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Consider three gambles, X, Y, and Z, for which the probability distributions of the gains are as follows:

\(\begin{align}{}{\bf{Pr}}\left( {{\bf{X = 5}}} \right){\bf{ = Pr}}\left( {{\bf{X = 25}}} \right){\bf{ = }}{\raise0.7ex\hbox{\({\bf{1}}\)} \!\mathord{\left/ {\vphantom {{\bf{1}} {\bf{2}}}}\right.\ } \!\lower0.7ex\hbox{\({\bf{2}}\)}}{\bf{,}}\\{\bf{Pr}}\left( {{\bf{Y = 10}}} \right){\bf{ = Pr}}\left( {{\bf{Y = 20}}} \right){\bf{ = }}{\raise0.7ex\hbox{\({\bf{1}}\)} \!\mathord{\left/ {\vphantom {{\bf{1}} {\bf{2}}}}\right.\ } \!\lower0.7ex\hbox{\({\bf{2}}\)}}{\bf{,}}\\{\bf{Pr}}\left( {{\bf{Z = 15}}} \right){\bf{ = 1}}{\bf{.}}\end{align}\)

Suppose that a person’s utility function has the form\({\bf{U}}\left( {\bf{x}} \right){\bf{ = }}{{\bf{x}}^{\bf{2}}}\)for\({\bf{x > 0}}\). Which of the three gambles would she prefer?

Short Answer

Expert verified

Gamble X is preferred.

Step by step solution

01

Given information

There are three gambles X, Y, and Z

Their probability distributions of the gains are,

\(\begin{align}\Pr \left( {X = 5} \right) = \Pr \left( {X = 25} \right) = {\raise0.7ex\hbox{$1$} \!\mathord{\left/ {\vphantom {1 2}}\right.\ } \!\lower0.7ex\hbox{$2$}},\\\Pr \left( {Y = 10} \right) = \Pr \left( {Y = 20} \right) = {\raise0.7ex\hbox{$1$} \!\mathord{\left/ {\vphantom {1 2}}\right.\ }\!\lower0.7ex\hbox{$2$}},\\\Pr \left( {Z = 15} \right) = 1.\end{align}\)

The utility function is given by,

\(U\left( x \right) = {x^2}\,for\,x > 0\)

02

Which gamble is preferable

The expectation of gamble X is,

\(\begin{align}E\left) {U\left( X \right)} \right) &= \left( {\frac{1}{2} \times {5^2}} \right) + \left( {\frac{1}{2} \times {{25}^2}} \right)\\ &= 12.5 + 312.5\\ &= 325\end{align}\)

The expectation of gamble Y is,

\(\begin{align}E\left) {U\left( Y \right)} \right) &= \left( {\frac{1}{2} \times {{10}^2}} \right) + \left( {\frac{1}{2} \times {{20}^2}} \right)\\ &= 50 + 200\\ &= 250\end{align}\)

The expectation of gamble Z is,

\(\begin{align}E\left) {U\left( Z \right)} \right) &= \left( {1 \times {{15}^2}} \right)\\ &= \left( {1 \times 225} \right)\\ &= 225\end{align}\)

Hence, gamble X is preferred.

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Suppose that X has the uniform distribution on the interval \(\left( {0,1} \right)\). Compute the variance of X.

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