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The May 1, 2009 issue of The Montclarian reported the following home sale amounts for a sample of homes in Alameda, CA that were sold the previous month ( 1000 s of \(\$$ ): \)\begin{array}{llllllllll}590 & 815 & 575 & 608 & 350 & 1285 & 408 & 540 & 555 & 679\end{array}\( a. Calculate and interpret the sample mean and median. b. Suppose the \)6^{\text {th }}\( observation had been 985 rather than 1285 . How would the mean and median change? c. Calculate a \)20 \%\( trimmed mean by first trimming the two smallest and two largest observations. d. Calculate a \)15 \%$ trimmed mean.

Short Answer

Expert verified
Mean is 640.5, median is 582.5. With the altered value, mean is 610.5, median unchanged. 20% trimmed mean is 591.17, same for 15% due to rounding.

Step by step solution

01

List and Sort the Data for Part (a)

List the sale amounts: 590, 815, 575, 608, 350, 1285, 408, 540, 555, 679. Now, sort the data in ascending order: 350, 408, 540, 555, 575, 590, 608, 679, 815, 1285.
02

Calculate the Sample Mean for Part (a)

Sum all of the sale amounts: \(350 + 408 + 540 + 555 + 575 + 590 + 608 + 679 + 815 + 1285 = 6405\). Divide by the number of sales (10) to find the mean: \(\frac{6405}{10} = 640.5\).
03

Determine the Median for Part (a)

For an even number of observations, the median is the average of the two middle numbers (the 5th and 6th values): \(\frac{575 + 590}{2} = 582.5\).
04

Adjust Observation and Recalculate Mean of Part (b)

Replace the 6th sale amount of 1285 with 985. Recalculate the mean: Sum is now \(6405 - 1285 + 985 = 6105\), and the mean becomes \(\frac{6105}{10} = 610.5\).
05

Recalculate Median after Observation Change of Part (b)

Since the sorted sequence is unchanged by the update in the 6th spot's value, the median stays \(582.5\).
06

Calculate the 20% Trimmed Mean for Part (c)

For two smallest and two largest numbers: drop 350, 408, 815, 1285. New set is: 540, 555, 575, 590, 608, 679. Sum these: \(3547\). Divide by 6 (remaining numbers): \(\frac{3547}{6} \approx 591.17\).
07

Calculate 15% Trimmed Mean for Part (d)

Trim 1.5 smallest and 1.5 largest, make it closest integer: drop 350, 408, 815, 1285. Use the same set: 540, 555, 575, 590, 608, 679. The trimmed mean is the same as before: \(591.17\) (since fewer than one more element per side rounded to integer).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Mean
The sample mean is a statistical measure that provides the average value of a data set. It's computed by summing all the values in a sample and then dividing by the number of observations.
For example, with home sale amounts of 590, 815, 575, 608, 350, 1285, 408, 540, 555, and 679 (in thousands), the sample mean is calculated by summing all these amounts to get 6405, and then dividing by the total number of sales, which is 10.
This results in a sample mean of 640.5.
The sample mean is useful because it gives a central point around which the data is spread. It's important to remember that the mean is sensitive to outliers, as it is affected by unusually large or small values, like 1285 in our data set. Therefore, while it provides a useful average, it may sometimes misrepresent a data set with extreme values.
Sample Median
The sample median is another measure of central tendency, which represents the middle value in a sorted data set. Unlike the mean, the median is less influenced by outliers.
To find the median, the data must be arranged in ascending order.
  • For an odd number of observations, the median is the middle number.
  • For an even number of observations, like in our sorted home sale amounts (350, 408, 540, 555, 575, 590, 608, 679, 815, 1285), the median is the average of the two middle numbers.
In this set, the fifth and sixth values are 575 and 590.
So, the median is calculated as \[ \frac{575 + 590}{2} = 582.5 \]
The sample median is particularly helpful in skewed distributions or when data contains outliers, as it provides a more representative measure of the central tendency in such scenarios.
Trimmed Mean
The trimmed mean is a variant of the traditional mean, which provides an average after removing a certain percentage of the smallest and largest values in a data set. This approach reduces the effect of outliers, providing a more robust measure.
  • To calculate a 20% trimmed mean in the provided exercise, the two smallest (350, 408) and two largest (815, 1285) values are removed.
  • The remaining data are 540, 555, 575, 590, 608, and 679.
They sum to 3547. Dividing this sum by the number of remaining data points (6), we get a trimmed mean of \[ \frac{3547}{6} \approx 591.17 \]
The 15% trimmed mean, similarly in this context, involves trimming 1.5, which would result in rounding and coincidentally keeps the same trimmed values, leading to the same trimmed mean of 591.17.
This method is valuable for mitigating the impact of outliers on the mean, thereby reflecting a more accurate central tendency for skewed data collections.
Data Analysis
Data analysis involves collecting, organizing, and interpreting raw data to discover useful information and inform conclusions. In the context of home sale amounts, different statistical measures—like the mean, median, and trimmed mean—help in understanding the market tendencies more clearly.
Analyzing data through these measures allows for a deeper insight into the real estate market values:
  • The **mean** reveals the average transaction size.
  • The **median** provides the central point, which is often more representative in skewed data sets.
  • The **trimmed mean** offers a balanced view by minimizing outliers' influence.
By using all of these methods, one can thoroughly understand the nuances of pricing and sales trends, ensuring a comprehensive data analysis.
Understanding these concepts is crucial as real-world data often contain anomalies or are not perfectly symmetric, and different methods may be required to extract meaningful insights.

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