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Determine whether the statement is true or false. Justify your answer. \((2 x-1)\) is a factor of the polynomial \(6 x^{6}+x^{5}-92 x^{4}+45 x^{3}+184 x^{2}+4 x-48.\)

Short Answer

Expert verified
The statement is false; \((2x-1)\) is not a factor of the given polynomial since the substitution of x = 0.5 in the polynomial does not yield zero.

Step by step solution

01

Transform the Factor

First, we need to find the value of x that would make \((2x-1) = 0\). This can be solved as follows:\[2x - 1 = 0 \rightarrow x = 0.5\]
02

Substitute into the Polynomial

Next, we substitute x = 0.5 into the polynomial \(6x^6 + x^5 - 92x^4 + 45x^3 + 184x^2 + 4x - 48\) and see if it equals to zero:\[6(0.5)^6 + (0.5)^5 - 92(0.5)^4 + 45(0.5)^3 + 184(0.5)^2 + 4(0.5) - 48\]
03

Evaluate the Expression

After performing the calculations, we find that the result of the substitution does not equal to zero.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Factor Theorem
The Factor Theorem is a valuable tool in algebra that connects factors and roots of a polynomial. It states that for a polynomial \(P(x)\), if \((x - c)\) is a factor, then \(P(c) = 0\). Put simply, if plugging a value into the polynomial results in zero, then that value is a root, and \((x - c)\) is a factor.

This theorem simplifies the process of factorization:
  • First, find potential roots of the polynomial. These potential roots are often derived from setting the potential factor equal to zero, and solving for \(x\).
  • Next, substitute these potential roots into the polynomial.
  • If the result is zero, it confirms that the value is a root and the corresponding expression is a factor of the polynomial.
With this understanding, step 2 in the solution attempts to apply this by inserting \(x = 0.5\) into the polynomial. Because the calculation did not yield zero, \((2x - 1)\) is not a factor of the polynomial.
Polynomial Expressions
Polynomials are algebraic expressions that consist of variables and coefficients. They are constructed from terms, which are products of a coefficient and a variable raised to a whole-number power. The general form is \(a_nx^n + a_{n-1}x^{n-1} + \, ... \, + a_1x + a_0\), where \(a_n, a_{n-1}, ..., a_0\) are coefficients, and \(n\) is a non-negative integer representing the degree of the polynomial.

Some key characteristics of polynomial expressions include:
  • Degree: This is the highest exponent of the variable in the polynomial. It dictates the number of roots and the general shape of the graph.
  • Leading Coefficient: Found in front of the variable with the highest degree; it influences the directional behavior of the polynomial as \(x\) heads towards infinity or negative infinity.
  • Roots or Zeros: Values of \(x\) that make the polynomial equal to zero.
  • Constant Term: This is the term without a variable, influencing the y-intercept of the graph.
In the exercise, you are working with a sixth-degree polynomial, reflecting its complex nature. Analyzing the individual terms can provide insights into possible factor combinations and behaviors across its real number domain.
Synthetic Division
Synthetic division is a streamlined technique for dividing a polynomial by another polynomial of the form \(x - c\). It is generally more efficient than traditional long division, especially when dealing with a large polynomial.

The process involves using the roots from factorization attempts to "divide" the polynomial. Here are the steps used in synthetic division:
  • Write down the coefficients of the polynomial you are dividing.
  • Use the root (from \(x - c = 0\), \(c\) becomes the root) outside the synthetic division structure.
  • Bring down the first coefficient, then multiply it by the root and add this product to the next coefficient.
  • Repeat until all coefficients are used up.
  • If the last number (remainder) is zero, it confirms that \(x - c\) is a factor.
Synthetic division provides a quick method to confirm factors and simplify large polynomial expressions. While not used directly in the step-by-step solution, it is a related and powerful tool for understanding polynomial division techniques.

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Most popular questions from this chapter

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