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Finding a Polynomial Function, find a polynomial function that has the given zeros. (There are many correct answers.) $$ 2,4+\sqrt{5}, 4-\sqrt{5} $$

Short Answer

Expert verified
The polynomial function that has the roots \(2, 4 + \sqrt{5}\), and \(4 - \sqrt{5}\) is \(f(x) = x^3 - 10x^2 + 36x - 28\).

Step by step solution

01

Identify the Roots

The given roots are \(2, 4 + \sqrt{5}, 4 - \sqrt{5}\). Observe that \(4 + \sqrt{5}\) and \(4 - \sqrt{5}\) are conjugate pairs.
02

Use the Factor Theorem

According to the Factor Theorem, if \(r\) is a root of the polynomial, then \((x - r)\) is a factor of the polynomial. Consequently, we can write the polynomial as \((x - 2)(x - (4 + \sqrt{5}))(x - (4 - \sqrt{5}))\).
03

Expand the Polynomial

Expand the polynomial \(f(x) = (x - 2)(x - (4 + \sqrt{5}))(x - (4 - \sqrt{5}))\) product\-to\-expand, which would yield \(f(x) = x^3 - 10x^2 + 36x - 28\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Factor Theorem
The Factor Theorem is a powerful tool in algebra that establishes a direct link between the roots of a polynomial and its factors. Suppose we want to determine if a particular number, say 'r', is a root of a polynomial function like \( f(x) \). In that case, the Factor Theorem says that if \( f(r) = 0 \), then \( (x - r) \) is indeed a factor of the polynomial \( f(x) \).

Think of it like a detective solving a mystery: if you have a suspect (a potential root) and evidence (the function value is zero), you've found your factor (the 'culprit'). This relationship is critical because once we identify all the roots of a polynomial, we can reconstruct it by combining these factors. For students who find the steps tricky, remember that finding and verifying roots allows you to piece the polynomial together, factor by factor, to unveil the original equation.
Conjugate Pairs
When dealing with complex numbers, a concept known as 'conjugate pairs' often comes into play. This concept is equally important when some roots of a polynomial are irrational numbers, involving square roots - just like in our exercise. A pair of roots is said to be conjugate if they are of the form \( a + b\sqrt{c} \) and \( a - b\sqrt{c} \) where \( a \) and \( b \) are rational numbers, and \( c \) is a positive integer that is not a perfect square.

Why is this important? When you're working with polynomials with real coefficients (which most of them are), if one root is a non-real complex number or any irrational number (as \( 4 + \sqrt{5} \) in our case), its conjugate will also be a root. This conjugate pair will result in factors that are also polynomials with real coefficients when multiplied together. Therefore, recognizing these pairs is a strategic shortcut to finding polynomial equations with real coefficients.
Polynomial Roots
Polynomial roots, often called zeroes of the equation, are those values that make the polynomial equal to zero. For students, imagine each root as a puzzle piece that fits into the big picture, forming a complete polynomial equation. Knowing the roots tells us directly what the factors of the polynomial are, thanks to the Factor Theorem mentioned earlier.

For instance, if you know that a polynomial has roots at \( 2 \), \( 4 + \sqrt{5} \) and \( 4 - \sqrt{5} \) as in our example, your polynomial could be constructed from the factors \( x - 2 \) and the conjugate pair \( x - (4 + \sqrt{5}) \) and \( x - (4 - \sqrt{5}) \). When you multiply these factors together, you find the overall polynomial that has these specific roots. Remember that for a polynomial function of degree 'n', you should expect exactly 'n' roots (counting multiplicity), which means some roots can repeat. Finally, in practicum and competitive exams alike, recognizing and applying the significance of these roots can simplify your problem-solving process considerably.

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Most popular questions from this chapter

Average Speed A driver averaged 50 miles per hour on the round trip between two cities 100 miles apart. The average speeds for going and returning were \(x\) and \(y\) miles per hour, respectively. (a) Show that \(y=(25 x) /(x-25)\) . (b) Determine the vertical and horizontal asymptotes of the graph of the function. (c) Use a graphing utility to graph the function. (d) Complete the table. (e) Are the results in the table what you expected? Explain. (f) Is it possible to average 20 miles per hour in one direction and still average 50 miles per hour on the round trip? Explain.

Cost, Revenue, and Profit The revenue and cost equations for a product are \(R=x(50-0.0002 x)\) and \(C=12 x+150,000,\) where \(R\) and \(C\) are measured in dollars and \(x\) represents the number of units sold. How many units must be sold to obtain a profit of at least \(\$ 1,650,000 ?\) What is the price per unit?

Think About It, determine (if possible) the zeros of the function \(g\) when the function \(f\) has zeros at \(x=r_{1}, x=r_{2},\) and \(x=r_{3}\). $$g(x)=f(x-5)$$

Rational and Irrational Zeros, match the cubic function with the numbers of rational and irrational zeros. (a) Rational zeros: \(0 ;\) irrational zeros: 1 (b) Rational zeros: \(3 ;\) irrational zeros: 0 (c) Rational zeros: \(1 ;\) irrational zeros: 2 (d) Rational zeros: \(1 ;\) irrational zeros: 0 $$f(x)=x^{3}-1$$

Forensics At \(8 : 30\) A.M., a coroner went to the home of a person who had died during the night. In order to estimate the time of death, the coroner took the person's temperature twice. At \(9 : 00\) A.M. the temperature was \(85.7^{\circ} \mathrm{F},\) and at \(11 : 00\) A.M. thetemperature was \(82.8^{\circ} \mathrm{F}\) . From these two temperatures, the coroner was able to determine that the time elapsed since death and the body temperature were related by the formula $$t=-10 \ln \frac{T-70}{98.6-70}$$ where \(t\) is the time in hours elapsed since the person died and \(T\) is the temperature (in degrees Fahrenheit) of the person's body. (This formula comes from a general cooling principle called Newton's Law of Cooling.It uses the assumptions that the person had a normal body temperature of \(98.6^{\circ} \mathrm{F}\) at death and that the room temperature was a constant \(70^{\circ} \mathrm{F} .\) ) Use the formula to estimate the time of death of the person.

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