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In Example 5.3.2, compute the probability that all 10 successful patients appear in the subsample of size 11 from the Placebo group.

Short Answer

Expert verified

\(8.39 \times {10^{ - 8}}.\)

Step by step solution

01

Given information

The given example is:

Consider the patients in the clinical trial

whose results are tabulated in Table 2.1. We might need to re-examine a subset of the patients in the placebo group. Suppose that we need to sample 11 distinct patients from the 34 patients in that group.

What is the distribution of the number of successes (no relapse) that we obtain in the sub sample?

Let X stand for the number of successes in the sub sample. Table 2.1 indicates that there are 10 successes and 24 failures in the placebo group. According to the definition of the hyper geometric distribution, X has the hypergeometric distribution with parameters A = 10, B = 24, and n = 11. In particular, the possible values of X are the integers from 0 to 10. Even though we sample 11 patients, we cannot observe 11 successes, since only 10 successes are available.

02

Define the pdf

Here, as noted, X follows a hypergeometric distribution \(X \sim Hyp\left( {A = 10,B = 24,n = 11} \right)\)

Therefore, the pdf is,

\(p\left( x \right) = \frac{{{}^{10}{C_x}{}^{24}{C_{11 - x}}}}{{{}^{34}{C_{11}}}},x = 0,1,2, \ldots ,10\)

03

Calculate the desired probability value

The probability that all 10 successful patients appear in the subsample of size 11 from the Placebo group is;

\(\begin{array}{c}p\left( x \right) = \frac{{{}^{10}{C_{10}}{}^{24}{C_{11 - 10}}}}{{{}^{34}{C_{11}}}},x = 0,1,2, \ldots ,10\\ = \frac{{{}^{10}{C_{10}}{}^{24}{C_1}}}{{{}^{34}{C_{11}}}},x = 0,1,2, \ldots ,10\\ = 8.39 \times {10^{ - 8}}.\end{array}\)

Therefore, the final answer is \(8.39 \times {10^{ - 8}}\).

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Most popular questions from this chapter

In a clinical trial with two treatment groups, the probability of success in one treatment group is 0.5, and the probability of success in the other is 0.6. Suppose that there are five patients in each group. Assume that the outcomes of all patients are independent. Calculate the probability that the first group will have at least as many successes as the second group.

Suppose that the measurementXof pressure made bya device in a particular system has the normal distributionwith meanμand variance 1, whereμis the true pressure.Suppose that the true pressureμis unknown but has theuniform distribution on the interval{5,15}. IfX = 8is observed, find the conditional p.d.f. ofμgivenX = 8.

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\(\begin{array}{l}{\bf{p = }}\left( {{{\bf{p}}_{\bf{1}}}{\bf{ \ldots }}{{\bf{p}}_{\bf{k}}}} \right){\bf{,}}\,{\bf{where}}\\{{\bf{p}}_{\bf{i}}}{\bf{ = }}\frac{{{{\bf{\lambda }}_{\bf{i}}}}}{{\sum\limits_{{\bf{j = 1}}}^{\bf{k}} {{{\bf{\lambda }}_{\bf{j}}}} }}\,{\bf{for}}\,{\bf{i = 1, \ldots ,k}}{\bf{.}}\end{array}\)

Consider again the two tests A and B described in Exercise2. If a student is chosen at random, what is the probability that the sum of her scores on the two tests will be greater than 200?

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