/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q10 E Suppose that six random variable... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Suppose that six random variables\({X_1},{X_2},...,{X_6}\)form a random sample from the standard normal distribution, and let

\(Y = {\left( {{X_1} + {X_2} + {X_3}} \right)^2} + {\left( {{X_4} + {X_5} + {X_6}} \right)^2}\). Determine a value ofcsuch that the random variablecYwill have a\({\chi ^2}\)distribution.

Short Answer

Expert verified

\(c = \frac{1}{3}\)

Step by step solution

01

Given information

Let\({X_1},{X_2},...,{X_6}\)be a random sample from a standard normal distribution.

02

Calculate the value of c 

\({X_1} + {X_2} + {X_3}\)And \({X_4} + {X_5} + {X_6}\) both will follow \(N\left( {0,3} \right)\).

\(\frac{{{X_1} + {X_2} + {X_3}}}{{\sqrt 3 }}\)and \(\frac{{{X_4} + {X_5} + {X_6}}}{{\sqrt 3 }}\)will follows a standard normal distribution.

So, each \(\frac{{{{\left( {{X_1} + {X_2} + {X_3}} \right)}^2}}}{3}\) and \(\frac{{{{\left( {{X_4} + {X_5} + {X_6}} \right)}^2}}}{3}\)will follow \({\chi ^2}\)with d.f 1.

And \(\frac{Y}{3} = \frac{{{{\left( {{X_1} + {X_2} + {X_3}} \right)}^2}}}{3} + \frac{{{{\left( {{X_4} + {X_5} + {X_6}} \right)}^2}}}{3}\) will follows \({\chi ^2}\) with 2 degrees of freedom.

Therefore,\(c = \frac{1}{3}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Suppose that\({X_1},...,{X_n}\)form a random sample from the normal distribution with unknown mean μ and known variance\({\sigma ^2}\). How large a random sample must be taken in order that there will be a confidence interval for μ with confidence coefficient 0.95 and length less than 0.01σ?

Suppose that\({{\bf{X}}_{\bf{1}}}{\bf{,}}...{{\bf{X}}_{\bf{n}}}\)form a random sample from a distribution for which the p.d.f. is as follows:

\({\bf{f}}\left( {{\bf{x}}\left| {\bf{\theta }} \right.} \right){\bf{ = }}\left\{ {\begin{align}{}{{\bf{\theta }}{{\bf{x}}^{{\bf{\theta - 1}}}}}&{{\bf{for}}\,\,{\bf{0 < x < 1,}}}\\{\bf{0}}&{{\bf{otherwise,}}}\end{align}} \right.\)

where the value of θ is unknown (θ > 0). Determine the asymptotic distribution of the M.L.E. of θ. (Note: The M.L.E. was found in Exercise 9 of Sec. 7.5.)

Suppose that the random variables \({X_1}\,\,\,{\rm{and}}\,\,\,{X_2}\) are independent and that each has the normal distribution with mean 0 and variance \({\sigma ^2}\) . Determine the value of

\(P\left( {\frac{{{{\left( {{X_1} + {X_2}} \right)}^2}}}{{{{\left( {{X_1} - {X_2}} \right)}^2}}} < 4} \right)\)

Question:Suppose that a specific population of individuals is composed of k different strata (k ≥ 2), and that for i = 1,...,k, the proportion of individuals in the total population who belong to stratum i is pi, where pi > 0 and\(\sum\nolimits_{{\bf{i = 1}}}^{\bf{k}} {{{\bf{p}}_{\bf{i}}}{\bf{ = 1}}} \). We are interested in estimating the mean value μ of a particular characteristic among the total population. Among the individuals in stratum i, this characteristic has mean\({{\bf{\mu }}_{\bf{i}}}\)and variance\({\bf{\sigma }}_{\bf{i}}^{\bf{2}}\), where the value of\({{\bf{\mu }}_{\bf{i}}}\)is unknown and the value of\({\bf{\sigma }}_{\bf{i}}^{\bf{2}}\)is known. Suppose that a stratified sample is taken from the population as follows: From each stratum i, a random sample of ni individuals is taken, and the characteristic is measured for each individual. The samples from the k strata are taken independently of each other. Let\({{\bf{\bar X}}_{\bf{i}}}\)denote the average of the\({{\bf{n}}_{\bf{i}}}\)measurements in the sample from stratum i.

a. Show that\({\bf{\mu = }}\sum\nolimits_{{\bf{i = 1}}}^{\bf{k}} {{{\bf{p}}_{\bf{i}}}{{\bf{\mu }}_{\bf{i}}}} \), and show also that\({\bf{\hat \mu = }}\sum\nolimits_{{\bf{i = 1}}}^{\bf{k}} {{{\bf{p}}_{\bf{i}}}{{{\bf{\bar X}}}_{\bf{i}}}} \)is an unbiased estimator of μ.

b. Let\({\bf{n = }}\sum\nolimits_{{\bf{i = 1}}}^{\bf{k}} {{{\bf{n}}_{\bf{i}}}} \)denote the total number of observations in the k samples. For a fixed value of n, find the values for which the variance \({\bf{\hat \mu }}\)will be a minimum.

Question:Suppose that \({{\bf{X}}_{\bf{1}}}{\bf{, }}{\bf{. }}{\bf{. }}{\bf{. , }}{{\bf{X}}_{\bf{n}}}\) form n Bernoulli trials for which the parameter p is unknown (0≤p≤1). Show that the expectation of every function \({\bf{\delta }}\left( {{{\bf{X}}_{\bf{1}}}{\bf{, }}{\bf{. }}{\bf{. }}{\bf{. , }}{{\bf{X}}_{\bf{n}}}} \right)\)is a polynomial in p whose degree does not exceed n.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.