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Baseball Team Problem 1: Nine people on a baseball team are trying to decide who will play each position. a. In how many different ways could they select a person to be pitcher? b. After someone has been selected as pitcher, in how many different ways could they select someone to be catcher? c. In how many different ways could they select a pitcher and a catcher? d. After the pitcher and catcher have been selected, in how many different ways could they select a first-base player? e. In how many different ways could they select a pitcher, catcher, and first- base player? f. In how many different ways could all nine positions be filled? Surprising?!

Short Answer

Expert verified
a. 9 ways, b. 8 ways, c. 72 ways, d. 7 ways, e. 504 ways, f. 362,880 ways

Step by step solution

01

Determine options for pitcher

Since anyone of the nine people can be selected to play as the pitcher, there are 9 different ways a person could be selected to be the pitcher.
02

Options for catcher after pitcher is chosen

After the pitcher has been chosen, 8 people remain to choose from for the catcher position. Thus, there are 8 different ways to choose a catcher once the pitcher is selected.
03

Options for pitcher and catcher combined

To determine the number of ways to select both a pitcher and a catcher, multiply the number of options for pitcher by the number of options for catcher, which is 9 (pitcher) * 8 (catcher) = 72 ways.
04

Options for first-base player after pitcher and catcher are chosen

After selecting a pitcher and a catcher, 7 people remain to choose from for the first-base position. Hence, there are 7 different ways to select a first-base player.
05

Options for picking pitcher, catcher, and first-base player combined

The number of ways to select a pitcher, a catcher, and a first-base player is calculated by multiplying the number of choices for each position: 9 (pitcher) * 8 (catcher) * 7 (first-base) = 504 ways.
06

Options for filling all nine positions

To fill all nine positions, we use the principle of permutations for 9 distinct positions. Starting with 9 choices for pitcher and decreasing by 1 for each subsequent position, the number of ways is 9! (9 factorial), which equals 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1 = 362,880 ways.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Factorial
In mathematics, the concept of a factorial is fundamental when dealing with permutations and combinations. A factorial is the product of all positive integers up to a given number. Denoted by an exclamation mark (!), it plays a key role in calculating the number of ways in which a set of objects can be arranged. For instance, the factorial of 4, expressed as 4!, is computed as 4 x 3 x 2 x 1, which equals 24.

In the context of the baseball team problem, when you're asked to fill all nine positions, you're calculating 9!, which means you multiply 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1, giving us 362,880 possible arrangements. This large number might be surprising at first, but it demonstrates just how many combinations can be made even with a seemingly small number of items.
Combinatorics
Combinatorics is an area of mathematics primarily concerned with counting, both as a means and an end in obtaining results, and certain properties of finite structures. It includes the counting of objects arranged in specific patterns; such patterns could be permutations, combinations, and various other configurations. In the problem we're considering, combinatory principles are applied to solve several related counting problems, ranging from selecting individual roles to determining the arrangement of the entire baseball team.

Permutations in Team Selection

When looking at how to select a pitcher, catcher, and first-base player, we are working with permutations since the order is important. The formula for permutations of 'n' objects taken 'r' at a time is given by: \( P(n, r) = \frac{n!}{(n-r)!} \). However, when all nine positions need filling, this simplifies to 9! since you're permuting all nine positions.
Probability and Statistics
While probability and statistics are broader fields of mathematics than just combinatorics, they are deeply interconnected. Probability uses combinatorial calculations to determine the likelihood of an event occurring, given a finite set of possible outcomes. On the other hand, statistics often employs combinatorial concepts to analyze and interpret data.

Understanding the baseball team example from a probabilistic standpoint, if we were to randomly assign the nine players to nine positions, the probability that they end up in a specific order is 1 divided by the total number of permutations, which is \( \frac{1}{9!} \). This tiny number underscores the vast number of different ways a baseball team can be arranged, showing just how unlikely it is for a random assignment to result in any one particular configuration.

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Most popular questions from this chapter

The menu at Paesano's lists 7 salads, 11 entrees, and 9 desserts. How many different salad-entree-dessert meals could you select? (Meals are considered to be different if any one thing is different.)

Multiple-Choice Test Problem 2: Suppose that you are taking your College Board tests. You answer all the questions you know, and have some time left over. So you decide to guess the answers to the rest of the questions. a. Each question is multiple choice with five choices. If you guess at random, what is the probability of getting an answer right? Of getting an answer wrong? b. When the testing service grades your paper, they give you 1 point if the answer is right and subtract \(\frac{1}{4}\) point if the answer is wrong. What is your mathematically expected score on any question for which you guess at random? c. Suppose that, on one question, you can eliminate one choice you know is wrong, and then randomly guess among the other four. What is your mathematically expected score on this question? Surprisingly low, isn't it? d. Calculate your mathematically expected score on a question for which you can eliminate two of the choices and then for which you can eliminate three of the choices. e. Based on your answers, do you think it is worthwhile guessing answers on a multiplechoice test?

Historical Search Project: Check the Internet or other sources for information about early contributors to the field of mathematical probability. See if you can find out about the dice problem investigated by Blaise Pascal and Pierre de Fermat that led to the foundations of probability theory.

Evaluate the number of combinations or permutations two ways: a. Using factorials, as in the examples of this section b. Directly, using the built-in features of your grapher $$10 C_{10}$$

Fran Tick takes a 10 -problem precalculus test. The problems may be worked in any order. a. In how many different orders could she work all 10 of the problems? b. In how many different orders could she work any 7 of the 10 problems?

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