Chapter 2: Problem 4
The graph of a quadratic function is symmetric about its__________
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Chapter 2: Problem 4
The graph of a quadratic function is symmetric about its__________
These are the key concepts you need to understand to accurately answer the question.
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Intensity of Sound In Exercises \(47-50\) , use the following information for determining sound intensity. The level of sound \(\beta,\) in decibels, with an intensity of \(I,\) is given by \(\beta=10 \log \left(I I_{0}\right),\) where \(I_{0}\) is an intensity of \(10^{-12}\) watt per square meter, corresponding roughly to the faintest sound that can be heard by the human ear. In Exercises 47 and \(48,\) find the level of sound \(\beta .\) (a) \(I=10^{-10}\) watt per \(\mathrm{m}^{2}\) (quiet room) (b) \(I=10^{-5}\) watt per \(\mathrm{m}^{2}\) (busy street corner) (c) \(I=10^{-8}\) watt per \(\mathrm{m}^{2}\) (quiet radio) (d) \(I=10^{0}\) watt per \(\mathrm{m}^{2}\) (threshold of pain)
Intensity of Sound In Exercises \(47-50\) , use the following information for determining sound intensity. The level of sound \(\beta,\) in decibels, with an intensity of \(I,\) is given by \(\beta=10 \log \left(I I_{0}\right),\) where \(I_{0}\) is an intensity of \(10^{-12}\) watt per square meter, corresponding roughly to the faintest sound that can be heard by the human ear. In Exercises 47 and \(48,\) find the level of sound \(\beta .\) Due to the installation of noise suppression materials, the noise level in an auditorium decreased from 93 to 80 decibels. Find the percent decrease in the intensity level of the noise as a result of the installation of these materials.
Forensics At \(8 : 30\) A.M., a coroner went to the home of a person who had died during the night. In order to estimate the time of death, the coroner took the person's temperature twice. At \(9 : 00\) A.M. the temperature was \(85.7^{\circ} \mathrm{F},\) and at \(11 : 00\) A.M. thetemperature was \(82.8^{\circ} \mathrm{F}\) . From these two temperatures, the coroner was able to determine that the time elapsed since death and the body temperature were related by the formula $$t=-10 \ln \frac{T-70}{98.6-70}$$ where \(t\) is the time in hours elapsed since the person died and \(T\) is the temperature (in degrees Fahrenheit) of the person's body. (This formula comes from a general cooling principle called Newton's Law of Cooling.It uses the assumptions that the person had a normal body temperature of \(98.6^{\circ} \mathrm{F}\) at death and that the room temperature was a constant \(70^{\circ} \mathrm{F} .\) ) Use the formula to estimate the time of death of the person.
Think About It Explore transformations of the form $$ g(x)=a(x-h)^{5}+k $$ (a) Use a graphing utility to graph the functions $$ y_{1}=-\frac{1}{3}(x-2)^{5}+1 $$ and $$ y_{2}=\frac{3}{5}(x+2)^{5}-3 $$ Determine whether the graphs are increasing or decreasing. Explain. (b) Will the graph of \(g\) always be increasing or decreasing? If so, then is this behavior determined by \(a, h,\) or \(k ?\) Explain. (c) Use the graphing utility to graph the function $$ H(x)=x^{5}-3 x^{3}+2 x+1 $$ Use the graph and the result of part (b) to determine whether \(H\) can be written in the form $$ H(x)=a(x-h)^{5}+k $$ Explain.
Radioactive Decay Carbon 14 dating assumes that the carbon dioxide on Earth today has the same radioactive content as it did centuries ago. If this is true, then the amount of \(^{14} \mathrm{C}\) absorbed by a tree that grew several centuries ago should be the same as the amount of 14 C absorbed by a tree growing today. A piece of ancient charcoal contains only 15\(\%\) as much radioactive carbon as a piece of modern charcoal. How long ago was the tree burned to make the ancient charcoal, assuming that the half-life of \(^{14} \mathrm{C}\) is 5715 years?
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