/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 7 A six-letter permutation is sele... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A six-letter permutation is selected at random from the letters in the word NIMBLE. a. How many permutations are possible? b. How many of these permutations begin with \(M ?\) c. What is the probability that the permutation begins with \(M ?\) d. Express the probability in part c as a percent. e. What is the probability that the permutation is NIMBLE?

Short Answer

Expert verified
a. 720 permutations possible. b. 120 permutations begin with M. c. Probability begins with M is 1/6. d. Probability as a percent is 16.67%. e. Probability of NIMBLE permutation is 1/720 or 0.14%.

Step by step solution

01

Determine Total Number of Permutations

The total number of permutations of 6 letters from the word NIMBLE is found using the factorial of the number of letters. Since there are no repeating letters, the number of permutations is simply 6 factorial, which is calculated as 6! = 6 × 5 × 4 × 3 × 2 × 1.
02

Calculate Number of Permutations Beginning with M

To determine the permutations beginning with M, we fix M as the first letter and find permutations of the remaining 5 letters. This is given as 5! = 5 × 4 × 3 × 2 × 1.
03

Compute Probability of a Permutation Beginning with M

The probability is the ratio of the number of favorable outcomes (permutations beginning with M) over the total possible outcomes (total number of permutations). This is given by the formula P(begin with M) = (number of permutations beginning with M)/(total number of permutations) = 5!/6!.
04

Convert Probability to Percent

To express the probability as a percent, we multiply the probability by 100. Therefore, the percentage is P(begin with M) × 100.
05

Determine Probability of NIMBLE Permutation

The permutation NIMBLE is just one specific arrangement out of all possible permutations. Thus, the probability P(NIMBLE) is 1/(total number of permutations) = 1/6!.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Factorial Notation
Factorial notation is fundamental to understanding permutations in statistics. It's signified by an exclamation point (!) following a number, and represents the product of all positive integers up to that number. For instance, the factorial of 6, written as 6!, is calculated as
\(6! = 6 \times 5 \times 4 \times 3 \times 2 \times 1 = 720\).
Factorials grow very fast with larger numbers, which indicates just how quickly the number of permutations can increase. It's critical for calculations where order matters, such as arranging objects or choosing sequential events. When considering permutations, the factorial denotes the total number of ways a set number of items can be ordered.
Probability
Probability is a way of quantifying the likelihood that a given event will occur. It's expressed as a number between 0 and 1, where 0 indicates impossibility and 1 indicates certainty. The probability P of an event is calculated by dividing the number of favorable outcomes by the total number of possible outcomes:
\( P(\text{event}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}} \).
Understanding the basic principle of probability allows us to tackle more complex problems, such as calculating permutation probabilities. It's essential to consider both the favorable and total outcomes, bearing in mind that all outcomes must be equally likely for the probability calculation to be valid.
Permutation Probability
Permutation probability combines the concepts of factorial notation and probability to determine how likely a specific arrangement of items is among all possible permutations. In a situation where order is important, like in the example of the six-letter word NIMBLE, it helps to calculate the probability that a permutation will have a particular form or characteristic.
To improve understanding, consider the permutations that begin with the letter M. Since M is fixed at the beginning, the remaining letters can be arranged in 5! ways as detailed in our exercised solution. The probability, then, of getting a permutation that starts with M is the ratio of favorable permutations (those beginning with M) to total permutations (all possible arrangements). Using our factorial method, this becomes \(\frac{5!}{6!}\), by simplifying this, we see the six cancels out, leaving us with \(\frac{1}{6}\) or about 16.67% when converted to a percent.
Overall, permutation probability is invaluable when needing to calculate the likelihood of different arrangements or sequences in a set of items.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Frost Bank has seven vice presidents, but only three spaces in the parking lot are labeled "Vice President." In how many different ways could these spaces be occupied by the vice presidents' cars?

Baseball Team Problem 3: Nine people try out for the nine positions on a baseball team. If the players are selected at random for the positions, find the probability of each event. a. Fred, Mike, or Jason is the pitcher. b. Fred, Mike, or Jason is the pitcher, and Sam or Paul plays first base. c. Fred, Mike, or Jason is the pitcher, Sam or Paul plays first base, and Bob is the catcher.

Colorblindness Problem: Statistics show that about \(8 \%\) of all males are colorblind. Interestingly, women are less likely to have this condition. Suppose that 20 males are selected at random Let \(P(x)\) be the probability that \(x\) of the 20 men are colorblind. (A). Compute the probability distribution and plot its graph. Use a window that makes the graph fill most of the screen. Sketch the pattern followed by the points on the graph. (B). From your output in part a, find \(P(0), P(1)\) \(P(2),\) and \(P(3)\) (C). In a time-efficient way, calculate the probability that at least 4 of the 20 males are colorblind. Show the method you used in the computation.

Review Problem 1: You draw a 5 -card hand from a standard 52 -card deck and then arrange the cards from left to right. a. After the cards have been selected, in how many different ways could you arrange them? b. How many different 5 -card hands could be formed without considering arrangement? c. How many different 5 -card arrangements could be formed from the deck? d. Which part(s) of this problem involve permutations and which involve combinations?

Backup System Problem: Vital systems such as electric power generating systems have "backup", components in case one component fails. Suppose that two generators each have a \(98 \%\) probability of working. The system will continue to operate as long as at least one of the generators is working. What is the probability that the system will continue to operate?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.