysis, the second moment of a set of observations is a crucial concept. It is often described as a measure of the distribution's variance about the mean. The second moment is closely linked to the calculation of variance, an essential part of assessing variability within a dataset. In mathematical terms,
  • The first moment is the mean, which captures the average value of the data points.
  • The second moment, hence, involves squaring the deviations of each data point from the mean, amplifying deviations further from the mean.
The second moment helps in understanding the spread or dispersion of the data. It becomes foundational in calculating the sample variance, often represented by the symbol \( s^2 \). This squared deviation provides insight into whether data values are close to the mean or widely spread out.
Data Analysis
Data analysis is the systematic approach of evaluating data using analytical and statistical tools. In our exercise about scleral lamina area observations from human optic nerve heads, data analysis allows us to derive meaningful conclusions and patterns.

To conduct effective data analysis, it's important to follow these steps:
  • Data Collection: Gathering accurate data, such as the measurements provided in the exercise.
  • Organization: Arranging the data systematically to facilitate efficient analysis and computation.
  • Computation: Performing calculations like the sum of observations and the sum of squares, key to our variance and standard deviation analysis.
  • Interpretation: Deciphering the results to make informed decisions or predictions.
Through proper data analysis, we turn raw data into insightful information, uncovering underlying trends and variability.
Standard Deviation
In statistical computation, standard deviation is a vital measure used to quantify the amount of variation or dispersion in a set of data values. It expresses the average distance of each observation from the mean, providing a clear picture of the dataset's spread.

The sample standard deviation, \( s \), is calculated directly from the sample variance, \( s^2 \), by taking its square root:
  • Variance measures the squared average deviation of each value from the mean.
  • Standard deviation, being the square root of variance, returns to the original units of measurement, which makes it easier to interpret.
  • In our exercise, the sample standard deviation of approximately 0.7722 indicates the typical deviation of scleral lamina areas from their mean value.
Calculating the standard deviation aids in understanding how spread out the observations are, which is crucial for comparing variations across different datasets.
Statistical Computation
Statistical computation involves using mathematical tools and formulas to process and derive information from data. In the context of our exercise with scleral lamina areas, several statistical computations were performed to analyze and interpret the data.

The key computational steps include:
  • Adding the data points to obtain the sum, \( \sum x_i \).
  • Squaring each data point, then summing these squares to get \( \sum x_i^2 \).
  • Applying the formula for sample variance: \( s^2 = \frac{\sum x_i^2 - \frac{(\sum x_i)^2}{n}}{n - 1} \).
  • Finally, deriving the sample standard deviation as the square root of the sample variance.
These computations not only provide summary statistics but are also foundational for further statistical analysis such as hypothesis testing and regression.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The accompanying specific gravity values for various wood types used in construction appeared in the article "Bolted Connection Design Values Based on European Yield Model" (J. of Structural Engr., 1993: 2169-2186): \(\begin{array}{lllllllll}.31 & .35 & .36 & .36 & .37 & .38 & .40 & .40 & .40 \\\ .41 & .41 & .42 & .42 & .42 & .42 & .42 & .43 & .44 \\ .45 & .46 & .46 & .47 & .48 & .48 & .48 & .51 & .54 \\ .54 & .55 & .58 & .62 & .66 & .66 & .67 & .68 & .75\end{array}\) Construct a stem-and-leaf display using repeated stems (see the previous exercise), and comment on any interesting features of the display.

Let \(\bar{x}_{n}\) and \(s_{n}^{2}\) denote the sample mean and variance for the sample \(x_{1}, \ldots, x_{n}\) and let \(\bar{x}_{n+1}\) and \(s_{n+1}^{2}\) denote these quantities when an additional observation \(x_{n+1}\) is added to the sample. a. Show how \(\bar{x}_{n+1}\) can be computed from \(\bar{x}_{n}\) and \(x_{n+1^{*}}\). b. Show that $$ n s_{n+1}^{2}=(n-1) s_{n}^{2}+\frac{n}{n+1}\left(x_{n+1}-\bar{x}_{n}\right)^{2} $$ so that \(s_{n+1}^{2}\) can be computed from \(x_{n+1}, \bar{x}_{n}\), and \(s_{n}^{2}\) c. Suppose that a sample of 15 strands of drapery yarn has resulted in a sample mean thread elongation of \(12.58 \mathrm{~mm}\) and a sample standard deviation of \(512 \mathrm{~mm}\). A \(16^{\text {th }}\) strand results in an elongation value of \(11.8\). What are the values of the sample mean and sample standard deviation for all 16 elongation observations?

Fire load \(\left(\mathrm{MJ} / \mathrm{m}^{2}\right)\) is the heat energy that could be released per square meter of floor area by combustion of contents and the structure itself. The article "Fire Loads in Office Buildings" ( \(J\). of Structural Engr., 1997: 365-368) gave the following cumulative percentages (read from a graph) for fire loads in a sample of 388 rooms: \(\begin{array}{lrrrrr}\text { Value } & 0 & 150 & 300 & 450 & 600 \\ \text { Cumulative \% } & 0 & 19.3 & 37.6 & 62.7 & 77.5 \\ \text { Value } & 750 & 900 & 1050 & 1200 & 1350 \\ \text { Cumulative \% } & 87.2 & 93.8 & 95.7 & 98.6 & 99.1 \\ \text { Value } & 1500 & 1650 & 1800 & 1950 & \\ \text { Cumulative \% } & 99.5 & 99.6 & 99.8 & 100.0 & \end{array}\) a. Construct a relative frequency histogram and comment on interesting features. b. What proportion of fire loads are less than 600 ? At least \(1200 ?\) c. What proportion of the loads are between 600 and 1200 ?

The article "Oxygen Consumption During Fire Suppression: Error of Heart Rate Estimation" (Ergonomics, 1991: 1469-1474) reported the following data on oxygen consumption ( \(\mathrm{mL} / \mathrm{kg} / \mathrm{min})\) for a sample of ten firefighters performing a fire-suppression simulation: \(\begin{array}{llllllllll}29.5 & 49.3 & 30.6 & 28.2 & 28.0 & 26.3 & 33.9 & 29.4 & 23.5 & 31.6\end{array}\) Compute the following: a. The sample range b. The sample variance \(s^{2}\) from the definition (i.e., by first computing deviations, then squaring them, etc.) c. The sample standard deviation d. \(s^{2}\) using the shortcut method

a. Let \(a\) and \(b\) be constants and let \(y_{i}=a x_{i}+b\) for \(i=1,2, \ldots, n\). What are the relationships between \(\bar{x}\) and \(\bar{y}\) and between \(s_{x}^{2}\) and \(s_{y}^{2}\) ? b. A sample of temperatures for initiating a certain chemical reaction yielded a sample average \(\left({ }^{\circ} \mathrm{C}\right)\) of \(87.3\) and a sample standard deviation of \(1.04\). What are the sample average and standard deviation measured in \({ }^{\circ} \mathrm{F}\) ? [Hint: $$ F=\frac{9}{5} C+32 \text {.] } $$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.