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Suppose that \({{\bf{X}}_{\bf{1}}}\;{\bf{and}}\;{{\bf{X}}_{\bf{2}}}\) are i.i.d. random variables andthat each of them has a uniform distribution on theinterval [0, 1]. Find the p.d.f. of\({\bf{Y = }}{{\bf{X}}_{\bf{1}}}{\bf{ + }}{{\bf{X}}_{\bf{2}}}\).

Short Answer

Expert verified

The p.d.f of \(Y = {X_1} + {X_2}\) is,

\(g\left( y \right) = \left\{ \begin{array}{l}y\;\;\;\;\;\;\;\;\;\;\;for\;0 < y \le 1\\2 - y\;\;\;\;\;\;for\;1 < y < 2\\0\;\;\;\;\;\;\;\;\;\;\;{\rm{otherwise}}\end{array} \right.\)

Step by step solution

01

Given information

\({X_1},{X_2}\) is a random variable following uniform distribution on a given interval [0,1], that is,\({X_i} \sim U[0,1]\;\;\;\forall \;i = 1,2\).

02

State p.d.f of

The pdf of any random variable X with uniform distribution is obtained by using the formula: \(\frac{1}{{b - a}};a \le x \le b\).

Here, \(a = 0,b = 1\).

Therefore, the pdf of \({X_i} \sim U[0,1]\) is expressed as,

\({f_{{x_i}}} = \left\{ \begin{array}{l}\frac{1}{{1 - 0}} = 1\;\;\;\;\;\;\;\;\;\;0 \le {x_i} \le 1\\0;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;otherwise\end{array} \right.\)

03

Define new variables Y and Z 

Define,

\(\begin{aligned}{\bf{Y = }}{{\bf{X}}_{\bf{1}}}{\bf{ + }}{{\bf{X}}_{\bf{2}}}\\{\bf{Z = }}{{\bf{X}}_{\bf{1}}}{\bf{ - }}{{\bf{X}}_{\bf{2}}}\end{aligned}\)

Obtain the two uniformly distributed variables in terms of the new variables and obtain the ranges as follows.

From definitions of Y and Z,

If \({x_1} = 0 \Rightarrow y + z = 0\)

If \({x_1} = \frac{{y + z}}{2} \Rightarrow z = - y\)

Then,

\({x_2} = 0 \Rightarrow y = z\)

\({x_2} = \frac{{y - z}}{2}\)which implies that,

\(\begin{aligned}{x_1} &= 1 \Rightarrow y + z = 2\\{x_2} &= 1 \Rightarrow y - z = 2\end{aligned}\)

04

Perform the Jacobian Transformation

The jacobian is obtained as follows,

\(\begin{aligned}J &= \left| {\begin{aligned}{}{\frac{{\partial {x_1}}}{{\partial Y}}}&{\frac{{\partial {x_2}}}{{\partial Y}}}\\{\frac{{\partial {x_1}}}{{\partial Z}}}&{\frac{{\partial {x_2}}}{{\partial Z}}}\end{aligned}} \right|\\ &= \left| {\begin{aligned}{}{\frac{1}{2}}&{\frac{1}{2}}\\{\frac{1}{2}}&{\frac{{ - 1}}{2}}\end{aligned}} \right|\\ &= \frac{1}{2}\end{aligned}\)

05

Define the joint pdf of the two variables Y and Z

Define the joint distribution as,

\(\begin{aligned}g\left( {y,z} \right) &= f\left( {{x_1},{x_2}} \right)\left| J \right|\\ &= \frac{1}{2},\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;0 < y < 2, - 1 < z < 1\end{aligned}\)

From the joint distribution, the marginal pdf of the variables is obtained as,

\(\begin{aligned}{g_1}\left( y \right) &= \int_{ - y}^y {\frac{1}{2}dz} \;\\ &= \frac{1}{2}\left| z \right|_{ - y}^y\\ &= y\end{aligned}\)

\(\begin{aligned}{g_2}\left( z \right) &= \int_{y - 2}^{2 - y} {\frac{1}{2}dz} \;\\ &= \frac{1}{2}\left| z \right|_{y - 2}^{2 - y}\\ &= 2 - y\end{aligned}\)

Thus, the distribution of \(Y = {X_1} + {X_2}\)is,

\(g\left( y \right) = \left\{ \begin{array}{l}y\;\;\;\;\;\;\;\;\;\;\;for\;0 < y \le 1\\2 - y\;\;\;\;\;\;for\;1 < y < 2\\0\;\;\;\;\;\;\;\;\;\;\;{\rm{otherwise}}\end{array} \right.\)

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Most popular questions from this chapter

Suppose that three boys A, B, and C are throwing a ball from one to another. Whenever A has the ball, he throws it to B with a probability of 0.2 and to C with a probability of 0.8. Whenever B has the ball, he throws it to A with a probability of 0.6 and to C with a probability of 0.4. Whenever C has the ball, he is equally likely to throw it to either A or B.

a. Consider this process to be a Markov chain and construct the transition matrix.

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Question:A painting process consists of two stages. In the first stage, the paint is applied, and in the second stage, a protective coat is added. Let X be the time spent on the first stage, and let Y be the time spent on the second stage. The first stage involves an inspection. If the paint fails the inspection, one must wait three minutes and apply the paint again. After a second application, there is no further inspection. The joint pdf.of X and Y is

\(f\left( {x,y} \right) = \left\{ \begin{array}{l}\frac{1}{3}if\,1 < x < 3\,and\,0 < y < 1\\\frac{1}{6}if\,1 < x < 3\,and\,0 < y < 1\,\\0\,\,otherwise.\\\,\end{array} \right.\,\,\)

a. Sketch the region where f (x, y) > 0. Note that it is not exactly a rectangle.

b. Find the marginal p.d.f.’s of X and Y.

c. Show that X and Y are independent.

Suppose that either of two instruments might be used for making a certain measurement. Instrument 1 yields a measurement whose p.d.f.\({{\bf{h}}_{\bf{1}}}\)is

\({{\bf{h}}_{\bf{1}}}\left( {\bf{x}} \right){\bf{ = }}\left\{ {\begin{align}{}{{\bf{2x}}}&{{\bf{for}}\,{\bf{0 < x < 1}}}\\{\bf{0}}&{{\bf{otherwise}}}\end{align}} \right.\)

Instrument 2 yields a measurement whose p.d.f.\({{\bf{h}}_2}\)is

\({{\bf{h}}_{\bf{2}}}\left( {\bf{x}} \right){\bf{ = }}\left\{ {\begin{align}{}{{\bf{3}}{{\bf{x}}^{\bf{2}}}}&{{\bf{for}}\,{\bf{0 < x < 1}}}\\{\bf{0}}&{{\bf{otherwise}}}\end{align}} \right.\)

Suppose that one of the two instruments is chosen randomly, and a measurement X is made with it.

  1. Determine the marginal p.d.f. of X.
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Show that there does not exist any numbercsuch that the following functionf (x)would be a p.d.f.:

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Response(X)

Treatment Group(Y)

Impramine(1)

Lithium(2)

Combination(3)

Placebo(4)

Relapse(0)

0.120

0.087

0.146

0.160

No relapse(1)

0.147

0.166

0.107

0.067

a. Calculate the probability that a patient selected at random from this study used Lithium (either alone or in combination with Imipramine) and did not relapse.

b. Calculate the probability that the patient had a relapse(without regard to the treatment group).

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