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Suppose that a random sample X1,鈥︹赌..,齿nis taken from the normal distribution with unknown mean 碌 and unknown variance2, and the following hypotheses are to be tested:

H0 : 碌 鈮 0

H1 : 碌 > 0

Suppose also that the sample size n is 17, and it is found from the observed values in the sample that 齿虅n= 3.2 and \(\frac{1}{n}\sum\limits_{i=1}^n{{{\left({{X_i}-{{\bar X}_n}}\right)}^2}}=0.09\). Calculate the value of the statistic U, and find the corresponding p-value.

Short Answer

Expert verified

The value of test statistics is U= 8/3 and the p-value is 0.008.

Step by step solution

01

Given Information:

A random sample of X1,鈥︹.., Xn is to be taken from the normal distribution.

Need to test,

H0 : 碌 鈮 3

H1: 碌 >3

02

Finding test statistics and determining the p-value

With the sample size of n = 17, the sample variance (with denominator n-1) is

\begin{aligned}s^{2}=\frac{n}{n-1}\times\frac{1}{n}\sum_{i-1}^{n}(X_{i}-\overline{X})^{2}\end{aligned}

\begin{aligned}=\frac{17}{16}\times0.09\end{aligned}

The T statistic U is now as follows:

\begin{aligned}U=\frac{\sqrt{n}\overline{X}-3}{s}\end{aligned}

\begin{aligned}=\frac{\sqrt{17}\times0.2}{\sqrt{\frac{17}{16}}\times 0.9}\end{aligned}

\begin{aligned}=\frac{0.2\times4}{0.3}\end{aligned}

\begin{aligned}=\frac{8}{3}\end{aligned}

Thus, U=8/3

The U statistic now follows a T distribution with n-1=16 degrees of freedom at 碌 = 3

As a result, the p values are provided by

P(U>8/3|碌 = 3) =0.008

A p-value is obtained by using the t table for 16 degrees of freedom.

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