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Suppose that 20 percent of the students who took acertain test were from schoolAand that the arithmetic average of their scores on the test was 80. Suppose alsothat 30 percent of the students were from school B and that the arithmetic average of their scores was 76. Suppose, finally, that the other 50 percent of the students were from schoolCand that the arithmetic average of their scores was 84. If a student is selected at random from the entiregroup that took the test, what is the expected value of herscore?

Short Answer

Expert verified

The expected score of a student is 80.8

Step by step solution

01

Given Information

Suppose that 20 percent of the students who took a certain test were from school Aand that the arithmetic average of their scores on the test was 80.

\(\)\(\begin{align}\Pr \left( A \right) &= 0.20\\E\left( {Score|A} \right) &= 80\end{align}\)

Suppose also that 30 percent of the students were from school B and that the arithmetic average of their scores was 76

\(\begin{align}\Pr \left( B \right) &= 0.30\\E\left( {Score|B} \right) &= 76\end{align}\)

Suppose, finally, that the other 50 percent of the students were from school Cand that the arithmetic average of their scores was 84

\(\begin{align}{l}\Pr \left( C \right) &= 0.50\\E\left( {Score|C} \right) &= 84\end{align}\)

02

Finding the expected score of the selected student

If X denotes the score of the selected student, then

\(\begin{align}E\left( X \right) &= E\left( {E\left( {X|School} \right)} \right)\\ &= \Pr \left( A \right)E\left( {X|A} \right) + \Pr \left( B \right)E\left( {X|B} \right) + \Pr \left( C \right)E\left( {X|C} \right)\\ &= 0.20 \times 80 + 0.30 \times 76 + 0.50 \times 84\\ &= 80.8\end{align}\)

The expected score of the selected student is 80.8

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