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Rational and Irrational Zeros, match the cubic function with the numbers of rational and irrational zeros. (a) Rational zeros: \(0 ;\) irrational zeros: 1 (b) Rational zeros: \(3 ;\) irrational zeros: 0 (c) Rational zeros: \(1 ;\) irrational zeros: 2 (d) Rational zeros: \(1 ;\) irrational zeros: 0 $$f(x)=x^{3}-1$$

Short Answer

Expert verified
The cubic function \(f(x)=x^{3}-1\) matches with option (c) which states that the function has one rational zero and two irrational zeros.

Step by step solution

01

Factoring the Cubic Function

The cubic function \(f(x) = x^3 - 1\) can be factored as \((x - 1)(x^2 + x + 1) = 0\). Here, '1' is an obvious root of the equation, so we have one rational zero.
02

Finding Remaining Roots

The quadratic equation obtained from the factorization previously, \(x^2 + x + 1 = 0\), does not have any rational roots. We can confirm this by using the quadratic formula, \(x = \frac{-b \pm \sqrt{b^{2} - 4ac}}{2a}\), which provides the roots as irrational numbers. Hence, we have two irrational zeros.
03

Matching the Function

Since we found that the cubic function \(f(x) = x^3 - 1\) has one rational zero and two irrational zeros, the matching option for the function is (c).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cubic Function
A cubic function is a type of polynomial equation of the third degree. The general form of a cubic function is given by:
\[f(x) = ax^3 + bx^2 + cx + d\]where \(a\), \(b\), \(c\), and \(d\) are constants, and \(a eq 0\) because if \(a\) were 0, the function would be quadratic, not cubic. In this particular case, the cubic function provided is:
\[f(x) = x^3 - 1\]This implies we are looking at a simplified scenario where \(a = 1\) and both \(b\) and \(c\) are 0, leaving only the constant term \(d = -1\). Cubic functions can have either one or three real roots, depending on the nature of their discriminant. Understanding this is key to deducing the rational and irrational roots.
Factoring
Factoring is a crucial method used to simplify polynomial functions by expressing them as a product of their factors. In the case of cubic equations, factoring helps identify roots more easily. The expression
\[f(x) = x^3 - 1\]can be factored using known identities, specifically the difference of cubes:
\[a^3 - b^3 = (a - b)(a^2 + ab + b^2)\]Applying this identity to our cubic function where \(a = x\) and \(b = 1\), we obtain:
\[(x - 1)(x^2 + x + 1)\]This shows that one of the roots is rational (\(x = 1\)), while the other factor \(x^2 + x + 1\) needs further analysis to find other roots. Factoring reduces complexity, making solving such equations less daunting.
Quadratic Formula
The quadratic formula is a universal method for solving quadratic equations of the form \(ax^2 + bx + c = 0\). Given the factorized part \(x^2 + x + 1\), setting it equal to zero offers a quadratic that lacks rational roots. To find the roots, use the quadratic formula:
\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]Here, \(a = 1\), \(b = 1\), and \(c = 1\). Substitute these into the formula:
\[x = \frac{-1 \pm \sqrt{1^2 - 4 \times 1 \times 1}}{2 \times 1}\]Simplifying further:
\[x = \frac{-1 \pm \sqrt{1 - 4}}{2}\]\[x = \frac{-1 \pm \sqrt{-3}}{2}\]The solution includes imaginary components \(\pm \sqrt{3}i\), which implies no real rational roots. Thus, utilizing the quadratic formula shows these roots are irrational.
Roots of Polynomial
Roots of a polynomial are the solutions to the equation set when the polynomial equals zero. They are the values of \(x\) where the polynomial evaluates to zero. For the cubic equation \(f(x) = x^3 - 1\), the roots are the solutions for \(f(x) = 0\).
- The root \(x = 1\) is factored directly from \(x - 1 = 0\) and is a rational root.- The other roots come from \(x^2 + x + 1 = 0\), which provides complex roots by the quadratic formula.
In general, finding roots often involves factoring, using special identities, or applying formulas to identify both rational and irrational roots. Hence, understanding the process helps in solving polynomial equations effectively.
Polynomial Equations
Polynomial equations constitute expressions involving variables and coefficients. These are often characterized by their degree, which is determined by the highest exponent in the polynomial. The general form is:
\[a_nx^n + a_{n-1}x^{n-1} + \ldots + a_1x + a_0 = 0\]where \(a_n\) are coefficients and \(n\) is the degree.
A cubic polynomial, for example, has a degree of 3, indicating up to three roots. These roots can be found using methods like factoring and formulas.
- Polynomial equations can exhibit rational roots, which are whole numbers or fractions, or irrational roots, often involving square roots or complex numbers.- Solving polynomial equations often involves simplifying them into easily managed factors or using mathematical tools like the quadratic formula.
Mastering polynomial equations equips one with the facility to navigate extensive mathematical challenges effectively.

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