/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q4E In a small community consisting ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In a small community consisting of 153 families, the number of families that have k children \(\left( {k = 0,1,2,......} \right)\) is given in the following table

Number of children

Number of families

0

21

1

40

2

42

3

27

4 or more

23

Determine the mean and the median of the number of children per family. (For the mean, assume that all families with four or more children have only four children. Why doesn’t this point matter for the median?)

Short Answer

Expert verified

The mean number of children per family is 2.

The median number of children per family is 2.

The assumption that all families with four or more children have only four children has not been used for calculating the median because it does not fall into the median class. Hence, it does not affect the median value at all.

Step by step solution

01

Given information

In a small community consisting of 153 families, the number of families that have k children \(\left( {k = 0,1,2,......} \right)\) is given in the following table:

Number of children

Number of families

0

21

1

40

2

42

3

27

4 or more

23

02

Find the mean number of children per family

Assuming that all families with four or more children have only four children, the above table is modified as follows:

Then, the mean is calculated as:

\(\begin{aligned}{c}Mean &= \frac{{\sum {{x_i}{f_i}} }}{{\sum {{f_i}} }}\\ &= \frac{{297}}{{153}}\\ &= 1.94\\ \simeq 2.\end{aligned}\)

Therefore, on an average, there exist 2 children per family.

03

Find the median number of children per family

Here, the median number of children is the class for which the cumulative frequency is greater than or equal to \(\frac{{153}}{2} = 76.5\).

Then, from the table above, it can be concluded that the median number of children per family is 2.

Here, the assumption that all families with four or more children have only four children has not been used because it does not fall into the median class. Hence, it does not affect the median value at all.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Suppose that a person must accept a gamble X of the following form:

\({\bf{Pr}}\left( {{\bf{X = a}}} \right){\bf{ = p}}\,\,\,{\bf{and}}\,\,\,{\bf{Pr}}\left( {{\bf{X = 1}} - {\bf{a}}} \right){\bf{ = 1}} - {\bf{p}}\),

where p is a given number such that\({\bf{0 < p < 1}}\), suppose also that the person can choose and fix the value of a\(\left( {{\bf{0}} \le {\bf{a}} \le {\bf{1}}} \right)\)to be used in this gamble. Determine the value of a that the person would choose if his utility function was\({\bf{U}}\left( {\bf{x}} \right){\bf{ = logx}}\)for\({\bf{x > 0}}\).

Determine the value of a that a person would choose in Exercise 7 if his utility function was\({\bf{U}}\left( {\bf{x}} \right){\bf{ = x}}\)for\({\bf{x}} \ge {\bf{0}}\).

Suppose that the pair(X, Y )is uniformly distributed on the interior of a circle of radius 1. ComputeÒÏ(³Ý,³Û).

Suppose that a person has a lottery ticket from which she will win X dollars, where X has the uniform distribution on the interval\(\left( {{\bf{0,4}}} \right)\). Suppose also that the person’s utility function is\({\bf{U}}\left( {\bf{x}} \right){\bf{ = }}{{\bf{x}}^{\bf{\alpha }}}\)for\({\bf{x}} \ge {\bf{0}}\), where α is a given positive constant. For how many dollars\({{\bf{x}}_{\bf{0}}}\)would the person be willing to sell this lottery ticket?

Suppose thatXis a random variable for which the m.g.f. is as follows:\(\psi \left( t \right) = \frac{1}{5}{e^t} + \frac{2}{5}{e^{4t}} + \frac{2}{5}{e^{8t}}\)for−∞< t <∞.Find the probability distribution ofX. Hint:It is a simple discrete distribution.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.