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Sketching the Graph of a Rational Function In Exercises \(17-40,\) (a) state the domain of the function, (b) identify all intercepts, (c) find any vertical or horizontal asymptotes, and (d) plot additional solution points as needed to sketch the graph of the rational function. $$f(x)=\frac{x^{2}}{x^{2}+9}$$

Short Answer

Expert verified
The domain of the function is all real numbers. The only intercept is at the origin (0,0). There are no vertical asymptotes and a horizontal asymptote at y=1. The graph is a U-shape that approaches the line y=1 as x gets larger in either the positive or negative direction.

Step by step solution

01

Find the Domain

The domain of a function is the set of all possible x-values. For this function, \( f(x) = \frac{x^{2}}{x^{2} + 9} \), the denominator cannot equal zero as division by zero is undefined. But \( x^{2} + 9 = 0 \) has no real solution as the minimum value of \( x^{2} \) is 0 and thus \( x^{2} + 9 \) is always greater than zero. Therefore, the domain of this function is all real numbers.
02

Identify Intercepts

To find the x-intercept, set \( f(x) = 0 \) and solve for x. So, \( 0 = \frac{x^{2}}{x^{2} + 9} \) which implies \( x = 0 \). Thus, the x-intercept is 0. To find the y-intercept, substitute \( x = 0 \) into the function: \( f(x) = \frac{0}{0 + 9} = 0 \). Thus, the y-intercept is also 0. Therefore, the only intercept is at the origin (0,0).
03

Find Asymptotes

There are two types of asymptotes - vertical and horizontal. A vertical asymptote is a value of x where the function approaches infinity or negative infinity. In this case, there are no values of x that make the denominator equal to zero and thus, there are no vertical asymptotes. A horizontal asymptote is a value of y that the function gets arbitrarily close to as x approaches infinity or negative infinity. For the given function, as x approaches infinity or negative infinity, the function approaches \( \frac{x^{2}}{x^{2}} = 1 \). Therefore, the horizontal asymptote is y = 1.
04

Sketch the Graph

To sketch the graph, first plot the intercept at (0,0). Then, draw a dashed line at y = 1, representing the horizontal asymptote. As x approaches either positive or negative infinity, the graph of the function will approach this line. The graph looks like a U-shape getting closer and closer to the line y = 1 as x gets larger in either the positive or negative direction.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rational Function Domain
Understanding the domain of a rational function is crucial to sketching its graph. For the function given, \( f(x) = \frac{x^{2}}{x^{2} + 9} \), we look for values of \(x\) that could potentially make the denominator equal to zero, as these are not allowed (since division by zero is undefined). However, \( x^{2} + 9 \), with \( x^{2} \) being always non-negative, can never be zero. So, the domain of this particular function includes all real numbers. This means that the graph will stretch horizontally across the entire \(x\)-axis without any interruptions.

It's important to remember that for other rational functions, whenever the denominator can be zero, we exclude those \(x\)-values from the domain. Identifying the domain first helps in further graphing steps, such as locating intercepts and asymptotes.
Function Intercepts
Intercepts are where the graph of the function crosses or touches the \(x\)-axis and \(y\)-axis. For our function \( f(x) \), to find the \(x\)-intercept, we set the numerator equal to zero and solve for \(x\). As the numerator is \(x^{2}\), we find that \(x = 0\) is the solution, indicating the \(x\)-intercept is at the origin (0,0). Similarly, the \(y\)-intercept occurs when \(x = 0\); substituting this into our function, we again get 0. Thus, the \(y\)-intercept is also at the origin (0,0), giving us a single point where the function intersects both axes. In general, finding intercepts for rational functions involves setting the numerators and denominators to zero and solving for both \(x\) and \(y\), respectively.

These intercepts can be crucial in sketching the graph as they give starting points from which the function extends and provide insights into its behavior at these critical values.
Vertical and Horizontal Asymptotes
Asymptotes are lines that the graph of a function approaches but never actually reaches. Vertical asymptotes occur at values of \(x\) that make the denominator zero, but since our denominator \(x^{2} + 9\) is never zero, this function has no vertical asymptotes. However, many rational functions can have one or more vertical asymptotes, and identifying these is a major part of the graph sketching process.

Horizontal asymptotes are determined by the end behavior of the function as \(x\) approaches infinity or negative infinity. For our function, as \(x\) grows larger in either direction, the ratio of \(x^{2}\) to \(x^{2} + 9\) approaches 1. Thus, we have a horizontal asymptote at \(y = 1\). This line represents a boundary that the graph gets infinitely close to but does not cross as \(x\) becomes very large or very small. Recognizing horizontal asymptotes is vital as they give a horizontal reference line that the function will approach.
Graphing Rational Functions
Graphing rational functions starts by putting together the insights from the domain, intercepts, and asymptotes. With the intercepts at hand, we plot the point (0,0) on the graph. Then, knowing there's a horizontal asymptote at \(y=1\), we draw a dashed line to represent it. As \(x\) moves towards infinity or negative infinity, the graph will approach but never touch this dashed line.

For the function \(f(x) = \frac{x^{2}}{x^{2} + 9}\), the graph assumes the shape of a parabola that has been ‘flattened’ by the asymptote at \(y=1\). It widens as \(x\) moves away from the origin, increasingly resembling the asymptote. In the general case, the shape and direction of the graph heavily depend on the degrees of the polynomials in the numerator and denominator, as well as the presence of vertical asymptotes. Sketching additional points if necessary can provide a more accurate representation of the function's curve and help illustrate its overall behavior.

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